ohnson" <[EMAIL PROTECTED]>
To: [EMAIL PROTECTED], "Rafael Morales" <[EMAIL PROTECTED]>
Subject: RE: Dates again.
Date: Mon, 5 Dec 2005 10:32:29 -0800
>
>
> localtime() returns an array with populated with the details about the
> current time and date (unless y
Hi vmalik -
At 2005-12-05, 07:09:51 you wrote:
>I am assuming that localtime() returns the time in unix file format (number of
>seconds since 12:00 AM on January 01, 1970). Why don't you convert 72 days to
>seconds and subtract that number from the output of localtime()?
No. time() returns epo
ven easier:
my $dateInThePast = time - 72 * 86400;
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
Sent: Monday, December 05, 2005 9:10 AM
To: Rafael Morales
Cc: beginners@perl.org
Subject: Re: Dates again.
I am assuming that localtime() returns the time in unix f
I am assuming that localtime() returns the time in unix file format (number of
seconds since 12:00 AM on January 01, 1970). Why don't you convert 72 days to
seconds and subtract that number from the output of localtime()?
For example, 72 days = 72 x 3600 x 24 seconds = 6220800 seconds
So, try:
Hi to all !!!
Now I have a new trouble with dates. How can I know the date of 72 days ago ?.
For example for get 2005-12-05, I do this
use POSIX qw(strftime);
my $today = strftime "%Y-%m%d", localtime();
I would like to get this date: 2005-09-21.
Thanks list.
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