Like David pointed out, cycles can be very complex. In theory. But
with random playouts I believe only triple-ko is possible. And rare
at that. The reason is simple: it will only keep going on if there's
no choice. Otherwise a deviation will be played at some point,
reducing the situation.
Thanks Dave, but you're answering the wrong question. I'm not asking
which super ko cases exist, but rather which ones can result in
infinite random play. The two stone ko you mentioned is resolved with
random play because other moves exist that break the cycle (even
though they are poor mo
There can be more than 3 kos in a cycle. There are some pathological cases
of loops involving captures of two-stone groups, but I've never seen this in
a real game.
Here are some example odd positions:
http://www.cs.cmu.edu/~wjh/go/rules/bestiary.html
http://www.goban.demon.co.uk/go/bestiary/mola
