Damn, Meikel's solution is better, I was thinking:

(apply concat (repeat n xs))

On Wed, Jul 13, 2011 at 10:54 AM, Bhinderwala, Shoeb <
sabhinderw...@wellington.com> wrote:

> **
>
> I have to write a function that will take a vector as input, repeat the
> elements multiple times and return back a single vector of the repeated
> items. I came up with the following but am wondering if there is a better
> or simpler way to write this:
>
> (def xs ["a" "b" "c"])
>
> (defn repeat-vec-n
>
>   [xs n]
>
>   (vec
>
>     (reduce concat []
>
>       (take n (repeat xs)))))
>
> OUTPUT:
>
> user=> xs
>
> ["a" "b" "c"]
>
> user=> (repeat-vec-n xs 3)
>
> ["a" "b" "c" "a" "b" "c" "a" "b" "c"]
>
> *******-- Shoeb*
>
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