> (rest *v1) is equal to *v2 in the below mentioned example. Then why
> `conj' operation on them is returning different things.
rest is giving you a seq. conj is thus producing a cons where the
first is 0 and the rest is that seq. (Essentially, seqs are treated as
lists, and thus print with
Hi Nipra,
2009/11/27 nipra :
> Hi,
> (rest *v1) is equal to *v2 in the below mentioned example. Then why
> `conj' operation on them is returning different things.
>
> user> (def *v1 [1 2 3 4 5])
> #'user/*v1
> user> (def *v2 [2 3 4 5])
> #'user/*v2
> user> (= (rest *v1) *v2)
> true
> user> (def
Hi,
(rest *v1) is equal to *v2 in the below mentioned example. Then why
`conj' operation on them is returning different things.
user> (def *v1 [1 2 3 4 5])
#'user/*v1
user> (def *v2 [2 3 4 5])
#'user/*v2
user> (= (rest *v1) *v2)
true
user> (def *v3 (conj (rest *v1) 0))
#'user/*v3
user> *v3
(0
