GitHub user prabhjyotsingh opened a pull request:
https://github.com/apache/zeppelin/pull/2628
[ZEPPELIN-2999] Cannot create shell interpreter without timeout property
### What is this PR for?
A user can not run any shell interpreter if
"shell.command.timeout.millisecs" is not present in interpreter setting.
### What type of PR is it?
[Improvement]
### What is the Jira issue?
*
[https://issues.apache.org/jira/browse/ZEPPELIN-2999](https://issues.apache.org/jira/browse/ZEPPELIN-2999)
### How should this be tested?
* Remove "shell.command.timeout.millisecs" from sh interpreter settings and
then try to run any sh paragraph, it should run without any error.
### Questions:
* Does the licenses files need update? N/A
* Is there breaking changes for older versions? N/A
* Does this needs documentation? N/A
You can merge this pull request into a Git repository by running:
$ git pull https://github.com/prabhjyotsingh/zeppelin ZEPPELIN-2999
Alternatively you can review and apply these changes as the patch at:
https://github.com/apache/zeppelin/pull/2628.patch
To close this pull request, make a commit to your master/trunk branch
with (at least) the following in the commit message:
This closes #2628
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commit e2a62f63d2a14ac0c13ca9774dbede3946736f8b
Author: Prabhjyot Singh <[email protected]>
Date: 2017-10-23T06:43:24Z
ZEPPELIN-2999: Cannot create shell interpreter without timeout property
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