Okay, I am not a physicist, but let's see if we're talking about the
same thing. Could it be that the author of this Wikipedia entry is
referring to Fraunhofer diffraction rather than Fresnel diffraction?
See
http://hyperphysics.phy-astr.gsu.edu/hbase/phyopt/fraunhofcon.html
and
http://hyp
ter
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From: CCP4 bulletin board on behalf of Carlos Frazao
Sent: Wed 24/01/2007 09:09
To: CCP4BB@JISCMAIL.AC.UK
Subject: [ccp4bb] relation between wavelength and inter-atomic distances
Hi,
I have once heard and recently read that "the
Diana Tomchick wrote:
The most conceptually simple example of diffraction is single-slit
diffraction in which the slit is narrow, that is, significantly
smaller than a wavelength of the wave.
What ? Diffraction when the slit is much smaller than the wavelength ???
After the wave passes throug
Carlos Frazao wrote:
Hi,
I have once heard and recently read that "the diffraction event
results from the fact that both the X-rays wavelength and the atomic
distances are of the same magnitude". Although such a relation seems
appealing I am unsure if this is not a mere coincidence. Could som
On Jan 24, 2007, at 11:04 AM, Bart Hazes wrote:
Carlos Frazao wrote:
Hi,
I have once heard and recently read that "the diffraction event
results from the fact that both the X-rays wavelength and the
atomic distances are of the same magnitude". Although such a
relation seems appealing I am
Carlos Frazao wrote:
Hi,
I have once heard and recently read that "the diffraction event results
from the fact that both the X-rays wavelength and the atomic distances
are of the same magnitude". Although such a relation seems appealing I
am unsure if this is not a mere coincidence. Could some
Hi Carlos,
In his book "Crystals, X-rays and Proteins", Dennis Sherwood
explained in the first chapter: why do use x-rays?
Using his analogy: for a small boat (5 m length) in the ocean,
waves come in from the ocean with a wavelength (say 20 - 30 m) are
merely pass underneath the boat.
On t
Hi Carlos
It is more than coincidence - in that the X-rays we use for diffraction
are _chosen_ from the spectrum of X-ray wavelengths that correspond to the
interatomic distances (though this is not the only reason they are
chosen).
X-rays can be thought of as those EM waves with wavelengths from
As a rule of thumb from optics, you need a wavelength at least twice the
distance or shorter between two points you want to resolve. That is why we
cannot do a diffraction experiment with visible light.
On the other hand, if the wavelength were much shorter, inaccuracies in
their positions wou
teratomic distance, plus or minus a factor of
~ 1.5.
-- Ian
> -Original Message-
> From: CCP4 bulletin board [mailto:[EMAIL PROTECTED] On
> Behalf Of Carlos Frazao
> Sent: 24 January 2007 09:09
> To: CCP4BB@JISCMAIL.AC.UK
> Subject: [ccp4bb] relation between wav
Hi,
I have once heard and recently read that "the diffraction event results
from the fact that both the X-rays wavelength and the atomic distances
are of the same magnitude". Although such a relation seems appealing I
am unsure if this is not a mere coincidence. Could someone clarify or
lead m
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