On 28 March 2013 22:51, Ryan wrote:
> Thanks for your explanation Jonathan. I am still a bit confused however what
> is the proper solution here. Should i use an anonymous function instead to
> do what I want or can it be done with the #() syntax?
Just wanted to add that the #() syntax is just sh
Thanks Gary, it didn't cross my mind that i can use the # reader with the
threading macro :)
On Tuesday, April 2, 2013 4:15:58 PM UTC+3, Gary Verhaegen wrote:
>
> And there's the threading macro : #(-> {:foo %})
>
> On 1 April 2013 07:12, Ryan > wrote:
> > Thanks for your input guys
> >
> > R
Thanks Gary, it didn't cross my mind that i can use the # reader with the
threading macro :)
On Tue, Apr 2, 2013 at 4:15 PM, Gary Verhaegen wrote:
> And there's the threading macro : #(-> {:foo %})
>
> On 1 April 2013 07:12, Ryan wrote:
> > Thanks for your input guys
> >
> > Ryan
> >
> >
> > On
And there's the threading macro : #(-> {:foo %})
On 1 April 2013 07:12, Ryan wrote:
> Thanks for your input guys
>
> Ryan
>
>
> On Sunday, March 31, 2013 11:11:08 AM UTC+3, Alex Baranosky wrote:
>>
>> There's also 'for'
>>
>> (defn my-function [foo-id a-keyword a-list]
>> (for [m a-list]
>>
Thanks for your input guys
Ryan
On Sunday, March 31, 2013 11:11:08 AM UTC+3, Alex Baranosky wrote:
>
> There's also 'for'
>
> (defn my-function [foo-id a-keyword a-list]
> (for [m a-list]
> {:foo_id foo-id (keyword a-keyword) (:BAR_KEY m)}))
>
>
> On Sun, Mar 31, 2013 at 12:57 AM, JvJ >w
There's also 'for'
(defn my-function [foo-id a-keyword a-list]
(for [m a-list]
{:foo_id foo-id (keyword a-keyword) (:BAR_KEY m)}))
On Sun, Mar 31, 2013 at 12:57 AM, JvJ wrote:
> ...even cheezier, use do
> #(do {:foo %})
>
>
> On Saturday, 30 March 2013 23:58:31 UTC-4, JvJ wrote:
>>
>> He
...even cheezier, use do
#(do {:foo %})
On Saturday, 30 March 2013 23:58:31 UTC-4, JvJ wrote:
>
> Here's a cheezy hack, use identity.
>
> #(identity {:foo %})
>
> On Thursday, 28 March 2013 17:51:10 UTC-4, Ryan wrote:
>>
>> Thanks for your explanation Jonathan. I am still a bit confused however
>
Here's a cheezy hack, use identity.
#(identity {:foo %})
On Thursday, 28 March 2013 17:51:10 UTC-4, Ryan wrote:
>
> Thanks for your explanation Jonathan. I am still a bit confused however
> what is the proper solution here. Should i use an anonymous function
> instead to do what I want or can i
No problem, glad to be of help. :)
Jonathan
On Thu, Mar 28, 2013 at 11:19 PM, Ryan wrote:
> Thanks for all your help Jonathan :) I went with the standard fn syntax,
> its a two-liner anyway so not a big of deal :)
> The important part here was that I learned that #() executes the content
> as
Thanks for all your help Jonathan :) I went with the standard fn syntax,
its a two-liner anyway so not a big of deal :)
The important part here was that I learned that #() executes the content as
a function, very helpful!
Ryan
On Friday, March 29, 2013 12:08:04 AM UTC+2, Jonathan Fischer Friber
It can still be done with the #(), with for example the hash-map function.
It's basically the same as the {} but as a function, like this:
(hash-map :a 3 :b 4)
=> {:a 3, :b 4}
So you should be able to write the function as:
#(hash-map :foo_id foo-id (keyword a-keyword) (:BAR_KEY %))
I think you s
Thanks for your explanation Jonathan. I am still a bit confused however
what is the proper solution here. Should i use an anonymous function
instead to do what I want or can it be done with the #() syntax?
Hyphens is my preferred way as well, but, those keys represent sql columns
which they use
It's because the #() syntax always calls the content as a function.
So #(...) is the same as (fn [] (...)). In your case,
#({:foo_id foo-id (keyword a-keyword) (:BAR_KEY %)})
is the same as:
(fn [%] ({:foo_id foo-id (keyword a-keyword) (:BAR_KEY %)}))
Note the extra () around {}. In other words, y
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