>>>>> "Wiggins" == Wiggins D Anconia <[EMAIL PROTECTED]> writes:
Wiggins> Out of curiousity, why/when *in Perl* would you take a reference to Wiggins> something that holds a reference? And, "how deep does the well go?" Wiggins> (how far will Perl take the above indirection?)... I suppose I could Wiggins> just test, but I am rather lazy... For the same reason you might take a reference to a scalar otherwise... indirection. For example, I might have my $active_table = [EMAIL PROTECTED]; and then I want to call a subroutine to decide a new active table: adjust_table(\$active_table); sub adjust_table { my $table_ref = shift; $$table_ref = rand(2) > 1 ? [EMAIL PROTECTED] : [EMAIL PROTECTED]; } I can't change $active_table except by reference. -- Randal L. Schwartz - Stonehenge Consulting Services, Inc. - +1 503 777 0095 <[EMAIL PROTECTED]> <URL:http://www.stonehenge.com/merlyn/> Perl/Unix/security consulting, Technical writing, Comedy, etc. etc. See PerlTraining.Stonehenge.com for onsite and open-enrollment Perl training! -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>