"Sharad Gupta" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
>
> Hi All,
>
> I have a path like:
>
> $s = "http::/foo/bar:http::/foo1/bar1:http/foo1/bar1";
^^
Is your data accurately reflected in $s? There is no :: after the
On Wed, Aug 06, 2003 at 07:02:21PM -0700 Gupta, Sharad wrote:
> I have a path like:
>
> $s = "http::/foo/bar:http::/foo1/bar1:http/foo1/bar1";
>
> I am trying to get all the http paths which are seperated by ":" like this:
>
> @x = ($s =~ /(http::.*?):(?=http::.*?)/g)
>
> The problem is i get
In the @x i am expecting to get all the http paths just like u showed in ur example.
This should work fine.
Thanx,
-Sharad
-Original Message-
From: Todd W. [mailto:[EMAIL PROTECTED]
Sent: Wednesday, August 06, 2003 9:32 PM
To: [EMAIL PROTECTED]
Subject: Re: Look Ahead
"S
