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Dear Pavel, dear Garib,
how do you figure out automatically the correct flag? (I hope both
phenix and refmac will allow to manual overwrite the software's decision)
Cheers,
Tim
On 01/24/2013 07:47 PM, Pavel Afonine wrote:
> Hi,
>
> It would be nice
You can just connect two machines together with an ethernet cable, no switches
or
routers. However you need a crossover cable to do this. Most likely you have
standard
cables only in the lab.
Adam
Dear Tim
In principle if a user defines freer flag then refmac knows about that (unless
freer flag is 0 then refmac assumes that it is default). In this case (if freer
defined by user) then it is not altered.
regards
Garib
On 25 Jan 2013, at 09:14, Tim Gruene wrote:
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Dear Adam,
cross-over cables are only required for really old machines. For a few
years, RJ-45 plugs have been able to figure out automatically whether
they are connected to a switch or directly to another machine.
Best,
Tim
On 01/25/2013 10:40 AM,
I noticed that Refmac has done the 1vs0 thing correct for ages, which is very
useful because mix-ups between the work set and test set used to be quite
common in the reflection files at the pdb (Refmac saved me a lot of extra work
with this). Dealing with this problem is very simple as the small
The FFT software tries to limit the volume to the asymmetric unit for the
spacegroup. This has to be a 3-D box, so cubic spacegroups give more peaks
than expected, but not a full list of 1260 ..
However there may not be a complete list - these S are in di-sulphide
bonds, and at limited resoluton yo
Hi Wei
Are you saying that the highest 9 peaks in your list that you highlighted
correspond to disulphide-disulphide vectors and the rest don't? Actually
of the 9 only 3 are independent, the other 6 are related by the 3-fold so
you need to take that into account in your calculation of the no of p
On Fri, Jan 25, 2013 at 2:24 AM, Robbie Joosten
wrote:
> Phenix however needs to deal with the CCP4 type reflection binning. Now the
> size of the sets cannot be used which means that you have find a smarter
> solution. So I wonder how this is implemented. Does Phenix use the
> (reasonable) assump
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Hi Wei
The explanation from looking at your FFT log file would appear to be that
what you have calculated is not a Patterson at all but an anomalous
difference Fourier, which would of course explain the lack of peaks! The
evidence for this is that the FFT run 1) has the phase & FOM assigned, 2)
i
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