Github user toughrogrammer commented on the issue:
https://github.com/apache/zeppelin/pull/2628
I'm reporter of ZEPPELIN-2999. IMO it's invalid solution. With this code,
it cannot run without timeout. What I intend with no timeout option is I will
approve waiting command execution for
GitHub user prabhjyotsingh opened a pull request:
https://github.com/apache/zeppelin/pull/2628
[ZEPPELIN-2999] Cannot create shell interpreter without timeout property
### What is this PR for?
A user can not run any shell interpreter if
"shell.command.timeout.millisecs" is not p
There's no phenix interpreter for zeppelin 0.8.0, you need to figure out
what phenix interpreter you are using.
Jongyoul Lee 于2017年10月23日周一 上午10:27写道：
> Hi,
>
> I think it looks related to the version of components.
>
> Can you check it?
>
> JL
>
> On Thu, Oct 19, 2017 at 8:52 PM, Indtiny S wrot
Hi,
I think it looks related to the version of components.
Can you check it?
JL
On Thu, Oct 19, 2017 at 8:52 PM, Indtiny S wrote:
> Hi,
>
> I installed zeppelin 0.8.0 and added phoenix interpreter .
>
> when I run simple query from the
>
> %phoenix
> select "age" from "empolyeelist"
>
>
> I
