In the @x i am expecting to get all the http paths just like u showed in ur example. This should work fine.
Thanx, -Sharad -----Original Message----- From: Todd W. [mailto:[EMAIL PROTECTED] Sent: Wednesday, August 06, 2003 9:32 PM To: [EMAIL PROTECTED] Subject: Re: Look Ahead "Sharad Gupta" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > > Hi All, > > I have a path like: > > $s = "http::/foo/bar:http::/foo1/bar1:http/foo1/bar1"; ^^ Is your data accurately reflected in $s? There is no :: after the last 'http'? > I am trying to get all the http paths which are seperated by ":" like this: > > @x = ($s =~ /(http::.*?):(?=http::.*?)/g) Could you explain what you want in @x? Right off I'm not sure what you expect the look ahead to do for you. I think you can do without it. If I am reading correctly, you want to seperate the data at the colins: [EMAIL PROTECTED] trwww]$ perl $s = "http::/foo/bar:http::/foo1/bar1:http::/foo1/bar1"; @x = $s =~ /(http::[^:]+)/g; print( map { "$_\n" } @x ); Ctrl-D http::/foo/bar http::/foo1/bar1 http::/foo1/bar1 if the '::'s are optional like in the string you posted, use: [EMAIL PROTECTED] trwww]$ perl $s = "http::/foo/bar:http::/foo1/bar1:http/foo1/bar1"; @x = $s =~ /(http:?:?[^:]+)/g; print( map { "$_\n" } @x ); Ctrl-D http::/foo/bar http::/foo1/bar1 http/foo1/bar1 Todd W. -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
