On Wed, Jul 13, 2011 at 5:17 PM, Sam Ritchie wrote:
> Ken, that'll result in the original vector back out again.
> (vec (take 3 (cycle [1 2 3]))) => [1 2 3].
> I think you mean:
> (vec (take (* n (count xs)) (cycle xs
I wasn't using "n" to mean the number of repetitions of the xs but the
tota
Ken, that'll result in the original vector back out again.
(vec (take 3 (cycle [1 2 3]))) => [1 2 3].
I think you mean:
(vec (take (* n (count xs)) (cycle xs
On Wed, Jul 13, 2011 at 5:13 PM, Ken Wesson wrote:
> On Wed, Jul 13, 2011 at 11:21 AM, Bhinderwala, Shoeb
> wrote:
> > Thanks Tamr
On Wed, Jul 13, 2011 at 11:21 AM, Bhinderwala, Shoeb
wrote:
> Thanks Tamreen. Your solution will have to be wrapped in another vec call. I
> will use Miekel’s:
>
>
>
> (reduce into [] (repeat n xs)).
What about (vec (take n (cycle xs)))?
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Protege: What is this seething mass of parentheses?
11 11:02 AM
To: clojure@googlegroups.com
Subject: Re: Repeating a vector n times
Damn, Meikel's solution is better, I was thinking:
(apply concat (repeat n xs))
On Wed, Jul 13, 2011 at 10:54 AM, Bhinderwala, Shoeb
wrote:
I have to write a function that will take a vector as input,
Damn, Meikel's solution is better, I was thinking:
(apply concat (repeat n xs))
On Wed, Jul 13, 2011 at 10:54 AM, Bhinderwala, Shoeb <
sabhinderw...@wellington.com> wrote:
> **
>
> I have to write a function that will take a vector as input, repeat the
> elements multiple times and return back a
Hi,
you could use (reduce into [] (repeat n xs)).
Sincerely
Meikel
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I have to write a function that will take a vector as input, repeat the
elements multiple times and return back a single vector of the repeated
items. I came up with the following but am wondering if there is a
better or simpler way to write this:
(def xs ["a" "b" "c"])
(defn repeat-vec-n
[xs
