> > Q: Can you call 'f' with keywords that will be
> > ignored, without changing 'f's definition ?
>
> no.
OK. Thank you for an answer.
> what's the use case?
I have extended the dict class, so that my __getitem__ accepts an
optional parameter
class MyTree(dict):
def __getitem__(self, key, **k):
..
def lookup(self, seq):
node = self
for k in seq:
node = node.__getitem__(k, someoption=True)
lookup takes a sequence of keys to lookup in hierarchy
of Tree nodes. But I would like lookup to work also on objects
that are not subclasses of Tree. It has to work on any dict-like class.
If a user defines a custom class, he will intuitively define
__getitem__
like this:
def MyNode(??):
def __getitem__(self, key):
..
I could check in 'lookup'
if isinstance(node, Tree):
node = node.__getitem__(k, someoption=True)
else:
node = node.__getitem__(k)
But it still doesn't guarantee that __getitem__ accepts keywords.
(What if somebody will extend the Tree class and overlook the
definition of __getitem__ and define a "classic" one)
BranoZ
--
http://mail.python.org/mailman/listinfo/python-list
