On Nov 9, 2010, at 2:07 AM, Kyle Sluder wrote:
> On Mon, Nov 8, 2010 at 9:06 AM, Gerriet M. Denkmann
> wrote:
>> typedef char *(*my_type)(const char *, int);
>> my_type some = index;
>> fprintf(stderr,"sizeof(index): %lu\n", sizeof(index));
>> fprintf(stderr,"sizeof(some): %lu\n", sizeof(some));
>
On Mon, Nov 8, 2010 at 9:06 AM, Gerriet M. Denkmann
wrote:
> typedef char *(*my_type)(const char *, int);
> my_type some = index;
> fprintf(stderr,"sizeof(index): %lu\n", sizeof(index));
> fprintf(stderr,"sizeof(some): %lu\n", sizeof(some));
1. This is not a Cocoa question.
2. sizeof of an expres
These lines:
typedef char *(*my_type)(const char *, int);
my_type some = index;
fprintf(stderr,"sizeof(index): %lu\n", sizeof(index));
fprintf(stderr,"sizeof(some): %lu\n", sizeof(some));
produce:
sizeof(index): 1
sizeof(some): 8
This is x86_64 so the pointer-size should be 8 bytes. But why is
