> (rest *v1) is equal to *v2 in the below mentioned example. Then why > `conj' operation on them is returning different things.
rest is giving you a seq. conj is thus producing a cons where the first is 0 and the rest is that seq. (Essentially, seqs are treated as lists, and thus print with parens.) user=> (rest [1 2 3 4 5]) (2 3 4 5) user=> (type (rest [1 2 3 4 5])) clojure.lang.PersistentVector$ChunkedSeq user=> (conj (rest [1 2 3 4 5]) 1) (1 2 3 4 5) user=> (type *1) clojure.lang.Cons user=> (rest *2) (2 3 4 5) user=> (type *1) clojure.lang.PersistentVector$ChunkedSeq If you want conj to act as if it's working on a vector, you need to give it a vector: user=> (conj (vec (rest [1 2 3 4])) :a) [2 3 4 :a] user=> (conj (rest [1 2 3 4]) :a) (:a 2 3 4) -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
