> -Original Message-
> From: Randal L. Schwartz [mailto:[EMAIL PROTECTED]
> Sent: Wednesday, December 24, 2003 3:50 PM
> To: [EMAIL PROTECTED]
> Subject: Re: the ref() function: what does it mean when ...
>
>
> >>>>> "Wiggins"
Randal L. Schwartz wrote:
"Wiggins" == Wiggins D Anconia <[EMAIL PROTECTED]> writes:
Wiggins> Out of curiousity, why/when *in Perl* would you take a reference to
Wiggins> something that holds a reference? And, "how deep does the well go?"
Wiggins> (how far will Perl take the above indirection?).
> "Wiggins" == Wiggins D Anconia <[EMAIL PROTECTED]> writes:
Wiggins> Out of curiousity, why/when *in Perl* would you take a reference to
Wiggins> something that holds a reference? And, "how deep does the well go?"
Wiggins> (how far will Perl take the above indirection?)... I suppose I could
On Dec 24, 2003, at 12:05 PM, Wiggins d Anconia wrote:
[..]
Out of curiousity, why/when *in Perl* would you take a reference to
something that holds a reference?
Good question, let me know if you find a gooder answer.
But clearly the fact that it can detect that a given
scalar is a reference to a r
>
> On Dec 24, 2003, at 11:24 AM, [EMAIL PROTECTED] wrote:
> [..]
> > However, I have not seen this documented; could someone please (1)
> > confirm or refute this (2) clarify if necessary and (3) point me to
> > the relevant documentation. (The perlfunc page for ref() just lists
> > possibl
On Dec 24, 2003, at 11:24 AM, [EMAIL PROTECTED] wrote:
[..]
However, I have not seen this documented; could someone please (1)
confirm or refute this (2) clarify if necessary and (3) point me to
the relevant documentation. (The perlfunc page for ref() just lists
possible return values, and not
Hi list,
This question has to do with the ref() built-in function and its return values.
I see that one possible return value is 'REF', which I am inferring to mean that the
argument given to ref() is a reference to a scalar which is itself a reference.
However, I have not seen this documen
