Hi
I just want to launch  a python script from my web page done with
django.
2 ways to do this-> by a form included in  "mytemplate.html" for
example, like this:

<form name="ingestionForm" action="/spica/cgi-bin/ingestion.py"
method="post">
<input type="text" name="target" value="" size="50"
maxlength="50">
<input type="submit" value="Ingestion" />
</form>

With this solution a press button is created and the browser wants to
open the url: ".../spica/cgi-bin/ingestion.py" by pressing it.
Can this url be matched in the urls.py? (because urls.py is the only
way to navigate through django site)
if this is the case, how?
perhaps like this: (r'^spica/cgi-bin/$','??????'), OR (r'^spica/cgi-
bin/ingestion.py$','??????') and how can i fill the second field with
"??????"

I've tried this solution but it doesn't work, so may be it can't be
done with the url formalism of django.

howhever i don't know how to do this....

the second way is to include some stuff in the httpd.conf of apache to
permit python script to be executed by the server through modpython
but i don't know how to do this

hope you understand now


Greg



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