Hi Tim,
your getArg function is actually a nice use case
of a not very often used of condp: :>>.
Please note in the following example: as David
Nolen said, we have to use seq after re-seq since
re-seq doesn't return a nil but the empty list.
Hence I used comp to chain the two together.
Also inco
On Mar 9, 2009, at 5:48 AM, timc wrote:
>
> (re-seq #"([a-zA-Z_0-9]+)=([^ ]+)" arg))]
>
Two small suggestions--it's easier, and more legible to use \S to
match non-whitespace characters:
(re-seq #"([a-zA-Z_0-9]+)=(\S+)" arg)
And you've basically defined the "word character" cl
On Mar 9, 10:48 am, timc wrote:
> Can someone please see what's wrong with this.
>
> (defn getArg [arg]
> "Return a [keyword value] depending on the form of the string arg:
> 1. arg is of the form +x ==> [:x true].
> 2. arg is of the form -x ==> [:x false].
> 3.
Thanks David.
On Mar 9, 4:22 pm, David Nolen wrote:
> The first regex is returning an empty list not nil.
> David
>
> On Mon, Mar 9, 2009 at 11:48 AM, timc wrote:
>
> > Can someone please see what's wrong with this.
>
> > (defn getArg [arg]
> > "Return a [keyword value] depending on the
The first regex is returning an empty list not nil.
David
On Mon, Mar 9, 2009 at 11:48 AM, timc wrote:
>
> Can someone please see what's wrong with this.
>
> (defn getArg [arg]
>"Return a [keyword value] depending on the form of the string arg:
>1. arg is of the form +x ==> [:x t
Can someone please see what's wrong with this.
(defn getArg [arg]
"Return a [keyword value] depending on the form of the string arg:
1. arg is of the form +x ==> [:x true].
2. arg is of the form -x ==> [:x false].
3. arg is of the form x=v ==> [:x v].
4. el
