These lines: typedef char *(*my_type)(const char *, int); my_type some = index; fprintf(stderr,"sizeof(index): %lu\n", sizeof(index)); fprintf(stderr,"sizeof(some): %lu\n", sizeof(some));
produce: sizeof(index): 1 sizeof(some): 8 This is x86_64 so the pointer-size should be 8 bytes. But why is the size of index = 1? Kind regards, Gerriet. _______________________________________________ Cocoa-dev mailing list (Cocoa-dev@lists.apple.com) Please do not post admin requests or moderator comments to the list. Contact the moderators at cocoa-dev-admins(at)lists.apple.com Help/Unsubscribe/Update your Subscription: http://lists.apple.com/mailman/options/cocoa-dev/archive%40mail-archive.com This email sent to arch...@mail-archive.com
