s ;)
David R. Wagner
Senior Programmer Analyst
FedEx Freight
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When using the system function I get an error. Does anyone know
how to
achieve that in perl.
thanks in advance,
Thomas
Sincerely,
James Moser
ja...@endpoi
codes.
Thanks
Sincerely,
James Moser
ja...@endpoint.com
There are 10 kinds of people in the world.
Those who understand binary, and those who do not.
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is not listed as a perl predefined variable, though you or
someone else could certainly create and use a variable by that name.
If you are seeing %ENV_VARS is a perl script, that is most likely what
someone has done.
Sincerely,
James Moser
[EMAIL PROTECTED]
There are 10 kinds of people
set $title
to $title1 if defined, otherwise to $title2 if defined and otherwise
to $old_title.
Oh sweet, I did not know that... thanks Jenda!
Sincerely,
James Moser
[EMAIL PROTECTED]
There are 10 kinds of people in the world.
Those who understand binary, and those who do not.
-BEGIN PGP
title = $image->title2;
}
else {
$title = $image->oldtitle;
}
Wouldn't this work for what you are trying to do:
my $title = $image->title1 || $image->title2 || $image->oldtitle;
Sincerely,
James Moser
[EMAIL PROTECTED]
T
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
On Dec 2, 2008, at 11:51 AM, John W. Krahn wrote:
James Moser wrote:
On Dec 2, 2008, at 5:48 AM, Koti wrote:
I have a directory named "X" which has many sub directories
"Y","Z","W" and many files a
}
else {
print $l2;
print " It's a file!\n";
}
}
}
print "Enter The Directory Path";
$dir = ;
chomp($dir);
directory($dir);
This should work for what your trying to do, but I have
