(Randal L. Schwartz) schreef:
> And I came up with this:
>
> $variable ||= 0; # all false values become 0
> $variable &&= 1; # all true values become 1
How about this:
($variable ||= 0) &&= 1 ;
or
($variable &&= 1) ||= 0 ;
depending on whether you expect $variable to be fa
Intrah onat Diria .. 09 Jun 2006 08:10:11 -0700
, Randal L. Schwartz wrote "Revera y":
> x-mayan-date: Long count = 12.19.13.6.13; tzolkin = 9 Ben; haab = 6 Zotz
..
the following could be unreadable @ 1149876152 :::
_
, /
, >
, 982
, "tome"
, >
, i
> ""Dr" == "Dr Ruud" writes:
"Dr> And q{0 but true} and q{0e0} and q{0e1} etc. become 1 as well.
Exactly what I wanted, yes.
--
Randal L. Schwartz - Stonehenge Consulting Services, Inc. - +1 503 777 0095
http://www.stonehenge.com/merlyn/>
Perl/Unix/security consulting, Technical writing,
> ""Mr" == "Mr Shawn H Corey" <[EMAIL PROTECTED]> writes:
"Mr> How about?
"Mr> $variable = 1 - !$variable;
Same problem. And you'll also get a warnings error.
There is *no promise* in the Perl docs that a boolean returns a specific value
for "true" or "false". Any code that depends on s
(Randal L. Schwartz) schreef:
> There's an &&=, and I thought I'd never use it.
>
> However, one day, I realized that I needed to "normalize" the
> "true/false" value of a variable, because I wanted to reduce all
> possible true/false values to just 1/0 for easy operations in the
> next step of th
On Fri, 2006-09-06 at 09:54 -0400, Mr. Shawn H. Corey wrote:
> How about?
>
> $variable = 1 - !$variable;
And, of course, to calculate its inverse:
$variable = 1 - !!$variable;
--
__END__
Just my 0.0002 million dollars worth,
--- Shawn
"For the things we have to learn before we c
On Fri, 2006-09-06 at 06:10 -0700, Randal L. Schwartz wrote:
> > ""John" == "John W Krahn" <[EMAIL PROTECTED]> writes:
>
> "John> Wouldn't
>
> "John> $variable = !!$variable;
>
> "John> work just as well?
>
> No. There's no promise that the output of ! is "0" and "1". In fact,
>
> ""John" == "John W Krahn" <[EMAIL PROTECTED]> writes:
"John> Wouldn't
"John> $variable = !!$variable;
"John> work just as well?
No. There's no promise that the output of ! is "0" and "1". In fact,
it's "" and "1". And that's exactly what I was trying to avoid.
Don't confuse C
-Original Message-
From: Bryan R Harris [mailto:[EMAIL PROTECTED]
Sent: Wednesday, June 07, 2006 4:43 PM
To: Beginners Perl
Subject: Re: defaults
>
>
> Take this (lame) example of an RSVP to an invitation:
>
> **
> $_ = "Bil
> Bryan R Harris wrote:
>>
>> Can someone explain what:
>>
>> $pi ||= 3;
>>
>> ...means? I just saw it in Programming Perl (pp 540), but it doesn't
>> explain it. Thx!
>
> || is the logical OR operator (see perldoc perlop) which says that if $pi is
> TRUE then keep the current value of $pi
Randal L. Schwartz wrote:
>>"Bryan" == Bryan R Harris <[EMAIL PROTECTED]> writes:
>
> Bryan> Is there an "&&=" also? How about "or="?
>
> There's an &&=, and I thought I'd never use it.
>
> However, one day, I realized that I needed to "normalize" the "true/false"
> value of a variable, bec
> "Bryan" == Bryan R Harris <[EMAIL PROTECTED]> writes:
Bryan> Is there an "&&=" also? How about "or="?
There's an &&=, and I thought I'd never use it.
However, one day, I realized that I needed to "normalize" the "true/false"
value of a variable, because I wanted to reduce all possible tru
Bryan R Harris wrote:
>
>>>Can someone explain what:
>>>
>>>$pi ||= 3;
>>>
>>>...means? I just saw it in Programming Perl (pp 540), but it doesn't
>>>explain it. Thx!
>>|| is the logical OR operator (see perldoc perlop) which says that if $pi is
>>TRUE then keep the current value of $pi but if $
Bryan R Harris wrote:
: Is there an "&&=" also? How about "or="?
All perl operators are listed in the 'perlop' file.
HTH,
Charles K. Clarkson
--
Mobile Homes Specialist
Free Market Advocate
Web Programmer
254 968-8328
Don't tread on my bandwidth. Trim your posts.
--
To unsubscribe, e
>> Can someone explain what:
>>
>> $pi ||= 3;
>>
>> ...means? I just saw it in Programming Perl (pp 540), but it doesn't
>> explain it. Thx!
>
> || is the logical OR operator (see perldoc perlop) which says that if $pi is
> TRUE then keep the current value of $pi but if $pi is FALSE then ass
Bryan R Harris wrote:
>
> Can someone explain what:
>
> $pi ||= 3;
>
> ...means? I just saw it in Programming Perl (pp 540), but it doesn't
> explain it. Thx!
|| is the logical OR operator (see perldoc perlop) which says that if $pi is
TRUE then keep the current value of $pi but if $pi is FAL
16 matches
Mail list logo
