I am assuming that localtime() returns the time in unix file format (number of seconds since 12:00 AM on January 01, 1970). Why don't you convert 72 days to seconds and subtract that number from the output of localtime()?
For example, 72 days = 72 x 3600 x 24 seconds = 6220800 seconds So, try: -------------------------------------------------------------------------------- use POSIX qw(strftime); my $SeventyTwoDaysAgo = strftime "%Y-%m%d", localtime() - 6220800; -------------------------------------------------------------------------------- or something along these line..... Quoting Rafael Morales <[EMAIL PROTECTED]>: > Hi to all !!! > > Now I have a new trouble with dates. How can I know the date of 72 days ago > ?. For example for get 2005-12-05, I do this > > use POSIX qw(strftime); > > my $today = strftime "%Y-%m%d", localtime(); > > I would like to get this date: 2005-09-21. > > Thanks list. > > -- > _______________________________________________ > Get your free email from http://mymail.bsdmail.com > > -- > To unsubscribe, e-mail: [EMAIL PROTECTED] > For additional commands, e-mail: [EMAIL PROTECTED] > <http://learn.perl.org/> <http://learn.perl.org/first-response> > > > ---------------------------------------- This mail sent through www.mywaterloo.ca -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>
