https://youtu.be/oCSMWSp1_UI
Its a series or playlist where they provide how to create rss feed in
django website
Raj Patel
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https://youtu.be/2fB4PN-WRcQ
If you are facing issue in creating RSS feed in django ..
Here is tutorial they are coming up with.
And they help Developers like us to solve many problems. Follow there
telegram channel where usefull and updated problems solution updates come
always.
@*errormania
I am not a Django user neither I have an idea what it is.
I found a problem with the RSS-Feeds of the Debian-Package-Tracker which
runs with a "Django object".
They told me to open a bug report on Django for this but I am not the
user. And I don't know technical details.
It would be nice if s
Thank you! Really appreciate it.
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Done.
On Monday, November 14, 2016 at 7:03:43 AM UTC-5, Dávid Főző wrote:
>
> Hello fellow Djangonauts,
>
> I submitted rss feed of my website as a Django Blog. Now, I would like to
> modify it to make sure only selected articles will be submitted.
>
> If you have authority
Hello fellow Djangonauts,
I submitted rss feed of my website as a Django Blog. Now, I would like to
modify it to make sure only selected articles will be submitted.
If you have authority in this, I would like to change this:
https://www.davidfozo.com/blog/feeds/rss/
to this:
https
anyone??
On Saturday, July 7, 2012 3:52:52 AM UTC+1, psychok7 wrote:
>
> hi, i am trying to implement the syndicate feed framework simple rss with
> my program, but i get a ImproperlyConfigured at /latest/feed/
>
> Give your Debt class a get_absolute_url() method, or define an item_link()
> meth
on my feed.py i have
class LatestEntriesFeed(Feed):
title = "Chicagocrime.org site news"
link = "/blog/"
description = "Recent Posts"
def items(self):
return Debt.objects.all().order_by('-creation_date')[:10]
can anyone help me?
On Saturday, July 7, 2012 3:52:52 AM UTC
hi, i am trying to implement the syndicate feed framework simple rss with
my program, but i get a ImproperlyConfigured at /latest/feed/
Give your Debt class a get_absolute_url() method, or define an item_link()
method in your Feed class.
I know i am supposed to create a get_absolute_url in my D
I solved the problem. I used application's urls.py not project's
urls.py and update urls like (r'^rss/$', LatestEntriesFeed()).
Thanks for help.
On Jun 8, 3:45 pm, Diego pascual lopez wrote:
> On Fri, Jun 8, 2012 at 2:23 PM, armagan wrote:
> > No, I just realized. But I tried import 'from proj
On Fri, Jun 8, 2012 at 2:23 PM, armagan wrote:
> No, I just realized. But I tried import 'from projem.blogum.views
> import LatestEntriesFeed' and I've had a 404 error. I guess, i have a
> url error.
>
> #My RSS class
> class LatestEntriesFeed(Feed):
>title = "site news"
>link = "/projele
No, I just realized. But I tried import 'from projem.blogum.views
import LatestEntriesFeed' and I've had a 404 error. I guess, i have a
url error.
#My RSS class
class LatestEntriesFeed(Feed):
title = "site news"
link = "/projeler/haberler/"
description = "Updates on changes and additio
On Jun 8, 1:53 pm, armagan wrote:
> Hi,
>
> I'm trying to implemente an rss to my project. I have done a simple
> example in django doc.
Which one ? url, please.
> But I have an error in urls.py.
>
> from 'blogum.feeds import LatestEntriesFeed' ==> I've imported this, I
> have an error 'No modu
Hi,
Do you have in your blogum directory a feeds.py?
On Fri, Jun 8, 2012 at 1:53 PM, armagan wrote:
> Hi,
>
> I'm trying to implemente an rss to my project. I have done a simple
> example in django doc. But I have an error in urls.py.
>
> from 'blogum.feeds import LatestEntriesFeed' ==> I've i
Hi,
I'm trying to implemente an rss to my project. I have done a simple
example in django doc. But I have an error in urls.py.
from 'blogum.feeds import LatestEntriesFeed' ==> I've imported this, I
have an error 'No module named feeds'.
Thanks in advance for any help provided.
Armağan
--
You
On Mon, Sep 19, 2011 at 4:08 AM, Subhranath Chunder
wrote:
> I just added my tech blog to
> the https://www.djangoproject.com/community/ page with feeds
> from http://scratch-blog.appspot.com/feed/rss/
> Can someone with admin privileges, please edit and change the title to
> 'Subhranath Chunder'
I just added my tech blog to the https://www.djangoproject.com/community/ page
with feeds from http://scratch-blog.appspot.com/feed/rss/
Can someone with admin privileges, please edit and change the title to
'Subhranath Chunder' from the current 'ScratchBlog - The Scratch Blog'.
I had simply put t
http://www.feedparser.org/
On Sat, Jun 25, 2011 at 12:21 AM, raj wrote:
> I was trying to follow the following guide:
> https://docs.djangoproject.com/en/dev/ref/contrib/syndication/?from=olddocs
> and I had some questions.
>
> I'm not quite sure, but it seems like this guide is showing how to
>
I was trying to follow the following guide:
https://docs.djangoproject.com/en/dev/ref/contrib/syndication/?from=olddocs
and I had some questions.
I'm not quite sure, but it seems like this guide is showing how to
create your own feed. How would I go about retrieving the feed instead
of creating it
Like, say, the one at:
http://www.djangoproject.com/community/
You know, something like that?
Never mind!
On Dec 22, 2010, at 3:04 PM, Christophe Pettus wrote:
> Is there a feed consolidator for Django-related RSS feeds? One exists for
> the PostgreSQL project, and it's pretty nice t
Is there a feed consolidator for Django-related RSS feeds? One exists for the
PostgreSQL project, and it's pretty nice to keep track of what PG-related stuff
is being written by various bloggers. If not, is there interest in such a
thing?
--
-- Christophe Pettus
x...@thebuild.com
--
You
The problem with the first is that users would get a bunch of single
items whenever they were added to the DB. I need to give them a
digest of what happened that week. I had thought of the range idea,
but then you're hitting the DB every hour all week for a single update
which doesn't sound corre
On 2010-06-21, at 5:48 PM, TheIvIaxx wrote:
> I was wondering how to create a weekly feed for django. Lets say i
> have a table of objects that gets added to all week long. I'd like to
> allow people to subscribe to a feed that would give a single update
> with all items that were added that wee
Hello all, i tried searching for a solution to this but didn't find
it. If it's answered somewhere, please point me in the right
direction :)
I was wondering how to create a weekly feed for django. Lets say i
have a table of objects that gets added to all week long. I'd like to
allow people to
Hello,
My project is a simple wikipedia appication. I have 2 classes in
models namely Content and Tag. I am trying to generate a RSS feed for
this application. Whenever the database is empty I am able to view a
blank page when I access the RSS link, however as soon as I enter
content into the
As you probably have found out by now, since you're using 1.1, just
creat the templates
feed/_description.html
as mentioned in the docs for version 1.1:
http://docs.djangoproject.com/en/1.1/ref/contrib/syndication/
On Wed, Apr 14, 2010 at 5:44 PM, Ronnie Betzen wrote:
>> Have you tried the obv
> Have you tried the obvious - do what the Exception tells you and add a
> "get_absolute_url" method to the model of the objects published on the
> feed, or an item_link in your Feed class?
Well, duh.
This teaches me not to be reading documentation at 2 am while I'm sleepy.
I somehow looked straig
> Exception Type: ImproperlyConfigured at /feeds/latest/
> Exception Value: Give your Entry class a get_absolute_url() method, or
> define an item_link() method in your Feed class.
Have you tried the obvious - do what the Exception tells you and add a
"get_absolute_url" method to the model of the
Been working on this one for three days now. I'm stumped.
I've created my rss feed from the example listed in The Definitive
Guide to Django: Web Development Done Right.
Unfortunately, I'm getting an ImproperlyConfigured error. I've been
looknig on the Djangoproject.com site
I can create an RSS feed using the documentation for syndication and
have tried to extend it using the MediaRSS format as described here:
http://www.djangosnippets.org/snippets/1648/.
This works up to a point: I'm testing with Firefox and it still
doesn't display the media: exten
> The right person to email for that is Jacob Kaplan-Moss, whose email is at
> the bottom of that page.
I know, but as I wrote above I had no success sending emails to his
email.
Kai
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On Tue, May 5, 2009 at 8:38 AM, Kai Diefenbach wrote:
>
> Hi guys,
>
> (sorry, if this is the wrong place, I've sent already two emails to
> the provided address in the last couple of weeks without feedback)
>
> is somebody out there, who is able to ad
Hi guys,
(sorry, if this is the wrong place, I've sent already two emails to
the provided address in the last couple of weeks without feedback)
is somebody out there, who is able to adding an RSS-Feed to
http://www.djangoproject.com/community/.
The URL of the feed is:
http://www.getlf
On Mar 2, 1:10 pm, Malcolm Tredinnick
wrote:
> On Mon, 2009-03-02 at 00:02 -0800, Rama Vadakattu wrote:
> > Thanks Malcolm.Understood very clearly.
>
> > Following the same approach i have used following code in my templates
> > {% url djorum_feed_url category.getCategoryString %}
>
> > categ
On Mon, 2009-03-02 at 00:02 -0800, Rama Vadakattu wrote:
> Thanks Malcolm.Understood very clearly.
>
> Following the same approach i have used following code in my templates
> {% url djorum_feed_url category.getCategoryString %}
>
> category.getCategoryString is the function which returns cate
Thanks Malcolm.Understood very clearly.
Following the same approach i have used following code in my templates
{% url djorum_feed_url category.getCategoryString %}
category.getCategoryString is the function which returns category
string "category/catgory.id"
Regards
rama
BUt how should i us
On Fri, 2009-02-27 at 01:20 -0800, Rama Vadakattu wrote:
> i am using django feed syndication framework.
>
> 1) .in urls.py
>
> feeds = {
>'category': LatestTopicsByCategory,
> }
>
> urlpatterns += patterns('',
> url(r'^feeds/(?P.*)/$',
> 'django.contrib.syndication.v
i am using django feed syndication framework.
1) .in urls.py
feeds = {
'category': LatestTopicsByCategory,
}
urlpatterns += patterns('',
url(r'^feeds/(?P.*)/$',
'django.contrib.syndication.views.feed' , {'feed_dict':
feeds},name='djorum_feed_url') ,
Wiadomość napisana w dniu 2008-11-03, o godz. 11:59, przez please smile:
> Can anybody please send me a small RSS feed application using django.
> Thanks.
Google code has plenty of them.
--
We read Knuth so you don't have to. - Tim Peters
Jarek Zgoda, R&D, Redefine
[
Hi All ,
Can anybody please send me a small RSS feed application using django.
Thanks.
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Hey Guys,
Got a very strange thing going on with the RSS feed framework in
Django. Here is the code for one feed:
*
class LatestNotes(Feed):
title = "Title"
link = "Link"
description = "Description"
def items
Just found this via google:
http://lexhair.wordpress.com/2007/08/29/rss-feeds-and-internet-explorer-6/
Apparently IE 6 and RSS are not friends...
On Jul 20, 3:23 pm, "[EMAIL PROTECTED]" <[EMAIL PROTECTED]> wrote:
> I'm trying to generate RSS feed for my site us
I'm trying to generate RSS feed for my site using Django's syndication
framework.
I'm having 2 issues:
1) While the generated feed gets displayed correctly in Firefox,
Internet explorer v6x presents a 'save file as' prompt - like it
doesnt recognize the incoming data a
I use the Django syndication to generate RSS feeds for my site.
The feed is visible correctly in Firefox but Internet explorer v6x
cant really interpret this feed and tries to save it as a file.
I have tried using both - the RssFeed as well as the Atom1Feed
I noticed that the rss generated from
#x27;entries']: # entries are all the items under a
>>> particular feed
>>> it, created = FeedItem.objects.get_or_create(title=item.title,
>>> link=item.link, desc=item.description, date=item.date_parsed,
>>> id=item.id, feed=feed)
>>>
>&g
)
>>
>> Repeat the above for every url in your list of feed urls. Note: this
>> code goes in your standalone script running on a cron job, NOT in
>> your
>> views or whatever other normal part of your django code base. That
>> will put RSS feed items into your data
.title,
> link=item.link, desc=item.description, date=item.date_parsed,
> id=item.id, feed=feed)
>
> Repeat the above for every url in your list of feed urls. Note: this
> code goes in your standalone script running on a cron job, NOT in your
> views or whatever other normal part of
this
code goes in your standalone script running on a cron job, NOT in your
views or whatever other normal part of your django code base. That
will put RSS feed items into your database, your views.py pulls them
out again as per normal django methods:
feed = Feed.objects.get(
please much suggestions thank you
On May 28, 4:37 pm, sebastian stephenson <[EMAIL PROTECTED]> wrote:
> great finally some help thank you so much!
> On 28 May 2008, at 15:20, Rajesh Dhawan wrote:
>
>
>
>
>
> > On May 28, 6:30 am, sebey <[EMAIL PROTECTED]> wrote:
> >> from django.http import HttpR
great finally some help thank you so much!
On 28 May 2008, at 15:20, Rajesh Dhawan wrote:
>
>
>
> On May 28, 6:30 am, sebey <[EMAIL PROTECTED]> wrote:
>> from django.http import HttpResponse
>> import feedparser
>> from ubermicro.shows.models import show
>>
>> def show_page(request):
>> """th
On May 28, 6:30 am, sebey <[EMAIL PROTECTED]> wrote:
> from django.http import HttpResponse
> import feedparser
> from ubermicro.shows.models import show
>
> def show_page(request):
> """this is where we take what we need form the rss feeds in the
> data base"""
> query = show.objects.fi
/";)
podcast = feedparser.parse(query)
#show_about = podcast.feed.description
show_latest_title = podcast.entries[0].title
#show_latest = podcast.entries[0].description
return HttpResponse(show_latest_title)
ok so what this code is doing is its getting the rss feed from th
from django.http import HttpResponse
import feedparser
from ubermicro.shows.models import show
def show_page(request):
"""this is where we take what we need form the rss feeds in the
data base"""
query = show.objects.filter(show_feed__contains="http://";)
podcast = feedparser.parse(qu
stanleypark skrev:
> We just finiched a really cool RSS feed news reader. I need people
> comments on it.
> here is the link of the web site.
>
I see no link at this point in your post. Anyway, who are "we"?
> If you wish to know more about RSS feeds here is a group l
We just finiched a really cool RSS feed news reader. I need people
comments on it.
here is the link of the web site.
If you wish to know more about RSS feeds here is a group link that I
just started.
http://groups.google.com/group/adsense-and-rss-feeds/web/netsplorer-com?hl=en
all the best to
On 2/28/07, VirusRaja <[EMAIL PROTECTED]> wrote:
> Below is my class to generate rss feed for a list
> Which is an erroro "class a get_absolute_url() method, or define an
> item_link() method in your Feed class."
>
> Can any one help me with this.
The error message
Hi all
Below is my class to generate rss feed for a list
Which is an erroro "class a get_absolute_url() method, or define an
item_link() method in your Feed class."
Can any one help me with this.
if you send RSS generating code is much appreciated.
Thanx
Pra
On 9/2/06, Don Arbow <[EMAIL PROTECTED]> wrote:
> Is there any reason why XBox 360 and Java libraries articles are
> posted on the community RSS feeds page? Not to pick on a specific
> blog (the author does occasionally write about Django and the blog is
> written in Django). Is there a way to fil
Is there any reason why XBox 360 and Java libraries articles are
posted on the community RSS feeds page? Not to pick on a specific
blog (the author does occasionally write about Django and the blog is
written in Django). Is there a way to filter out non-Django content
from the feeds?
Don
f your Django project, just add a method to
the post_save signal that's sent whenever that particular model is
updated/saved. I don't think it's documented anywhere, but I did
throw up some rudimentary documentation here:
http://code.djangoproject.com/wiki/Signals
As for outp
On 8/1/06, a <[EMAIL PROTECTED]> wrote:
> i hav a table in postgres and it has title and body columns, i want to
> create a rss file on the fly when this table is updated wat is the best
> way to get it done
> thanks a lot
Have you read the documentation for Django's syndication system?
http://w
preparing rss feeds
i hav a table in postgres and it has title and body columns, i want to
create a rss file on the fly when this table is updated wat is the best
way to get it done
thanks a lot
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Wiktor Grêbla napisa³(a):
I've an impression that this message was not delivered to the list,
although google finds it...
> I was trying to add an rss feed with blog comments, and I'm mostly done,
> here are some snippets i pasted on irc this morning:
>
> http://paste.e-s
Hi.
I was trying to add an rss feed with blog comments, and I'm mostly done,
here are some snippets i pasted on irc this morning:
http://paste.e-scribe.com/934/
The problem is that i'd like to have unique_id for each item (comments
don't have unique links, as they're &q
ED]> wrote in message
news:[EMAIL PROTECTED]
>
> Hello,
>
> when generating a rss feed, i get the following:
>
> ---
> There's been an error:
>
> Traceback (most recent call last):
>
> File "/usr/lib/python2.3/site-packages/django/core/handlers/ba
Hello,
when generating a rss feed, i get the following:
---
There's been an error:
Traceback (most recent call last):
File "/usr/lib/python2.3/site-packages/django/core/handlers/base.py",
line 64, in get_response
response = callback(request, **param_dict)
File &quo
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