On Fri, 2006-09-06 at 06:10 -0700, Randal L. Schwartz wrote: > >>>>> ""John" == "John W Krahn" <[EMAIL PROTECTED]> writes: > > "John> Wouldn't > > "John> $variable = !!$variable; > > "John> work just as well? > > No. There's no promise that the output of ! is "0" and "1". In fact, > it's "" and "1". And that's exactly what I was trying to avoid.
How about? $variable = 1 - !$variable; -- __END__ Just my 0.00000002 million dollars worth, --- Shawn "For the things we have to learn before we can do them, we learn by doing them." Aristotle * Perl tutorials at http://perlmonks.org/?node=Tutorials * A searchable perldoc is at http://perldoc.perl.org/ -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>
