> awk '{$1="";print}'
> should do what you want, provided that you don't care about leading spaces.
really, it works, I have still much to learn, thank you,
Peter, aka ++pac
I think
awk '{$1="";print}'
should do what you want, provided that you don't care about leading spaces.
2009/11/19 Peter A. Cejchan :
> On Thu, Nov 19, 2009 at 9:52 AM, Russ Cox wrote:
>> awk '{print substr($0, 1+length($1)+1)}'
>>
>
> Big thank you, Russ, however, wouldn't it be smarter if we ha
On Thu, Nov 19, 2009 at 9:52 AM, Russ Cox wrote:
> awk '{print substr($0, 1+length($1)+1)}'
>
Big thank you, Russ, however, wouldn't it be smarter if we had some
kind of 'not' operator here...? Sometimes, especially when you write
the script by hand it is easier to delete few fields than to
expli
awk '{print substr($0, 1+length($1)+1)}'
