Sorry, didn't look at condition well...:(
So, you see the source and you see that there's no way to get all the
records with this view.
Why don't you use list_detail.object_list view? If you need just to order
list by date, you can use ordering on the model level:
http://docs.djangoproject.com/en/dev/ref/models/options/#ordering
2009/10/18 tezro <tezro...@gmail.com>
>
> Would it? If "latest=None" doesn't it mean that there are no entries?
>
> By the way, if I pass None to the condition, it returns False, so
> latest is None.
>
> Or isn't it?
>
> Also the template cannot render it, cause "object of type 'NoneType'
> has no len()".
>
> Anyways, thanks for reply :)
>
>
>
> On Oct 18, 11:04 pm, Mihail Lukin <mihail.lu...@googlemail.com> wrote:
> > Look at date_based.py:
> >
> > if date_list and num_latest:
> > latest = queryset.order_by('-'+date_field)[:num_latest]
> > else:
> > latest = None
> >
> > So, if you use num_latest=None, you will always get the whole list.
> >
> > On Aug 30, 2:47 pm, tezro <tezro...@gmail.com> wrote:
> >
> > > Anyone?
> >
> > > On Aug 14, 8:29 am, tezro <tezro...@gmail.com> wrote:
> >
> > > > The question is that
> "django.views.generic.date_based.archive_index()"
> > > > takes an optional argument "num_latest" which is 15 by default.
> > > > Setting it manually to num_latest=1000000000 is way off to correct to
> > > > me. It works. I suppose that it even doesn't retrieve all the tons of
> > > > data from the DB, but what if I have 1000000000 + 1 record :)
> >
> > > > What's the right way to use "django-pagination" and the
> "archive_index
> > > > ()" or am I missing something?
> >
> > > > Example code.
> > > > _______________
> >
> > > > def index(request):
> > > > qs = News.objects.filter(is_published=1)
> > > > return archive_index(request, qs, 'date',
> num_latest=100000000)
> > > > _______________
> >
> > > > Thanks.
> >
> >
> >
>
--
regards,
Mihail
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