I think
awk '{$1="";print}'
should do what you want, provided that you don't care about leading spaces.
2009/11/19 Peter A. Cejchan <tyap...@gmail.com>:
> On Thu, Nov 19, 2009 at 9:52 AM, Russ Cox <r...@swtch.com> wrote:
>> awk '{print substr($0, 1+length($1)+1)}'
>>
>
> Big thank you, Russ, however, wouldn't it be smarter if we had some
> kind of 'not' operator here...? Sometimes, especially when you write
> the script by hand it is easier to delete few fields than to
> explicitly write out all those remaining... IMHO...
>
> ++pac
>
>
--
Hugo
