On 11/19/2010 8:51 PM, Micah Carrick wrote:
> I'm having trouble coming up with a pretty solution to a seemingly
> simple task. I'm relatively new to Django.
>
> I want to allow the end user to control various lists of links on the
> site used for navigation. The admin should allow the creation of
I'm wondering, how are fail_to_get_lock and release_lock implemented?
It would be some kind of multiprocess lock, which seems overly
complicated..
using save() in this case is cumbersome, because save() is not
threadsafe... you'll have to try to maintain your own lock.
If you only want to impleme
On Fri, 2010-11-19 at 12:44 -0800, hank23 wrote:
> 'DateFimeField'
typo
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regards
Kenneth Gonsalves
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just off the cuff - what's a "DateFimeField"?should be
DateTimeField?
On Nov 19, 12:44 pm, hank23 wrote:
> I'm trying to work through part 1 of the tutorial at:
>
> http://docs.djangoproject.com/en/dev/intro/tutorial01/
>
> and I seem to be having problems getting my model code to work. I
> c
I'm trying to integrate two existing apps, both of which provide a
django Model - call them ModelA and ModelB - my app's model needs to
inherit from both of these.
I know django models support multiple inheritance, but both ModelA and
ModelB define a Meta class, override the save() method, etc., so
I'm trying to work through part 1 of the tutorial at:
http://docs.djangoproject.com/en/dev/intro/tutorial01/
and I seem to be having problems getting my model code to work. I
currently have Django-1.2.3, and Python 2.7 installed. I was able to
run the startproject and create the mysite directory
Just a thought, what about:
{% for k,v in mydict|order:'key' %}
or
{% for k,v in mydict orderby key %}
-Adam
On Nov 19, 10:55 am, Paweł Roman wrote:
> When rendering dictionary, there is absolutely no way to display
> values sorted by keys. The only workaround is to copy all the dict
> items
I have to override the default display of a foreignkey field in a form
and instead display it as a CharField. Currently it displays the
selection's ID but I need to display the label instead
To be clear, the select option would be the default display for the
ForeignKey. At the moment after I've
I'm having trouble coming up with a pretty solution to a seemingly simple
task. I'm relatively new to Django.
I want to allow the end user to control various lists of links on the site
used for navigation. The admin should allow the creation of "link groups"
which have a collection of "links". The
Hi Steve,
Ops, yes, I forgot to include the object.save() in the pseudo code
above. Yes, we're actually saving it:
1 object = MyModel.object.get(id=1)
2 print object.value# starting value is 5
3 while object.fail_to_get_lock():
4sleep(5)
5 object = MyModel.object.get(id=1) # Re-get the o
Hello Django Users,
I decided to write a series of applications that will make up a cms
among other things and the first application is a database template
application. It's for a cms where users won't have OS access. There
is a demo site that has nothing but the application and revision. It
us
If you really want to have a separate table for Tag, You can do this:
class CurrentTag(models.Model):
tag = models.OneToOneField(Tag, primary_key=True)
def __unicode__(self):
return self.tag
On Nov 20, 12:10 am, JE wrote:
> Thanks for the replies.
> I simplified the problem a bit
On 11/19/2010 5:35 PM, Iqbal Abdullah wrote:
> Hi,
>
> This might be a gotcha on the models side, but I would like
> clarification and guidance on how to write the code better concerning
> multiple process accessing the same data via models.
>
> I have a backend script that runs the following cod
Hi,
This might be a gotcha on the models side, but I would like
clarification and guidance on how to write the code better concerning
multiple process accessing the same data via models.
I have a backend script that runs the following code in multiple
processes:
1 object = MyModel.object.get(id=
An easy alternative is to make a sort filter:
register.filter('sort',lambda x: sorted(x))
and then do
{% for k,v in mydict.items|sort %}
{{k}}:{{v}}
{% endfor %}
I had to look at the docs to realize there isn't a sort filter in
django for some reason. I long ago added the one above to built
On 11/19/2010 1:56 PM, jonno wrote:
> And I have:
>
> {% load staticfiles %}
> {% get_staticfiles_prefix as STATIC_PREFIX %}
>
> at the top of my template. Sorry to trouble all with this again!
> Thanks for any help -- Jon.
PS: You might want to consider injecting STATIC_PREFIX into your
contex
Doing a redirect to the page with ?rand=time.time() did not work
either.
On Nov 19, 12:47 pm, vcarney wrote:
> This can be replicated in ie8 100% of the time and FF about 10% of the
> time.
>
> On Nov 19, 12:42 pm, vcarney wrote:
>
>
>
>
>
>
>
> > I have a custom settings form with a photo field
On 11/19/2010 1:56 PM, jonno wrote:
> Hello,
>
> Sorry not to have replied for so long, but I thought I'd better just
> try and dig through it! In the meantime, I have upgraded to Django
> (1, 3, 0, 'alpha', 1) and follow the instructions in the development
> documentation. I am just trying to s
Hello,
Sorry not to have replied for so long, but I thought I'd better just
try and dig through it! In the meantime, I have upgraded to Django
(1, 3, 0, 'alpha', 1) and follow the instructions in the development
documentation. I am just trying to serve my static files for
development purposes, b
This can be replicated in ie8 100% of the time and FF about 10% of the
time.
On Nov 19, 12:42 pm, vcarney wrote:
> I have a custom settings form with a photo field: photo =
> forms.ImageField(max_length=200, required=False)
>
> On submission with a new photo being uploaded, I delete any existing
I have a custom settings form with a photo field: photo =
forms.ImageField(max_length=200, required=False)
On submission with a new photo being uploaded, I delete any existing
image including its parent folder and replace with the new one. When
the settings page is reloaded, the old image is still
When rendering dictionary, there is absolutely no way to display
values sorted by keys. The only workaround is to copy all the dict
items to a sortable structure e.g. list and pass the list to the
template, instead of the dictionary.
Why not introduce a new tag to solve this problem:
I say, it sh
I want to pass a variable by URL to another page in django admin. it
seems it is not working, i want to pass the variable "/?
name=hello",but the url becomes "/?e=1" ( i think this is a redirect
made by Django )... does any one knows how to solve this problem
Thanks
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When you run dumpdata you can specify apps or models within an app to
export. That will allow you to avoid bringing Django's scaffolding
into your fixtures.
Shawn
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which python returns /opt/local/Library/Frameworks/Python.framework/
Versions/2.6/bin/python
I didn't install python 2.6.6, at least to my knowledge. Django
doesn't automatically load it does it? I have not explicitly loaded
Python myself. The first time I checked was after loading django I
jus
I'm trying to recreate my database and reload the data in it, using
the following steps:
On my app I dump data to a fixtures file with
> ./manage.py dumpdata > test_fixture
then drop and recreate the database
then run
> ./manage.py syncdb
to recreate the database tables
and
> ./manage.py loadda
extends can take a variable arg, set the variable to the
base you want.
{% extends base %}
http://docs.djangoproject.com/en/1.2/ref/templates/builtins/#extends
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On Nov 19, 3:46 pm, Jonas Geiregat wrote:
> I'm trying to save a model and then insert it into a generic relation.
> Having this models.py file:
>
> from django.db import models
> from datetime import datetime
> from django.conf import settings
> from django.contrib.contenttypes.models import Cont
I'm trying to save a model and then insert it into a generic relation.
Having this models.py file:
from django.db import models
from datetime import datetime
from django.conf import settings
from django.contrib.contenttypes.models import ContentType
from django.contrib.contenttypes import generic
Aha! Thanks Shawn. I'd left a forgotten "http://localhost:8000/
moreInfo" in there. I was so hung up on Django urls.py I forgot about
simple html mistakes and leftovers.
Thanks for the pointer!
-Ross.
On Nov 19, 10:16 am, Shawn Milochik wrote:
> What does the "action" parameter of your HTML f
What does the "action" parameter of your HTML form contain? I'm
guessing it's a relative URL.
If you want it to go to the same place, you can make the action blank
("") and it will submit to the same page.
Shawn
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"Djan
I've noticed a thing which is likely a symptom of something I'm doing
wrong. A good example is a page I'm serving which holds a form. If
there are issues with the form content, the same page is reloaded,
with an updated warning message in the body of the HTML.
The page is, say, addInfo.html and
You will need to use Javascipt: handwritten or via framework e.g.
JQuery. Its been asked about before on this mailing list and numerous
people have blogged on it.
On Nov 16, 11:58 am, Federico Capoano
wrote:
> Any suggestion?
>
> On Nov 14, 6:15 pm, Federico Capoano wrote:
>
> > Hi all,
>
> > I
Hi,
In the django documentation
(http://docs.djangoproject.com/en/dev/topics/templates/) it says that {%
extends %} tag should be the first one. Is there a way to create variable base
templates? Like this:
{% if is_blah %}
{% extends 'base.html' %}
{% else %}
{% extends 'base2.html' %}
{% endi
I am not an expert on charts, but I am using highcharts.com to generate some.
What I do here is:
1) get the data from the database inside the view (look for querysets on
django-documentation)
2) render this data on a template
3) build the chart using this library inside the template
bye, glob
Hi,
I've been using Djangos manytomany functionality to add values into the auto
generated table, here are my model classes:
class Contract_Item(models.Model):
quant = models.DecimalField(max_digits=10, decimal_places=4)
item = models.OneToOneField(Item)
class Contract(models.Model):
Thx, knew I'd forgotten something
Łukasz Balcerzak wrote:
>
> Try running "python manage.py syncdb". Hope that helps
>
> On Nov 19, 2:00 pm, MikeKJ wrote:
>> I have forgotten something here, added a model to a site, restarted the
>> server but the add/change/delete permission set is not showi
Try running "python manage.py syncdb". Hope that helps
On Nov 19, 2:00 pm, MikeKJ wrote:
> I have forgotten something here, added a model to a site, restarted the
> server but the add/change/delete permission set is not showing in the
> auth-user add permission set, what is it I have forgotten pl
with rev 12661, storage.py has been changed and
return smart_str(os.path.normpath(path))
has been replaced with
return os.path.normpath(path)
now, when trying to upload a filefield (or displaying the size of a
filefield), we get this error:
Caught UnicodeEncodeError while rendering: 'ascii' codec
Bah stupid me. Use admin.site.register(Poll, PollAdmin) not just
admin.site.register(Poll). Sorry ...
On Nov 19, 10:26 am, Reikje wrote:
> Hi, playing around with the django tutorial part 2. The fieldsets
> example does not work at all for me. I don't see the fieldsets. No
> error displayed. Anyo
I have forgotten something here, added a model to a site, restarted the
server but the add/change/delete permission set is not showing in the
auth-user add permission set, what is it I have forgotten please?
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Hi, playing around with the django tutorial part 2. The fieldsets
example does not work at all for me. I don't see the fieldsets. No
error displayed. Anyone had this? Using ubuntu 10.04 and django 1.2.3
installed with easy_install not Synaptic.
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Hi,
I am a new user to django ,can anybody please help me resolve this
issue.I am trying to construct a Gant chart based on the certain
constraints.Now i am unable to make a line of approach for this.I have
defined a class for chart and defined function for it in views.Now how
do i pass my values t
for tag in tags_list:
tag.blogs_count = tag.blogpost_set.count()
clean_tags = []
for tag in tags_list:
if tag.blogs_count != 0:
clean_tags.append(tag)
tags_list = clean_tags
- Just fixed that. The indentation gave the code a different meaning :).
On Fri, Nov 19, 2010 at 1:37 PM, S
Bruno, you were absolutely right - the "last" tag in my loop wasn't really
the last. I had this:
for tag in tags_list:
tag.blogs_count = tag.blogpost_set.count()
So, each tag would get a blog count, and some tags had zero blogs. In the
template, I was only writing out those tags that ha
Sean
I hear what you say - but is this approach also readily available inside the
Admin framework?
Derek
On 16 November 2010 16:20, Shawn Milochik wrote:
> On Tue, Nov 16, 2010 at 9:08 AM, derek wrote:
> > " you'll have to have all the states/provinces as 'choices' in the
> > ChoiceField in t
Hi Bruno,
Thanks for the idea! I checked my data and nothing seems out of the
ordinary. truly stumps me.
Regards
On Fri, Nov 19, 2010 at 12:51 PM, bruno desthuilliers <
bruno.desthuilli...@gmail.com> wrote:
>
>
> On 19 nov, 11:09, Sithembewena Lloyd Dube wrote:
> > Hi everyone,
> >
> > I have
Thanks for the replies.
I simplified the problem a bit by deciding it will be easier to have
some extra validation code in a separate admin view to do what I need
it to and removed the CurrentTag table, similar to what Rainy has
said.
On Nov 18, 4:59 pm, Rainy wrote:
> On Nov 18, 9:04 am, JE wr
On 19 nov, 11:09, Sithembewena Lloyd Dube wrote:
> Hi everyone,
>
> I have a template where Django is spitting out blog tags followed by a ','
> when the tag is not the final one in the loop.
>
> {% if not forloop.last %}, {% endif %}
>
> Strangely, I am still seeing tag1, tag2, tag3,
This shou
On 19 nov, 07:23, codingJoe wrote:
> Newbie question here... I know the basics of Django and nothing of
> ExtJS. I am running a simple web framework and I want to integrate
> ExtJS Grid into it.
>
> My first step was to run the example grid from extjs. "Yay!! It
> works"
>
> Then I wanted to re
Read up on how linux programs work the file system becomes intuitive.
Also try this:
python -c "from distutils.sysconfig import get_python_lib; print
get_python_lib()"
cheers
sam_w
On Fri, Nov 19, 2010 at 3:08 AM, Kenneth Gonsalves wrote:
> On Thu, 2010-11-18 at 06:10 -0800, sheeptick wrote:
Hi everyone,
I have a template where Django is spitting out blog tags followed by a ','
when the tag is not the final one in the loop.
{% if not forloop.last %}, {% endif %}
Strangely, I am still seeing tag1, tag2, tag3,. How can I suppress that last
','?
--
Regards,
Sithembewena Lloyd Dube
ht
I am trying to use Valum's Ajax Upload to do file uploads on a Django-
based site I am making. Currently I am avoiding a form simply because
AU sends the upload as the entirety of the POST data in an ajax
request. Right now I have a very naive approach to doing this:
upload = SimpleUploadedFile(
Hi Micheal,
Pretty sure it has nothing to do with your version of windows.
appended MS-DOS PATH: with "C:\hp\bin\Python\Lib\site-packages
\django
\bin"
which allows me to run django-admin.py
If you have installed Python and django propely, there is no need to
append anything. It should work st
There is also template2pdf which is basically and RML subset
interpreter, you write your RML from a django template and pass it to
a function from template2pdf which will generate a PDF from it.
http://code.google.com/p/template2pdf/
That is what we are using, I have even contributed a few patche
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