Re: [R] R ANOVA gives diferent results than SPSS

2010-02-11 Thread Joe King
I have found a similar problem with the ANOVA function in R, I found the
problem is when you specify a variable in SPSS as a random variable instead
of fixed, and R treats all of the factors as fixed.

Joe King
206-913-2912
j...@joepking.com
"Never throughout history has a man who lived a life of ease left a name
worth remembering." --Theodore Roosevelt


-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Greg Snow
Sent: Thursday, February 11, 2010 10:45 AM
To: Protzko; r-help@r-project.org
Subject: Re: [R] R ANOVA gives diferent results than SPSS

A couple of possibilities:

The data is not the same, e.g. something in the file was interpreted
differently by the 2 programs, one of the programs may have stopped reading
at an unrecognized value, while the other skipped it and went on.  Or it
used to be common to encode missing values as -999, if one program
recognizes that as missing, but you did not tell the other one too, then it
could treat that as a legitimate value.

The model is not the same, e.g. one program may be interpreting your
grouping variable as a continuous variable and the other as categorical,
which would result in 2 very different models and outcomes.

If you show us your data/code/output as has been requested, then we may be
able to tell which it is.  Without that information you are expecting either
R or the members of the list to read your mind.  I keep making notes to my
future self to use the timetravel package (not written yet, that's why I
need my future self to use it) to send a copy of the esp package (also not
written yet) back in time to me so I can use it for situations like this.
But so far that has not worked (maybe my future self is even more lazy than
my present self, or my near future self does something to offend my far
future self enough that he is unwilling to do this small favor for my
current past self, darn, either way means I should probably do better on the
diet/exercise).  

The short version of the above rambling is that we want to help, but cannot
help you until you help us to help you.  Show us your data/code/output (or
data/code/output for simulated/example data if you can't show your real
data).




-- 
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111


> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
> project.org] On Behalf Of Protzko
> Sent: Thursday, February 11, 2010 9:38 AM
> To: r-help@r-project.org
> Subject: Re: [R] R ANOVA gives diferent results than SPSS
> 
> 
> a one-way ANOVA should be a one-way ANOVA I guess, model is simple
> enough I
> thought.  The F value seems pretty clear, I'm doing nothing fancy here,
> just
> trying to figure out how to do in R what I'm doing in SPSS.
> --
> View this message in context: http://n4.nabble.com/R-ANOVA-gives-
> diferent-results-than-SPSS-tp1477322p1477468.html
> Sent from the R help mailing list archive at Nabble.com.
> 
> __
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-
> guide.html
> and provide commented, minimal, self-contained, reproducible code.

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Re: [R] Multiple missing values

2010-02-14 Thread Joe King
Gary King's Amelia package for R and a stand alone version does EM algorithm
multiple imputation.

Joe King
206-913-2912
j...@joepking.com
"Never throughout history has a man who lived a life of ease left a name
worth remembering." --Theodore Roosevelt

-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Frank E Harrell Jr
Sent: Sunday, February 14, 2010 9:39 AM
To: Patrick Burns
Cc: r-help@r-project.org; john.macin...@ed.ac.uk
Subject: Re: [R] Multiple missing values

Patrick Burns wrote:
> I can think of a few solutions, none perfect.
> 
> * You could have a master dataset that has the
> missing value codes you want, and a dataset that
> you use which is a copy of it with real NA's in it.
> 
> * You could add an attribute that gives the types
> of missing values in the various positions.  The
> downside is that attributes tend to disappear with
> subsetting.

The sas.get function in the Hmisc exemplifies that approach, and it has 
a subsetting method that preserves the special.miss attribute.

Frank

> 
> * If you only have two types, you might be able to
> get away with using NaN as the second type of NA.
> 
> On 14/02/2010 14:33, John wrote:
>> Does anyone know, or know documentation that describes, how to declare
>> multiple values in R as missing that does not involve coding them as 
>> NA? I
>> wish to be able to treate values as missing, while still retaining codes
>> that describe the reason for the value being missing.
>>
>> Thanks
>>
>> John MAcInnes
>>
>>
>>
-- 
Frank E Harrell Jr   Professor and ChairmanSchool of Medicine
  Department of Biostatistics   Vanderbilt University

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[R] opacity under dispersion command under plotrix

2009-10-30 Thread Joe King
Is there anyway to make the lines in the dispersion command come forward in
a plot and allow the fill in the dispersion parameter be transparent so all
of the lines I am using to note confidence intervals are shown?

 

---

Joe King, M.A.

Ph.D. Student 

University of Washington - Seattle

206-913-2912  

j...@joepking.com

---

"Never throughout history has a man who lived a life of ease left a name
worth remembering." --Theodore Roosevelt

 


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Re: [R] opacity under dispersion command under plotrix

2009-10-30 Thread Joe King
Heres my code:

era1 <- seq(1.5,5,.25)
plot(era1,yhyp1$pe, xlab="ERA", ylab="Probability of Winning Cy
Young",type="l", col="black", lwd=2)
dispersion(era1,yhyp1$pe,y1upper,y1lower,type="l",
fill="blue",arrow.cap=0.01,intervals=FALSE)#Requres plotrix
dispersion(era1,yhyp2$pe,y2upper,y2lower,type="l",
fill="lightcyan",arrow.cap=0.01,intervals=FALSE)#Requres plotrix
dispersion(era1,yhyp3$pe,y3upper,y3lower,type="l",
fill="gray97",arrow.cap=0.01,intervals=FALSE)#Requres plotrix
lines(era1,yhyp1$pe,col="black", lwd=5)
lines(era1,yhyp2$pe,col="blue", lwd=5)
lines(era1,yhyp3$pe,col="red", lwd=5)

my raw data is too much to add as I have coefficients from a model run and a
lot of code before that but the matricies for the above variables I am
trying to plot are
> yhyp1$pe
 [1] 0.91938328 0.88005171 0.82235810 0.74124787 0.63520716 0.51090516
 [7] 0.38417025 0.27254070 0.18569395 0.12375682 0.08183003 0.05420338
[13] 0.03619331 0.02446051 0.01677548

> yhyp1$upper
 [,1]
up 0.98470376
up 0.96729674
up 0.93342185
up 0.87016432
up 0.77356024
up 0.63337489
up 0.49704477
up 0.39523107
up 0.32380653
up 0.26340188
up 0.21370693
up 0.17113476
up 0.13810301
up 0.9516
up 0.08930777

> yhyp1$lower
   [,1]
low 0.758338075
low 0.704684752
low 0.636448570
low 0.569633622
low 0.485986148
low 0.390656111
low 0.276924551
low 0.169273771
low 0.092501362
low 0.048176412
low 0.023014862
low 0.010788438
low 0.005082446
low 0.002250877
low 0.001063545

Please forgive my poor posting manners.

Joe King
206-913-2912
j...@joepking.com
"Never throughout history has a man who lived a life of ease left a name
worth remembering." --Theodore Roosevelt


-Original Message-
From: David Winsemius [mailto:dwinsem...@comcast.net] 
Sent: Friday, October 30, 2009 7:15 AM
To: Joe King
Cc: r-help@r-project.org
Subject: Re: [R] opacity under dispersion command under plotrix


On Oct 30, 2009, at 7:02 AM, Joe King wrote:

> Is there anyway to make the lines in the dispersion command come  
> forward in
> a plot and allow the fill in the dispersion parameter be transparent  
> so all
> of the lines I am using to note confidence intervals are shown?

Got code?

> ---
>
> Joe King, M.A.
>
> Ph.D. Student

-- 

David Winsemius, MD
Heritage Laboratories
West Hartford, CT

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Re: [R] Frequency

2009-11-02 Thread Joe King
sorry, I forgot to send my reply to the list, I got to remember to hit reply
all:

So I set up a dummy matrix, v1,v2,v3,v4, an datamatrix

v1 = c(5,3,4)
v2 = c(6,4,6)
v3 = c(9,7,10)
v4 = c(10,10,18)
datamatrix=c(v1,v2,v3,v4)

then do 

sort(table(datamatrix))

Joe King
206-913-2912
j...@joepking.com
"Never throughout history has a man who lived a life of ease left a name
worth remembering." --Theodore Roosevelt


-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Val
Sent: Monday, November 02, 2009 10:35 AM
To: r-help@r-project.org
Subject: [R] Frequency

BAYESIAN INFERENCES FOR MILKING TEMPERAMENT IN CANADIAN HOLSTEINS

Hi All,

I have a data  set "x"  with several variables. Sample of the data is shown
below

 V1  v2  v3   v4

   569   10

 347   10

 46   10   18



I want the frequency  of each  data point sorted by their occurrence.



Below is the output that I want

10=3

6=2

4=2

9=1

5=1

7=1

3=1

How do I do it in R?



Thanks in advance



Val

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Re: [R] problems with read.csv

2009-11-02 Thread Joe King
I use 

indata = read.csv(file.choose(),header=TRUE)

of course you can specify your file.

Joe King
206-913-2912
j...@joepking.com
"Never throughout history has a man who lived a life of ease left a name
worth remembering." --Theodore Roosevelt


-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Fang (Betty) Yang
Sent: Monday, November 02, 2009 1:10 PM
To: r-help@r-project.org
Subject: [R] problems with read.csv

Dear all,

 

I'd like to ask help on R code to get the same results as the following
Splus code:

 

 

>indata<-importData("/home/data_new.csv")

 

>indata[1:5,4]

[1] 0930 1601 1006 1032 1020

 

I tried the following R code:

 

> indata<-read.csv("/home/data_new.csv")

> indata[1:5,4]

[1]  930 1601 1006 1032 1020

 

I'd like the first one to be 0930, too.

 

Thanks in advance,

 

 

Betty

 

 

 

 


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Re: [R] Finding Largest(or smallest) values

2009-11-15 Thread Joe King
There are probably better ways but cant you subset each parameter? So create
new variables for parameter 1, 2, ... and look at the summary data for those
which will include a min and max for all variables.

Joe King
206-913-2912
j...@joepking.com
"Never throughout history has a man who lived a life of ease left a name
worth remembering." --Theodore Roosevelt

-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of alphaace
Sent: Sunday, November 15, 2009 8:54 AM
To: r-help@r-project.org
Subject: [R] Finding Largest(or smallest) values


Hi,

I am trying to find a model of best fit, with 8 parameters. As such, I have
created a table with 2^8=256 rows with every variable either in or out of
the model(denoted by 1 or 0), and for each row, I have computed the Adjusted
R^2, AIC, CP and Press. I know I can use the leaps package to find the best
model (for every number of parameters n=1...8) for the Adjusted R2 and CP,
but not for AIC and PRESS. I was wondering, if anyone has any code to say
find the minimum press when the model has 1 parameter, 2 parameters, 3
parameters, etc...

I have attached a copy of my table below for reference. Thank you for your
help!

 > DF
P X1 X2 X3 X4 X5 X6 X7 X8   Adjusted R2 AICCP PRESS
1   0  0  0  0  0  0  0  0  0  0.00  0.99464282 14.367679  95.01075
2   1  1  0  0  0  0  0  0  0  0.0246074998 -0.36362381 12.634643  93.70900
3   1  0  1  0  0  0  0  0  0  0.0382916889 -1.69172730 11.194739  92.46010
4   1  0  0  1  0  0  0  0  0 -0.0005184148  2.02713507 15.278491  96.11336
5   1  0  0  0  1  0  0  0  0 -0.002134  2.24957370 15.527913  96.38092
6   1  0  0  0  0  1  0  0  0  0.0272855281 -0.62206426 12.352850  92.64962
7   1  0  0  0  0  0  1  0  0  0.0111851503  0.92108831 14.046995  94.47172
8   1  0  0  0  0  0  0  1  0  0.0020990063  1.78090275 15.003075  94.60974
9   1  0  0  0  0  0  0  0  1 -0.0108209410  2.99012118 16.362563  97.09546
10  2  1  1  0  0  0  0  0  0  0.0810965349 -4.99889125  7.639659  89.49671
11  2  1  0  1  0  0  0  0  0  0.0266267059  0.41424802 13.308890  94.64288
12  2  0  1  1  0  0  0  0  0  0.0315413664 -0.06156976 12.797371  94.04593
13  2  1  0  0  1  0  0  0  0  0.0145736386  1.57108162 14.563375  95.37943
14  2  0  1  0  1  0  0  0  0  0.0479608482 -1.66893313 11.088428  92.39152
15  2  0  0  1  1  0  0  0  0  0.0005123888  2.90290718 16.026873  97.24004
16  2  1  0  0  0  1  0  0  0  0.0541222887 -2.27926275 10.447144  91.16842
17  2  0  1  0  0  1  0  0  0  0.0754976703 -4.42788850  8.222390  88.96712
18  2  0  0  1  0  1  0  0  0  0.0241535771  0.65277858 13.566293  93.96203
19  2  0  0  0  1  1  0  0  0  0.0275121981  0.32869589 13.216727  93.77620
20  2  1  0  0  0  0  1  0  0  0.0245589269  0.61372449 13.524104  94.06972
21  2  0  1  0  0  0  1  0  0  0.0622492592 -3.09039933  9.601287  90.89229
22  2  0  0  1  0  0  1  0  0  0.0085444331  2.14445635 15.190896  95.73424
23  2  0  0  0  1  0  1  0  0  0.0089907346  2.10213293 15.15  95.79122
24  2  0  0  0  0  1  1  0  0  0.0407860378 -0.96318114 11.835183  91.76667
25  2  1  0  0  0  0  0  1  0  0.0244877014  0.62058800 13.531518  93.36514
26  2  0  1  0  0  0  0  1  0  0.0407457114 -0.95922936 11.839381  92.16665
27  2  0  0  1  0  0  0  1  0 -0.0047937805  3.40062281 16.579140  96.5
28  2  0  0  0  1  0  0  1  0  0.0020858488  2.75480952 15.863107  95.82804
29  2  0  0  0  0  1  0  1  0  0.0248637496  0.58434515 13.492378  92.73311
30  2  0  0  0  0  0  1  1  0  0.0171446547  1.32551143 14.295783  93.74595
31  2  1  0  0  0  0  0  0  1  0.0138889013  1.63637615 14.634643  95.78017
32  2  0  1  0  0  0  0  0  1  0.0277245197  0.30817080 13.194629  94.26947
33  2  0  0  1  0  0  0  0  1 -0.0115063328  4.02650409 17.277784  98.26103
34  2  0  0  0  1  0  0  0  1 -0.0130170902  4.16679510 17.435024  98.57288
35  2  0  0  0  0  1  0  0  1  0.0193924225  1.11028937 14.061835  94.52438
36  2  0  0  0  0  0  1  0  1  0.0004693207  2.90695757 16.031355  96.66280
37  2  0  0  0  0  0  0  1  1 -0.0087026647  3.76559547 16.985978  96.73581
38  3  1  1  1  0  0  0  0  0  0.0754624308 -3.46299014  9.168628  90.98724
39  3  1  1  0  1  0  0  0  0  0.0761667614 -3.53462845  9.096127  90.47049
40  3  1  0  1  1  0  0  0  0  0.0179377080  2.21094883 15.090020  96.18373
41  3  0  1  1  1  0  0  0  0  0.0443170822 -0.34853563 12.374620  93.90532
42  3  1  1  0  0  1  0  0  0  0.1233192905 -8.45916839  4.242412  85.48181
43  3  1  0  1  0  1  0  0  0  0.0532048878 -1.22682152 11.459741  92.37654
44  3  0  1  1  0  1  0  0  0  0.0668617200 -2.59257716 10.053955  90.62446
45  3  1  0  0  1  1  0  0  0  0.0452547720 -0.44081112 12.278098  92.71992
46  3  0  1  0  1  1  0  0  0  0.0924857470 -5.20992520  7.416308  88.22170
47  3  0  0  1  1  1  0  0  0  0.0281772097  1.22570975 14.036002  94.88753
48  3  1  1  0  0  0  1  0  0  0.0890014298 -4.84971194  7.774972  89.34392
49  3  1  0  1  

[R] Hmisc and Lattice question on gridlines

2009-11-19 Thread Joe King
I have been using lattice xyplot and am quite pleased, and I can use the
type=c("b","g") to have it print gridlines into the page, yet if I want to
have a line plot with points on it, how do I get the xYplot to print
gridlines (I use Hmisc xYplot because of its bands method which allows
plotting of confidence intervals). Any suggestions? I have looked at the
panel functions but when I try it I get the gridlines but my data is gone.

 

So a simple example is below. I want to create the reference lines in the
lattice plot in the xYplot from Hmisc so I can keep the confidence intervals
filled.

 

x<-seq(1,10,1)

y<-seq(1,10,1)

ci<-y*.10

ciupper<-y+ci

cilower<-y-ci

 

xyplot(y~x, type=c("b","g"),plot.points = TRUE)#using lattice

 

xYplot(Cbind(y,cilower,ciupper)~x,col.fill="grey",plot.points =
TRUE,type=c("b"),method="filled bands")#using Hmisc

 

JOE

 


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Re: [R] Do you keep an archive of "useful" R code? and if so - how?

2009-11-22 Thread Joe King
I accidentally sent this directly to the author and didn't reply to the
whole list, I am sorry, I need to remember to hit reply all instead of reply
to the R help list, heres my message:

I keep a separate R file of code I commonly use but more generic. So if I am
making contingency tables I say:

ftable(category, category[top])

or if I am wanting to subset data:

subset2$X5<-recode(subset2$X5, "6:10=1:5")

things like that, generic code that I can refer to and include my variables
in as necessary (as you can tell the "top" mark I made in ftable isn't in
the code but reminds me how the table structures itself. Since I am a newbie
at R I am still keeping notes, I do this for importing things, also
graphics:

xyplot(value~X1,data=subset1,groups=factor(X2),
 type=c("b","g"),ylim=c(0,1),xlim=c(1,5),lwd=1,cex = 1,
 plot.points = TRUE,auto.key = list(points = TRUE,lines = TRUE, space =
"inside"),
 label.curves=FALSE,xlab = "x axis title", ylab = " y axis title ")

so it just lets me organize my codes on my local system. R wiki is ok, but
will be much better as people expand it, I am sure very soon it will grow
exponentially as a good resource. 

(as you can tell some of the code I save includes old variable names instead
of neutral ones, but easy enough to change).

Joe King
206-913-2912
j...@joepking.com
"Never throughout history has a man who lived a life of ease left a name
worth remembering." --Theodore Roosevelt


-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Tal Galili
Sent: Sunday, November 22, 2009 10:31 AM
To: Marc Schwartz
Cc: r-help@r-project.org; Barry Rowlingson; jeff.la...@noaa.gov
Subject: Re: [R] Do you keep an archive of "useful" R code? and if so - how?

Marc and Barry, many thanks for your detailed answers.

Marc -
I thank you for the links and ideas. Thanks to your advice I will look more
into SVN in the future, although it sounds on the surface to require some
learning curve, so It could take me some time to start using it.

Barry -
I am actually a blog builder in my side profession, I already built myself a
blog called:
r-statistics.com
On which I intend to put up good code I will come across.  The problem with
it though is that I don't see blogs as a good information management system.
Since on a blog one is open to the public and doesn't want to leave half
scribles of thoughts (which IS what ends up happening when managing snippets
of code).  Also, blogging is not build for easy hierarchical ordering.

The idea of a wiki is more appealing.
BTW - another suggestion I got was using MS onenote. Although it is not open
source (which is my preference as well), I understood it offers a powerful
solution.

I hope more people will share how they manage their snippets of code.


Best to all of you,
Tal




Contact
Details:---
Contact me: tal.gal...@gmail.com |  972-52-7275845
Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) |
www.r-statistics.com/ (English)

--




On Sun, Nov 22, 2009 at 8:09 PM, Marc Schwartz  wrote:

> Tal,
>
> I would still use Subversion.
>
> Think of Subversion as as an electronic filing system. You can organize
> code into project trees, with sub-folders and so forth.
>
> As you come across code snippets that you want to save, copy them to a
file
> and commit the file to a project tree or sub-folder, based upon the domain
> of functionality. Add related code snippets to the same domains. That way,
> you have related code snippets in a common area, making recall easier.
>
> The advantage of using a VCS is that you can make trackable modifications
> to the code over time, as your functional requirements change or as you
> discover bugs, etc. to existing code.
>
> In terms of a GUI, for Windows, it seems that most use Tortoise SVN:
>
>   http://tortoisesvn.net/
>
> There are cross-platform GUIs such as RapidSVN (
> http://rapidsvn.tigris.org/), but it all depends upon personal
> preferences. More links here:
>
>   http://subversion.tigris.org/links.html#all-clients
>
> There are also Subversion extensions for editors, such as Emacs, like
> psvn.el (http://www.xsteve.at/prg/vc_svn/) which enable a blending of
> functionality into environments that you may already be using, such as
ESS.
>
> Last but not least, there are also commercial variants of Subversion
> clients, which of course have a cost associated with them. These are also
> listed on the clients link above.
>
> An alternative would be to create a local wiki, the implementation
details,
> as with a Subversion repo, would be dependent upon wheth

Re: [R] reshape question

2009-11-24 Thread Joe King
What about the melt function in reshape package?

EX:

> x=sample(1:100,20,replace=T)

> x
 [1] 48 94 32 96 81 99 10 64 64 94 57 60 16 64 32 76 63  1 64  8

> y=sample(1:100,20,replace=T)

> y
 [1] 73 78 82 43 58 85 74 64 73 41 45 38 63 36 44 74  7 88 91  1

> xy=cbind(x,y)

> melt(xy)
   X1 X2 value
1   1  x48
2   2  x94
3   3  x32
4   4  x96
5   5  x81
6   6  x99
7   7  x10
8   8  x64
9   9  x64
10 10  x94
11 11  x57
12 12  x60
13 13  x16
14 14  x64
15 15  x32
16 16  x76
17 17  x63
18 18  x 1
19 19  x64
20 20  x 8
21  1  y73
22  2  y78
23  3  y82
24  4  y43
25  5  y58
26  6  y85
27  7  y74
28  8  y64
29  9  y73
30 10  y41
31 11  y45
32 12  y38
33 13  y63
34 14  y36
35 15  y44
36 16  y74
37 17  y 7
38 18  y88
39 19  y91
40 20  y 1

>
Joe King
206-913-2912
j...@joepking.com
"Never throughout history has a man who lived a life of ease left a name
worth remembering." --Theodore Roosevelt


-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of David Winsemius
Sent: Tuesday, November 24, 2009 6:43 PM
To: AC Del Re
Cc: r-help@r-project.org
Subject: Re: [R] reshape question


On Nov 24, 2009, at 8:33 PM, AC Del Re wrote:

> Hi All,
>
> I am wanting to convert a data.frame from a wide format to a long  
> format
> (with >1 variable) and am having difficulties. Any help is  
> appreciated!
>
> #current wide format
>> head(data.out2)
> id   rater.1 n.1   rater.2 n.2   rater.3 n.3   rater.4 n.4
> 11   11 0.118  79NA  NANA  NANA  NA
> 114 114 0.2478709 113NA  NANA  NANA  NA
> 12   12 0.3130655  54 0.3668242  54NA  NANA  NA
> 121 121 0.240 331NA  NANA  NANA  NA
> 122 122 0.3004164  25 0.1046278  25 0.2424871  25 0.2796937  25
> 125 125 0.1634865 190NA  NANA  NANA  NA
>
> #This is close but I would like the 'n' column to remain and for the  
> '.1' to
> drop off

I don't really understand what you want and the example solution  
throws away quite a lot of data, so consider this alternative:

data.out2 <- read.table(textConnection("id   rater.1 n.1   rater.2 n. 
2   rater.3 n.3   rater.4 n.4
11   11 0.118  79NA  NANA  NANA  NA
114 114 0.2478709 113NA  NANA  NANA  NA
12   12 0.3130655  54 0.3668242  54NA  NANA  NA
121 121 0.240 331NA  NANA  NANA  NA
122 122 0.3004164  25 0.1046278  25 0.2424871  25 0.2796937  25
125 125 0.1634865 190NA  NANA  NANA  NA"),  
header=T, stringsAsFactors=F)


data.frame(id= data.out2$id, rater=stack(data.out2[,grep("rater",  
names(data.out2))]),
   n= stack(data.out2[,grep("n", names(data.out2))]) )

data.out2.id rater.values rater.ind n.values n.ind
1110.118   rater.1   79   n.1
2   1140.2478709   rater.1  113   n.1
3120.3130655   rater.1   54   n.1
4   1210.240   rater.1  331   n.1
5   1220.3004164   rater.1   25   n.1
6   1250.1634865   rater.1  190   n.1
711   NA   rater.2   NA   n.2
8   114   NA   rater.2   NA   n.2
9120.3668242   rater.2   54   n.2
10  121   NA   rater.2   NA   n.2
11  1220.1046278   rater.2   25   n.2
12  125   NA   rater.2   NA   n.2
13   11   NA   rater.3   NA   n.3
14  114   NA   rater.3   NA   n.3
15   12   NA   rater.3   NA   n.3
16  121   NA   rater.3   NA   n.3
17  1220.2424871   rater.3   25   n.3
18  125   NA   rater.3   NA   n.3
19   11   NA   rater.4   NA   n.4
20  114   NA   rater.4   NA   n.4
21   12   NA   rater.4   NA   n.4
22  121   NA   rater.4   NA   n.4
23  1220.2796937   rater.4   25   n.4
24  125   NA   rater.4   NA   n.4

You can take what you like from what I would consider a version that  
has no loss of the original information.



>
>> data.out3<-reshape(data.out2,varying=list(names(data.out2)[-1]),
> +  idvar='id',direction='long')
>> head(data.out3)
>   id time   rater.1
> 11.1   111 0.118
> 114.1 1141 0.2478709
> 12.1   121 0.3130655
> 121.1 1211 0.240
> 122.1 1221 0.3004164
> 125.1 1251 0.1634865
>
> Ideally I would like the columns to be

[R] layers in xYplot of Hmisc

2009-11-26 Thread Joe King
In the "filled bands" part of xYplot of the Hmisc package, is there a way to
have multiple bands with multiple lines? or does it just allow one for now?

 

So I had an example bit ago had a made up line and CI, now if I wanted to
make a second line with a CI filled in can I put them on the same plot?

 

x<-seq(1,10,1)

y<-seq(1,10,1)

ci<-y*.10

ciupper<-y+ci

cilower<-y-ci

 

xYplot(Cbind(y,cilower,ciupper)~x, method="filled bands", col.fill="light
grey", type=c("b"))

 

x2<-seq(1,5,.5)

y2<-seq(1,5,.5)

ci2<-y2*.10

ciupper2<-y2+ci2

cilower2<-y2-ci2

 

xYplot(Cbind(y2,cilower2,ciupper2)~x2, method="filled bands",col.fill="light
grey", type=c("b"))

 

---

Joe King, M.A.

Ph.D. Student 

University of Washington - Seattle

206-913-2912  

j...@joepking.com

---

"Never throughout history has a man who lived a life of ease left a name
worth remembering." --Theodore Roosevelt

 


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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] Create sequence given start and end vector

2009-12-12 Thread Joe King
Also what about

c(seq(1,4,1),seq(10,15,1),seq(20,27,1))

Joe King
j...@joepking.com
"Never throughout history has a man who lived a life of ease left a name
worth remembering." --Theodore Roosevelt

-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Jorge Ivan Velez
Sent: Saturday, December 12, 2009 1:43 PM
To: Kevin Ummel
Cc: r-help@r-project.org
Subject: Re: [R] Create sequence given start and end vector

Hi Kevin,

Here is a suggestion using mapply():

start <- c(1,10,20)
end <- c(4,15,27)
do.call(c, mapply( seq, start, end))

See ?mapply and ?do.call for more information.

HTH,
Jorge


On Sat, Dec 12, 2009 at 2:27 PM, Kevin Ummel <> wrote:

> How can I create the following without the 'for' loop?
>
> start=c(1,10,20)
>
> end=c(4,15,27)
>
> out=c()
>
> for (i in 1:length(start)) {
>out=c(out,start[i]:end[i])
>}
> out
>  [1]  1  2  3  4 10 11 12 13 14 15 20 21 22 23 24 25 26 27
>
> I know there must be an easier (and, hopefully, faster) way.
>
> Many thanks in advance,
> Kevin Ummel
>
> Central European University
> Department of Environmental Science and Policy
>
> __
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>

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__
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[R] Hmisc filled bands colors

2009-12-12 Thread Joe King
Hi all, i am still using the Hmisc package and I like the filled bands part,
is there a way though to have different groups have different color of
bands, maybe a lighter version of the color of the line that is used?

 

---

Joe King, M.A.

Ph.D. Student 

University of Washington - Seattle

206-913-2912  

j...@joepking.com

---

"Never throughout history has a man who lived a life of ease left a name
worth remembering." --Theodore Roosevelt

 


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and provide commented, minimal, self-contained, reproducible code.


[R] subtitle in Hmisc xYplot

2009-12-14 Thread Joe King
Ok so I am trying to add a subtitle to my xYplot using Hmisc and I have some
dummy code of

 

x<-seq(1,10,1)

y<-rev(seq(1,10,1))

ci<-y*.10

ciupper<-y+ci

cilower<-y-ci

 

this code works fine:

 

xYplot(Cbind(y,ciupper,cilower)~x, type=c("b"),plot.points = TRUE,
method='filled bands', main='main title')

 

but when I add sub=. at the end and use this

 

xYplot(Cbind(y,ciupper,cilower)~x, type=c("b"),plot.points = TRUE,
method='filled bands', main='main title', sub='subtitle')

 

I get an error saying subscript out of bounds, any help?

 

---

Joe King, M.A.

Ph.D. Student 

University of Washington - Seattle

206-913-2912  

j...@joepking.com

---

"Never throughout history has a man who lived a life of ease left a name
worth remembering." --Theodore Roosevelt

 


[[alternative HTML version deleted]]

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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] "Object is not a matrix" Error

2009-12-20 Thread Joe King
When you imported did you not import the headers?

Joe King
206-913-2912
j...@joepking.com
"Never throughout history has a man who lived a life of ease left a name
worth remembering." --Theodore Roosevelt

-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of jim holtman
Sent: Sunday, December 20, 2009 3:11 PM
To: John Paul Telthorst
Cc: r-help@r-project.org
Subject: Re: [R] "Object is not a matrix" Error

Where is the object 'write'?  SHouldn't you be using:

 lm(visits ~ (day.f))


On Sun, Dec 20, 2009 at 5:59 PM, John Paul Telthorst
wrote:

> I'm trying to follow this guide here:
> http://www.ats.ucla.edu/stat/r/modules/dummy_vars.htm
>
> In which I'm creating categorical variables using the factor function.
>
> I am able to go through the example listed above and have everything work,
> however, when I try to input my own numbers, I get an error.  I input the
> following:
>
>
> > hits = read.csv(file.choose())
>
> > attach(hits)
>
> > day.f <- factor(day)
>
> > lm(write ~ (day.f))
>
> lm(write ~ (day.f))
>
> Error in model.frame.default(formula = write ~ (day.f), drop.unused.levels
> =
> > TRUE) :
> >   object is not a matrix
> >
>
> So I import "hits = read.csv(file.choose())" a .csv file, which has the
> columns "visits" and "day" where "visits" is the number of hits to a
> website, and "day" is a number 1-7, for example 1 corresponds to Sunday
and
> 7 corresponds to Saturday.  I understand that the day variable needs to be
> a
> categorical variable, and I'm trying to use the factor function to do
this.
>  I would like to be able to run a regression that will correlate the day
> with the number of hits.
>
> Any help would be much appreciated.
>
>[[alternative HTML version deleted]]
>
> __
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
>
http://www.R-project.org/posting-guide.html<http://www.r-project.org/posting
-guide.html>
> and provide commented, minimal, self-contained, reproducible code.
>



-- 
Jim Holtman
Cincinnati, OH
+1 513 646 9390

What is the problem that you are trying to solve?

[[alternative HTML version deleted]]

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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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Re: [R] Signif. codes

2009-12-20 Thread Joe King
There will always be uncertainty in your estimates so you don't have 0
percent chance of being wrong, but remember that's your intercept, your
regressors are not significant. Although you can say it is less than ..05, I
mean if its significant at .001 (or something like that), that's
less than .05, so its not unethical to say p < .05, but it sounds like you
need to understand the regression model a little better.

Joe King
206-913-2912
j...@joepking.com
"Never throughout history has a man who lived a life of ease left a name
worth remembering." --Theodore Roosevelt


-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of John Paul Telthorst
Sent: Sunday, December 20, 2009 10:13 PM
To: r-help@r-project.org
Subject: [R] Signif. codes

My question is about the "Signif. codes" and the p-value, specifically, the
output when I run

summary(nameofregression.lm)


So you get this little key:

Signif. codes:  0 *** 0.001 ** 0.01 * 0.05 . 0.1   1

And on a regression I ran, next to the intercept data, I get '***'

Coefficients:
>
> Estimate Std. Error t value Pr(>|t|)
>
> (Intercept)  7.956520.59993  13.262   <2e-16 ***
>
> day.f2  -0.043480.84843  -0.0510.959
>
> day.f3  -0.130430.84843  -0.1540.878
>
> day.f4  -0.217390.84843  -0.2560.798
>
> day.f5   0.021740.84843   0.0260.980
>
> day.f6  -0.152170.84843  -0.1790.858
>
> day.f7   0.149860.84390   0.1780.859
>
>
Does this mean that these numbers have a 0% chance of being wrong?  Is there
a way to change this to the .05 level of significance?

Thanks,
John

[[alternative HTML version deleted]]

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Re: [R] Signif. codes

2009-12-20 Thread Joe King
No, so the probability means that's the probability of getting that data by
chance, so a p-value of .9997 means there is a .9997 probability that the
data could be acquired by chance. This is a very simplistic view and you
should study the regression model better.

 

Joe King

206-913-2912

j...@joepking.com

"Never throughout history has a man who lived a life of ease left a name
worth remembering." --Theodore Roosevelt

 

From: John Paul Telthorst [mailto:jpteltho...@gmail.com] 
Sent: Sunday, December 20, 2009 10:36 PM
To: Joe King
Subject: Re: [R] Signif. codes

 

Thanks for the reply, I definitely do need to understand the regression
model better.  I got a p-value of .9997, so that would be > .05?  I guess
I'm confused about the significance part you talked about.

 

John

On Mon, Dec 21, 2009 at 12:27 AM, Joe King  wrote:

There will always be uncertainty in your estimates so you don't have 0
percent chance of being wrong, but remember that's your intercept, your
regressors are not significant. Although you can say it is less than ..05, I
mean if its significant at .001 (or something like that), that's
less than .05, so its not unethical to say p < .05, but it sounds like you
need to understand the regression model a little better. Joe King
206-913-2912 j...@joepking.com "Never throughout history has a man who lived a
life of ease left a name worth remembering." --Theodore Roosevelt
-Original Message- From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of John Paul Telthorst Sent:
Sunday, December 20, 2009 10:13 PM To: r-help@r-project.org Subject: [R]
Signif. codes My question is about the "Signif. codes" and the p-value,
specifically, the output when I run summary(nameofregression.lm) So you get
this little key: Signif. codes:  0   0.001   0.01   0.05   0.1  And on a
regression I ran, next to the intercept data, I get '***' Coefficients: >
Estimate Std. Error t value Pr(>|t|) > (Intercept)  7.956520.59993
13.262   <2e-16 *** > day.f2  -0.043480.84843  -0.0510.959 >
day.f3  -0.130430.84843  -0.1540.878 > day.f4  -0.21739
0.84843  -0.2560.798 > day.f5   0.021740.84843   0.0260.980
> day.f6  -0.152170.84843  -0.1790.858 > day.f7   0.14986
0.84390   0.1780.859 Does this mean that these numbers have a 0% chance
of being wrong?  Is there a way to change this to the .05 level of
significance? Thanks, John [[alternative HTML version deleted]]
__ R-help@r-project.org mailing
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guide http://www.R-project.org/posting-guide.html and provide commented,
minimal, self-contained, reproducible code. 




-- 
John Telthorst, MHRIR
University of Illinois Alumnus


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and provide commented, minimal, self-contained, reproducible code.


Re: [R] Is SEM package of R suitable for sem analysis

2009-12-26 Thread Joe King
I am going to take SEM this next quarter in my doctoral program. My
suggestion is to use the program your professor suggests and try to
re-create your models in R using the SEM package. We are not going to use
AMOS though we use EQS, and another prof on campus who teaches it in a
different department uses LISREL, so since SEM hasn't been implemented in
most commercial software and you need specialty software for it, it may be
best to know several different software programs if you want to do SEM type
work. I do have a feeling since R is growing so rapidly it wont take time
for people in the community to create packages or develop existing packages
equal to or greater than commercial software! LONG LIVE R :)

Joe King
206-913-2912
j...@joepking.com
"Never throughout history has a man who lived a life of ease left a name
worth remembering." --Theodore Roosevelt


-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Reeyarn_???_10928113
Sent: Saturday, December 26, 2009 3:50 AM
To: R-help@r-project.org
Subject: [R] Is SEM package of R suitable for sem analysis

Dears,

I'm a college student and In doing my statistics homework.

I use R with SEM package as my tool for sem analysis,
but my teacher told me AMOS is more suitable for such analysis.

Could someone help tell me whether it is true
that some commercial software is better accepted in academic fields?

Sorry if I should not post such topics here.

-- 
Best Regards,
Reeyarn T. Lee

Accounting Dept, Guanghua School of Management,
Peking University, Beijing, P.R. China

__
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and provide commented, minimal, self-contained, reproducible code.

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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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Re: [R] Is SEM package of R suitable for sem analysis

2009-12-26 Thread Joe King
Your welcome, I wanted to say I agree with Bruno that the comparative
software is very expensive, even more prohibitively so for students and even
though MPlus is good I think R will catch up rapidly and even overtake those
as people who use these modeling techniques become more integrated into the
R community.

Joe King
206-913-2912
j...@joepking.com
"Never throughout history has a man who lived a life of ease left a name
worth remembering." --Theodore Roosevelt


-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Reeyarn_???_10928113
Sent: Saturday, December 26, 2009 6:27 PM
To: R-help@r-project.org
Subject: Re: [R] Is SEM package of R suitable for sem analysis

Dear Bruno and Joe,

Thanks for advising!


Reeyarn

On Sat, Dec 26, 2009 at 9:32 PM, Bruno Falissard 
wrote:

> A few years ago it could have been true, but now the package has improved
> (especially with the bootstrap procedure).
> At the moment there is no argument to recommend AMOS.

On Sun, Dec 27, 2009 at 12:30 AM, Joe King  wrote:

> I am going to take SEM this next quarter in my doctoral program. My
> suggestion is to use the program your professor suggests and try to
> re-create your models in R using the SEM package.

__
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[R] anova help

2009-02-15 Thread Joe King
Hi all, I am trying to run a two factor anova, but one of the factors is a
random factor, now I am also running in SPSS and it seems its dividing by
the wrong term to get the appropriate F term. here is my data. In SPSS the F
scores about double the ones in R, how can I specify one of my factors as a
random factor or change it to where it does the right model fitting? I am
using the lm command instead of glm. I am new to R so this might seem basic.

 

Joe King, M.A.
 <mailto:j...@joepking.com> j...@joepking.com

"Never give in, never give in, never; never; never; never - in nothing,
great or small, large or petty - never give in except to convictions of
honor and good sense" - Winston Churchill

 

"You have enemies? Good. That means you've stood up for something, sometime
in your life." - Winston Churchill

 


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Re: [R] anova help

2009-02-15 Thread Joe King
Ok well heres my data, with the second variable (B variable) being the
random variable and the other fixed. Although the F values are about half of
what SPSS puts out.

 

My code is anova(lm(dependentrandom~typemusic+typemusic*musicselection))

 

This is just dummy data for a class but I am trying to use the data I am
running in SPSS to learn R. I am also in an R class but we are not going to
learn ANOVA.

 

Joe King, M.A.
 <mailto:j...@joepking.com> j...@joepking.com

"Never give in, never give in, never; never; never; never - in nothing,
great or small, large or petty - never give in except to convictions of
honor and good sense" - Winston Churchill

 

"You have enemies? Good. That means you've stood up for something, sometime
in your life." - Winston Churchill

 

From: Tal Galili [mailto:tal.gal...@gmail.com] 
Sent: Sunday, February 15, 2009 10:25 AM
To: Joe King
Cc: r-help@r-project.org
Subject: Re: [R] anova help

 

Hi Joe,

you might want to have a look at the nlme package with the lme command.

Another option is the more advanced lmer package.

 

Lastly, you could have a look at the ?aov command, and notice the option of
using the +Error() term (but that would only work for balanced design cases,
so I've heard, so be aware)

 

Tal

 

 

On Sat, Feb 14, 2009 at 8:46 PM, Joe King  wrote:

Hi all, I am trying to run a two factor anova, but one of the factors is a
random factor, now I am also running in SPSS and it seems its dividing by
the wrong term to get the appropriate F term. here is my data. In SPSS the F
scores about double the ones in R, how can I specify one of my factors as a
random factor or change it to where it does the right model fitting? I am
using the lm command instead of glm. I am new to R so this might seem basic.



Joe King, M.A.
 <mailto:j...@joepking.com> j...@joepking.com

"Never give in, never give in, never; never; never; never - in nothing,
great or small, large or petty - never give in except to convictions of
honor and good sense" - Winston Churchill



"You have enemies? Good. That means you've stood up for something, sometime
in your life." - Winston Churchill




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-- 
--


My contact information:
Tal Galili
Phone number: 972-50-3373767
FaceBook: Tal Galili
My Blogs:
www.talgalili.com
www.biostatistics.co.il



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