curses & disable readline & replace stdin
Hi ! I'd like to init curses and still have working Python interactive command line. I found that you can replace stdin/stdout/stderr like this: #!/usr/bin/python -i import curses import sys import atexit # this doesn't help, anyway #del sys.modules['readline'] # global variable (curses window) stdscr = None class FakeStdIO(object): def write(self, str): global stdscr stdscr.addstr(str) stdscr.refresh() def readline(self): print "$ ", return stdscr.getstr() stdscr = curses.initscr() atexit.register(curses.endwin) curses.echo() f = FakeStdIO() sys.stdin = f sys.stdout = f sys.stderr = f print 'Hello, curses !'# <-- this works l = sys.stdin.readline() # <-- this also works fine # <-- interactive Python prompt doesn't echo imput It looks that '>>>' prompt is using the readline module, which is not using sys.stdin at all. Q: Can you prevent python interpreter to use readline module (even when it is available), *without* recompiling python ? I think it should be possible to write a module in C to access Python internals. But can you do it "from python" ? The other option is to make readline somehow work with curses. This is however not what I intended. Platform: Linux Mandrake, Python 2.3.5 Thanks, BranoZ -- http://mail.python.org/mailman/listinfo/python-list
Re: looking for way to include many times some .py code from another python code
On Tuesday 08 March 2005 12:41, Martin MOKREJŠ wrote:
> cat somefile.py
> a = 222
> b = 111
> c = 9
>
> cat anotherfile.py
>
> def a():
> include somefile
> postprocess(a)
What about :
def a():
exec open('somefile.py')
postprocess(a)
You can even use the optional dictionary parameter:
class klass(object):
pass
a = klass()
exec open('somefile.py') in a.__dict__
print a.a, a.b, a.c
222 111 9
Cheers,
BranoZ
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Embeding Py: failed to instantiate a class
Hi !
I need to import a module and create an instance
of a class from that module (in C).
import mod
o = mod.klass()
(mod.klass is a subclass of tuple)
When I receive a class object from the module..
module = PyImport_ImportModule("mod")
cls = PyObject_GetAttrString(module, "klass")
..it fails the PyClass_Check(cls) check.
Some classes pass the check, like:
class test1:
pass
class test3(test1):
pass
but most don't. It is enough to subclass
a buildin type. E.g. this class fails the check:
class test2(object):
pass
Q: Do I need to initialize the class object before
using ? How ?
I have found similar questions in this group, but
no "do-it-this-way" answer. It looks that new-style
classes have a different C API semantic than old ones.
To rephrase my question:
Q: Can you give an example code of creating an instance
of new-style class ?
Thanks,
BranoZ
PS: Below are some example code used to test it.
--- mod.py ---
class test1:
pass
class test2(object):
pass
class test3(test1):
pass
--- main.c ---
#include
static PyObject *module = NULL;
void check(char *name) {
PyObject *cls = NULL;
printf("%s - ", name);
if ((cls=PyObject_GetAttrString(module, name)) == NULL) {
PyErr_Print();
return;
}
PyObject_Print(cls, stdout, 0);
if (!PyClass_Check(cls))
printf(" - not a class!!\n");
else
printf(" - is a class.\n");
}
int main(int argc, char *argv[]) {
Py_Initialize();
if ((module=PyImport_ImportModule("mod")) == NULL) {
PyErr_Print();
return -1;
}
check("test1");
check("test2");
check("test3");
Py_Main(argc, argv);
Py_Finalize();
}
--- output ---
$ ./main
test1 - - is a class.
test2 - - not a class!!
test3 - - is a class.
Python 2.3 (#2, Feb 9 2005, 13:41:20)
[GCC 3.3.1 (Mandrake Linux 9.2 3.3.1-2mdk)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import mod
>>> mod.test1
>>> mod.test2
>>> mod.test1()
>>> mod.test2()
>>>
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Embeding Py: failed to instantiate a class
Hi !
I need to import a module and create an instance
of a class from that module (in C).
import mod
o = mod.klass()
(mod.klass is a subclass of tuple)
When I receive a class object from the module..
module = PyImport_ImportModule("mod")
cls = PyObject_GetAttrString(module, "klass")
..it fails the PyClass_Check(cls) check.
Some classes pass the check, like:
class test1:
pass
class test3(test1):
pass
but most don't. It is enough to subclass
a buildin type. E.g. this class fails the check:
class test2(object):
pass
Q: Do I need to initialize the class object in
some way ? How ?
Thanks,
BranoZ
PS: Below are some example code used to test it.
--- mod.py ---
class test1:
pass
class test2(object):
pass
class test3(test1):
pass
--- main.c ---
#include
static PyObject *module = NULL;
void check(char *name) {
PyObject *cls = NULL;
printf("%s - ", name);
if ((cls=PyObject_GetAttrString(module, name)) == NULL) {
PyErr_Print();
return;
}
PyObject_Print(cls, stdout, 0);
if (!PyClass_Check(cls))
printf(" - not a class!!\n");
else
printf(" - is a class.\n");
}
int main(int argc, char *argv[]) {
Py_Initialize();
if ((module=PyImport_ImportModule("mod")) == NULL) {
PyErr_Print();
return -1;
}
check("test1");
check("test2");
check("test3");
Py_Main(argc, argv);
Py_Finalize();
}
--- output ---
$ ./main
test1 - - is a class.
test2 - - not a class!!
test3 - - is a class.
Python 2.3 (#2, Feb 9 2005, 13:41:20)
[GCC 3.3.1 (Mandrake Linux 9.2 3.3.1-2mdk)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import mod
>>> mod.test1
>>> mod.test2
>>> mod.test1()
>>> mod.test2()
>>>
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execfile() on file subclass or string
Hi !
I have a python script represented by a string.
I need to execute it in a context. 'exec' does
the job, but doesn't display the filename in
tracebacks. 'execfile' is displaying the filename
but it can only exec a script in a filesystem.
I have tried:
- to give exec a filename, like:
exec script_content in dict({'__file__':'bla.py'})
=> didn't work (neighter with __name__)
- create an in-memory file subclassing 'file'
class memfile(file):
..
def read(self)..
=> also pointless as 'execfile' doesn't accept a file
only a filename
Can you help me ?
The only problem I need to resolve is that I don't see
the script name in tracebacks.
Thanks,
BranoZ
PS: The script didn't came from the filesystem, but I know
it's content and a name.
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Re: embedded python example: PyString_FromString doesnt work?
Hi David !
I cannot see anything wrong on your code. So, I'm posting my working
example.
Hint: try to determine, why it is returning NULL (the PyErr_Print()
call)
BranoZ
#include
int
main(int argc, char *argv[]) {
PyObject *s;
int ret;
if (argc < 2)
return -1;
Py_Initialize();
s = PyString_FromString(argv[1]);
if (s == NULL) {
PyErr_Print();
return -1;
}
ret = PyObject_Print(s, stdout, 0);
Py_XDECREF(s);
if (ret < 0) {
PyErr_Print();
return -1;
}
return 0;
}
$ cc test_String.c -o test_String -I /usr/include/python2.3 -lpython2.3
$ ./test_String
$ ./test_String hello
'hello'
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Re: exec src in {}, {} strangeness
As Greg pointed..
g = {}
exec open('t.py').read() in g, g
is what you want.
But you can write it also this way:
exec open('t.py').read() in {}
because if you specify only globals, the same
dictionary is also used for locals. (locals() is
used as a default only if you don't specify globals)
OR
explicitly move class Foo to globals
t.py contains:
globals Foo
class Foo: pass
class Bar:
f = Foo
(Should work. I haven't tried it, though)
BranoZ
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Re: execfile() on file subclass or string
> exec compile("code", "filename", "exec")
Thanks for the tip!
Works great!
BranoZ
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Re: embedded python example: PyString_FromString doesnt work?
> wierd. does: http://www.python.org/doc/2.3.2/ext/pure-embedding.html work > for you ? Yes. It does. > ./test_String script1.py multiply 4 5 Don't run it with the ".py" suffix. The argv[1] is a module name, not a filename.. Even if you do, it may not find the module. Depending of what you have in PYTHONPATH. Try also: export PYTHONPATH=. > I believe you have to call Py_SetProgramName before Py_Initialize, Yes. This is another way to affect the search path. BranoZ -- http://mail.python.org/mailman/listinfo/python-list
ignoring keywords on func. call
Hi !
If I define 'f' like this
def f(a):
print a
then, the call with keywords
f(1, optional=2)
fails. I have to change 'f' to
def f(a, **kwrds):
print a
to ignore optional parameters.
BUT..
Q: Can you call 'f' with keywords that will be
ignored, without changing 'f's definition ?
I would like to avoid code like this:
k = {}
k['optional'] = 2
try:
f(1, **k)
except TypeError:
f(1)
Also, the problem is that I don't know if the TypeError
was caused by calling 'f' with keywords or somewhere
"inside" f.
You can also say that I need to specify optional parameters
on caller side (not called side).
BranoZ
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Re: ignoring keywords on func. call
> > Q: Can you call 'f' with keywords that will be > > ignored, without changing 'f's definition ? > > no. OK. Thank you for an answer. > what's the use case? I have extended the dict class, so that my __getitem__ accepts an optional parameter class MyTree(dict): def __getitem__(self, key, **k): .. def lookup(self, seq): node = self for k in seq: node = node.__getitem__(k, someoption=True) lookup takes a sequence of keys to lookup in hierarchy of Tree nodes. But I would like lookup to work also on objects that are not subclasses of Tree. It has to work on any dict-like class. If a user defines a custom class, he will intuitively define __getitem__ like this: def MyNode(??): def __getitem__(self, key): .. I could check in 'lookup' if isinstance(node, Tree): node = node.__getitem__(k, someoption=True) else: node = node.__getitem__(k) But it still doesn't guarantee that __getitem__ accepts keywords. (What if somebody will extend the Tree class and overlook the definition of __getitem__ and define a "classic" one) BranoZ -- http://mail.python.org/mailman/listinfo/python-list
