(defn insert [v at el]
(flatten (assoc v at [el (v at)]))
You get a lazy seq back, so further operations are probably not as
performant as they should be. But that would be as performant as a
regular assoc for just that one operation. What you do from then
on.
Mark
On Aug 26, 10:33 am, C
On Thu, Aug 26, 2010 at 12:43 PM, David Nolen wrote:
> On Thu, Aug 26, 2010 at 11:53 AM, Chouser wrote:
>>
>> On Thu, Aug 26, 2010 at 9:44 AM, Jon Seltzer
>> wrote:
>> > I know what assoc does:
>> >
>> > user=> (assoc [\a \b \c] 0 \d) ;please extend to much larger vector
>> > with index somewhe
On Thu, Aug 26, 2010 at 11:53 AM, Chouser wrote:
> On Thu, Aug 26, 2010 at 9:44 AM, Jon Seltzer
> wrote:
> > I know what assoc does:
> >
> > user=> (assoc [\a \b \c] 0 \d) ;please extend to much larger vector
> > with index somewhere in the middle
> > [\d \b \c]
> >
> > but what if I want:
> >
On Thu, Aug 26, 2010 at 11:53 AM, Chouser wrote:
> On Thu, Aug 26, 2010 at 9:44 AM, Jon Seltzer wrote:
>> I know what assoc does:
>>
>> user=> (assoc [\a \b \c] 0 \d) ;please extend to much larger vector
>> with index somewhere in the middle
>> [\d \b \c]
>>
>> but what if I want:
>>
>> user=> (
On Thu, Aug 26, 2010 at 9:44 AM, Jon Seltzer wrote:
> I know what assoc does:
>
> user=> (assoc [\a \b \c] 0 \d) ;please extend to much larger vector
> with index somewhere in the middle
> [\d \b \c]
>
> but what if I want:
>
> user=> (assoc-x [\a \b \c] 0 \d) ;is there an assoc-x
> [\a \d \b \c
I know what assoc does:
user=> (assoc [\a \b \c] 0 \d) ;please extend to much larger vector
with index somewhere in the middle
[\d \b \c]
but what if I want:
user=> (assoc-x [\a \b \c] 0 \d) ;is there an assoc-x
[\a \d \b \c]
I don't see a function that does this. I'm sure I'm missing it. I
