bro try to send a intended code
On Tue, Jul 28, 2020 at 5:16 PM Harvindar Singh Garcha <
garchaama...@gmail.com> wrote:
> I am new to Django, and trying to paginate a dictionary objects,
> However I am unable to so and not getting what's wrong with my code,
> Its still printing whole data on a si
I think there might be a way around, below is the code modified for views.py
@login_required
def home_view(request):
"""Display all the post of friends and own posts on the dashboard"""
posts = Post.objects.order_by('-date_posted')
media: MEDIA_URL
# 'post':Post.objects.filter(Q(author=request.use
Dear Sir,
it shows all the text on all the pages.
if there are total 5 posts, then it shows all the 5 posts on all the pages.
Thanks,
Akshat Zala
On Saturday, 30 May 2020 20:54:35 UTC+5:30, maninder singh Kumar wrote:
>
> Views.py looks fine !
>
> regards
> willy
>
>
> On Sat, May 30, 2020 at
Hi,
if I change the template to:
{% if not is_paginated %}
{% if page_obj.has_previous %}
First
arrow_left
{% endif %}
{% for num in page_obj.paginator.page_range %}
{% if page_obj.number == num %}
{{ num }}
{% elif num > page_obj.number|add:'-4' and num < page_obj.number|add:'4' %}
{{ num }}
{%
Hi akshat,
What is the difficulty?
Where have you defined the variable is_paginated? Is it present in the
context?
On Sat, May 30, 2020, 8:53 PM maninder singh Kumar <
maninder.s.ku...@gmail.com> wrote:
> Views.py looks fine !
>
> regards
> willy
>
>
> On Sat, May 30, 2020 at 7:22 PM Akshat Zal
Views.py looks fine !
regards
willy
On Sat, May 30, 2020 at 7:22 PM Akshat Zala wrote:
> Hello,
>
> I am finding it difficult to paginate through all the posts
>
> My views.py :
>
> @login_required
> def home_view(request):
> """Display all the post of friends and own posts on the dashboard"""
On Saturday, 30 May 2020 19:20:47 UTC+5:30, Akshat Zala wrote:
>
> Hello,
>
> I am finding it difficult to paginate through all the posts
>
> My views.py :
>
> @login_required
> def home_view(request):
> """Display all the post of friends and own posts on the dashboard"""
> posts = Post.objects.
i find solutio
using https://docs.djangoproject.com/en/1.9/topics/pagination/ thnX
Τη Τρίτη, 26 Ιανουαρίου 2016 - 3:10:06 μ.μ. UTC+2, ο χρήστης pa xapy έγραψε:
>
> you want to paginate both querysets at the same page?
> i believe it's a pretty strange idea and if so, you should think how to
> r
i foolow the steps but i have again error my new view :
def index(request):
try:
page = request.GET.get('page', 1),
except PageNotAnInteger:
page = 1,
objects = ['john', 'edward', 'josh', 'frank']
p = Paginator(objects,request=request)
people = p.page(page)
that method is Confusing,i try to understand,i create new view or i work
with current?i not understand it the using 'people' and object on they view
Τη Δευτέρα, 25 Ιανουαρίου 2016 - 4:16:31 μ.μ. UTC+2, ο χρήστης Xristos
Xristoou έγραψε:
>
> i want to using Paginator in my main page for my post l
are you using python 3?
that's actually what i talking about - it's too old
try another one, like
this https://github.com/jamespacileo/django-pure-pagination - follow
the instructions and i hope you'll be fine
On Tuesday, January 26, 2016 at 5:09:29 PM UTC+3, Xristos Xristoou wrote:
>
> i follow
i follow the simpe steps but i take error invalid syntax
(pagination_tags.py, line 225)
Τη Δευτέρα, 25 Ιανουαρίου 2016 - 4:16:31 μ.μ. UTC+2, ο χρήστης Xristos
Xristoou έγραψε:
>
> i want to using Paginator in my main page for my post list. i see docs and
> examples for that but i thing my probl
thnx you i try to use that now
Τη Δευτέρα, 25 Ιανουαρίου 2016 - 4:16:31 μ.μ. UTC+2, ο χρήστης Xristos
Xristoou έγραψε:
>
> i want to using Paginator in my main page for my post list. i see docs and
> examples for that but i thing my problem is a specific, because on my view
> i have two Querys
are you familiar with the pip utility?
if not, i highly recommend to read about
it https://pip.pypa.io/en/stable/quickstart/
if yes, you should know that you can install any application with pip
install package_name
and how set it up with django - it's better if you read in instructions for
pack
one more question how to install this ?autopagination ?i dont see anything
Τη Δευτέρα, 25 Ιανουαρίου 2016 - 4:16:31 μ.μ. UTC+2, ο χρήστης Xristos
Xristoou έγραψε:
>
> i want to using Paginator in my main page for my post list. i see docs and
> examples for that but i thing my problem is a specif
you can read the usage doc i sent linked, but yes - you don't need to do
anything with you queryset in view only pass it to template
On Tuesday, January 26, 2016 at 4:39:17 PM UTC+3, Xristos Xristoou wrote:
>
> if i use {autopagination} i dont need quyre on my view ?
>
> Τη Δευτέρα, 25 Ιανουαρίου
if i use {autopagination} i dont need quyre on my view ?
Τη Δευτέρα, 25 Ιανουαρίου 2016 - 4:16:31 μ.μ. UTC+2, ο χρήστης Xristos
Xristoou έγραψε:
>
> i want to using Paginator in my main page for my post list. i see docs and
> examples for that but i thing my problem is a specific, because on my
if you'll decide to use some app for pagination, you can do it in template,
like
so https://github.com/ericflo/django-pagination/blob/master/docs/usage.txt
({% autopaginate posts 10 %})
or you can choose one of
these https://www.djangopackages.com/grids/g/pagination/
there is no actual need to
can you show me one examples with my view ?
Τη Δευτέρα, 25 Ιανουαρίου 2016 - 4:16:31 μ.μ. UTC+2, ο χρήστης Xristos
Xristoou έγραψε:
>
> i want to using Paginator in my main page for my post list. i see docs and
> examples for that but i thing my problem is a specific, because on my view
> i hav
you want to paginate both querysets at the same page?
i believe it's a pretty strange idea and if so, you should think how to
refactor it
if you want only paginate posts, i'll recommend you to use
django-pagination app of some sort, it's can be used in template
On Monday, January 25, 2016 at 5:
Thanks for the help guys, I managed to solve, so I did:
* queryset = Player.objects.filter(name=namepost)*
*paginator = Paginator(queryset, 2)*
*
*
*try: *
* page = int(request.POST.get('page','1')) *
*except ValueError: *
* page = 1 *
*try:
thus still giving the same error
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On 10/03/2013 04:13 PM, Roberto López López wrote:
> *return HttpResponse(json.dumps([players]) ,
> content_type='application/json')*
better without the square brackets
*return HttpResponse(json.dumps(players) ,
content_type='application/json')*
--
Roberto López López
System Developer
Paral
doing so:
*queryset = Player.objects.filter(name=namepost)*
*paginator = Paginator(queryset, 2)*
*
*
*page = request.GET.get('page')*
*try:*
*players = paginator.page(page)*
*except PageNotAnInteger:*
*players = paginator.page(1)*
*exc
Try this (I have not tried the code myself, but I think that it should
work):
*queryset = Player.objects.filter(name=namepost)*
*paginator = Paginator(queryset, 2)
page = request.GET.get('page')
try:
players = paginator.page(page)
except PageNotA
Better to say:
*queryset = Player.objects.filter(name=namepost)*
*paginator = Paginator(queryset, 2)
page = request.GET.get('page')
try:
players = paginator.page(page)
except PageNotAnInteger:
players = paginator.page(1)
excep
Already got it, I did so:
*queryset = Player.objects.filter(name=namepost)*
*paginator = Paginator(queryset, 2)*
*return HttpResponse(json.dumps([item.get_json() for item in
paginator.object_list]) , content_type='application/json')*
But I return all the records ... I should not retur
Already got it, I did so:
*queryset = Player.objects.filter(name=namepost)*
*paginator = Paginator(queryset, 1)*
*return HttpResponse(json.dumps([item.get_json() for item in
paginator.object_list]) , content_type='application/json')*
But I return all the records ... I should not retur
I'm doing this:
*queryset = Player.objects.filter(name=namepost)*
*paginator = Paginator(queryset, 20)*
*return json.dumps([item.get_json() for item in paginator.object_list])*
And my Document is thus:
http://plnkr.co/edit/FHH2hZh26OiLMKTk2ToO
But it gives me the following error:
'st
Hi Hélio,
It looks like you're applying pagination to the rendered JSON string itself.
You want to be paginating the queryset itself.
queryset = Player.objects.filter(name=namepost)
paginator = Paginator(queryset, 20)
return json.dumps([item.to_dict() for item in paginator.object_list
On Sun, May 6, 2012 at 10:56 PM, coded kid wrote:
> I'm trying to paginate a page in order to display five statuses per
> page. After inputting these codes, it fails to paginate. Below are the
> codes for pagination and updating of status in my django app.
>
>
> Views:
>
> def qask(request):
>
Nevermind, it is a SQL Server problem. (I hate SQL Server. There, I
said it.)
I had to first filter manually by the m2m objects, then apply the
pagination to the results.
Thanks!
On Feb 18, 2:53 pm, David De La Harpe Golden
wrote:
> On 18/02/11 17:38,diogobaederwrote:
>
> > Hi,
> > Any ideas of
On 18/02/11 17:38, diogobaeder wrote:
> Hi,
> Any ideas of what might be happening?
>
Have you set a Meta.ordering on your Model (or applied an .order_by()
to the QuerySet?)
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I don't have time to watch your code, but...
Take a look here http://www.tummy.com/Community/Articles/django-pagination/
I set up this cool pagination in 15 minutes without errors!
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To post to thi
Thanks again. Did it with object_list. Thanks for help :)
On Oct 19, 2:16 pm, Михаил Лукин wrote:
> Finally, I see only 3 ways:
> 1. copy/paste archive index code and change it's behaviour so it can eat
> num_latest=None
> 2. patch date_based.py in same way as (1)
> 3. use list_detail.object_lis
Finally, I see only 3 ways:
1. copy/paste archive index code and change it's behaviour so it can eat
num_latest=None
2. patch date_based.py in same way as (1)
3. use list_detail.object_list
Since 1-2 are dirty, I would recommend 3rd way. I'll let you know if I could
suggest something else :)
2009/
Surely I could use the list_detail.object_list, but the use of date
based generics though ))
On Oct 18, 11:45 pm, Михаил Лукин wrote:
> Sorry, didn't look at condition well...:(
>
> So, you see the source and you see that there's no way to get all the
> records with this view.
> Why don't you u
Sorry, didn't look at condition well...:(
So, you see the source and you see that there's no way to get all the
records with this view.
Why don't you use list_detail.object_list view? If you need just to order
list by date, you can use ordering on the model level:
http://docs.djangoproject.com/en/
Would it? If "latest=None" doesn't it mean that there are no entries?
By the way, if I pass None to the condition, it returns False, so
latest is None.
Or isn't it?
Also the template cannot render it, cause "object of type 'NoneType'
has no len()".
Anyways, thanks for reply :)
On Oct 18, 11
Look at date_based.py:
if date_list and num_latest:
latest = queryset.order_by('-'+date_field)[:num_latest]
else:
latest = None
So, if you use num_latest=None, you will always get the whole list.
On Aug 30, 2:47 pm, tezro wrote:
> Anyone?
>
> On Aug 14, 8:29 am, tezro
On Sat, Sep 5, 2009 at 4:52 PM, Michael Ralan wrote:
>
> Hi,
>
> Apologies if this question has been asked before but I was not able to
> find a satisfactory answer.
>
> In the django admin app there is a capability to have a pagination
> object that lists the number of pages that can be paged.
>
Anyone?
On Aug 14, 8:29 am, tezro wrote:
> The question is that "django.views.generic.date_based.archive_index()"
> takes an optional argument "num_latest" which is 15 by default.
> Setting it manually to num_latest=10 is way off to correct to
> me. It works. I suppose that it even doesn
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