On 28 March 2013 22:51, Ryan <arekand...@gmail.com> wrote: > Thanks for your explanation Jonathan. I am still a bit confused however what > is the proper solution here. Should i use an anonymous function instead to > do what I want or can it be done with the #() syntax?
Just wanted to add that the #() syntax is just shorthand notation expanded by the reader into fn* forms, so what it produces is an anonymous function, with no special magic. To see the exact expansion, you can quote a #() form: user=> '#(foo) (fn* [] (foo)) fn* is the special form behind #() and fn (which is a macro); basically an implementation detail. Cheers, Michał -- -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en --- You received this message because you are subscribed to the Google Groups "Clojure" group. To unsubscribe from this group and stop receiving emails from it, send an email to clojure+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.
