To Change A Pdf Ebook To Kindle
PDF Converter for Mac is a fantastic and easyto-use instrument for converting PDF documents on Macos. Macintosh PDF Converter can pdf to excel converter to Word, Shine, PowerPoint, EPUB, Text format for Mac. With PDF Converter Mac, the PDF documents, select certain websites of the PDF files etc that are huge can be also previewed by Mac users. https://sourceforge.net/projects/pdftoexcelconverter/ -- View this message in context: http://python.6.x6.nabble.com/To-Change-A-Pdf-Ebook-To-Kindle-tp5090337.html Sent from the Python - python-list mailing list archive at Nabble.com. -- https://mail.python.org/mailman/listinfo/python-list
Re: fibonacci series what Iam is missing ?
On Tuesday, March 24, 2015 at 6:54:20 AM UTC+8, Terry Reedy wrote: > On 3/23/2015 2:44 PM, Dave Angel wrote: > > > ## Example 2: Using recursion with caching > > cache = [0, 1] > > def fib4(n): > > if len(cache) <= n: > > value = fib4(n-2) + fib4(n-1) > > cache.append(value) > > return cache[n] > > > > This one takes less than a millisecond up to n=200 or so. > > Iteration with caching, using a mutable default arg to keep the cache > private and the function self-contained. This should be faster. > > def fib(n, _cache=[0,1]): > '''Return fibonacci(n). > > _cache is initialized with base values and augmented as needed. > ''' > for k in range(len(_cache), n+1): > _cache.append(_cache[k-2] + _cache[k-1]) > return _cache[n] > > print(fib(1), fib(3), fib(6), fib(5)) > # 1 2 8 5 > > Either way, the pattern works with any matched pair of base value list > and recurrence relation where f(n), n a count, depends on one or more > f(k), k < n. 'Matched' means that the base value list is as least as > long as the maximum value of n - k. For fib, the length and max are both 2. > > -- > Terry Jan Reedy How about adding a new type of numbers of the form: (a+sqrt(r0)+ swrt(r1))/b with proper operations, and then one can compute the Fib term directly in a field. -- https://mail.python.org/mailman/listinfo/python-list
Re: fibonacci series what Iam is missing ?
Chris Angelico wrote: Commenting is like dieting. You can always start tomorrow. I've been meaning to become a procrastinator, but I think I'll start tomorrow. In the meantime, since we seem to be having a fibbing competition, here's my contribution, that uses neither recursion nor (explicit) iteration: from numpy import array, dot a = array([[0,1],[1,1]]) b = array([0,1]) def fib(n): return reduce(dot,[a]*n+[b])[1] for i in range(10): print(fib(i)) -- Greg -- https://mail.python.org/mailman/listinfo/python-list
ANN: eGenix pyOpenSSL Distribution 0.13.8
ANNOUNCING eGenix.com pyOpenSSL Distribution Version 0.13.8 An easy-to-install and easy-to-use distribution of the pyOpenSSL Python interface for OpenSSL - available for Windows, Mac OS X and Unix platforms This announcement is also available on our web-site for online reading: http://www.egenix.com/company/news/eGenix-pyOpenSSL-Distribution-0.13.8.html INTRODUCTION The eGenix.com pyOpenSSL Distribution includes everything you need to get started with SSL in Python. It comes with an easy-to-use installer that includes the most recent OpenSSL library versions in pre-compiled form, making your application independent of OS provided OpenSSL libraries: http://www.egenix.com/products/python/pyOpenSSL/ pyOpenSSL is an open-source Python add-on that allows writing SSL/TLS- aware network applications as well as certificate management tools: https://launchpad.net/pyopenssl/ OpenSSL is an open-source implementation of the SSL/TLS protocol: http://www.openssl.org/ NEWS This new release of the eGenix.com pyOpenSSL Distribution includes the following updates: New in eGenix pyOpenSSL --- * Added FreeBSD as supported platform. * Updated the Mozilla CA root bundle to version 2015-02-19. New in OpenSSL -- * Updated included OpenSSL libraries from OpenSSL 1.0.1k to 1.0.1m. We had skipped OpenSSL 1.0.1l, since the 1.0.1l release only included a patch for Windows we had already included in our 0.13.7 release. See https://www.openssl.org/news/secadv_20150319.txt for a complete list of changes. The following fixes are relevant for pyOpenSSL applications: - CVE-2015-0286: Segmentation fault in ASN1_TYPE_cmp. - CVE-2015-0287: ASN.1 structure reuse memory corruption. - CVE-2015-0289: PKCS#7 NULL pointer dereference. - CVE-2015-0292: A vulnerability existed in previous versions of OpenSSL related to the processing of base64 encoded data. Any code path that reads base64 data from an untrusted source could be affected (such as the PEM processing routines). Already fixed in OpenSSL 1.0.1h, but wasn't listed, so repeated here for completeness. - CVE-2015-0293: Denial-of-Service (DoS) via reachable assert in SSLv2 servers. - CVE-2015-0209: Use After Free following d2i_ECPrivatekey error. A malformed EC private key file consumed via the d2i_ECPrivateKey function could cause a use after free condition. * The FREAK Attack (CVE-2015-0204) patch was already available in our last release with OpenSSL 1.0.1k. Please see the product changelog for the full set of changes: http://www.egenix.com/products/python/pyOpenSSL/changelog.html pyOpenSSL / OpenSSL Binaries Included - In addition to providing sources, we make binaries available that include both pyOpenSSL and the necessary OpenSSL libraries for all supported platforms: Windows, Linux, Mac OS X and now FreeBSD, for x86 and x64. To simplify installation, we have uploaded a web installer to PyPI which will automatically choose the right binary for your platform, so a simple pip install egenix-pyopenssl will get you the package with OpenSSL libraries installed. Please see our installation instructions for details: http://www.egenix.com/products/python/pyOpenSSL/#Installation We have also added .egg-file distribution versions of our eGenix.com pyOpenSSL Distribution for Windows, Linux and Mac OS X to the available download options. These make setups using e.g. zc.buildout and other egg-file based installers a lot easier. DOWNLOADS The download archives and instructions for installing the package can be found at: http://www.egenix.com/products/python/pyOpenSSL/ UPGRADING Before installing this version of pyOpenSSL, please make sure that you uninstall any previously installed pyOpenSSL version. Otherwise, you could end up not using the included OpenSSL libs. ___ SUPPORT Commercial support for these packages is available from eGenix.com. Please see http://www.egenix.com/services/support/ for details about our support offerings. MORE INFORMATION For more information about the eGenix pyOpenSSL Distribution, licensing and download instructions, please visit our web-site or write to sa...@egenix.com. Enjoy, -- Marc-Andre Lemburg eGenix.com Professional Python Services directly from the Source
module attributes and docstrings
Reading PEP 257 and 258 I got the impression that I could document module attributes and these would be available in the __doc__ attribute of the object. So things like the one below are something I got used to do, but that don't work after all, as I learned today: value_factory = lambda _, row: row[0] """Row factory. To be used with single-column queries.""" There are other things I could possibly do, like turning that lambda into a function, or document attributes in the module docstring. They are fair responses. But did I read docstring extraction rules in PEP 258 wrong by assuming that the above example would make into the __doc__ attribute? And if so, short of documenting attributes in the module docstring, is there another way I can document individual attributes? -- https://mail.python.org/mailman/listinfo/python-list
Re: module attributes and docstrings
On Tue, Mar 24, 2015 at 7:55 PM, Mario Figueiredo wrote: > So things like the one below are something I got used to do, but that > don't work after all, as I learned today: > > value_factory = lambda _, row: row[0] > """Row factory. To be used with single-column queries.""" > > There are other things I could possibly do, like turning that lambda > into a function, or document attributes in the module docstring. They > are fair responses. They certainly are. Any time you assign a lambda function directly to a simple name, it's probably worth replacing with a def function: def value_factory(_, row): """Row factory. To be used with single-column queries.""" return row[0] (Though I'd be inclined to give the first parameter a proper name here) ChrisA -- https://mail.python.org/mailman/listinfo/python-list
Re: module attributes and docstrings
On Tue, 24 Mar 2015 07:55 pm, Mario Figueiredo wrote: > Reading PEP 257 and 258 I got the impression that I could document > module attributes and these would be available in the __doc__ > attribute of the object. PEP 258 is rejected, so you can't take that as definitive. PEP 257 has this definition very early in the document: A docstring is a string literal that occurs as the first statement in a module, function, class, or method definition. Nothing there about documenting arbitrary attributes. The PEP does go on to say: String literals occurring elsewhere in Python code may also act as documentation. They are not recognized by the Python bytecode compiler and are not accessible as runtime object attributes (i.e. not assigned to __doc__ ), but two types of extra docstrings may be extracted by software tools: ... so if I write this: class K: x = something() """Documentation for x""" then the string *may* be extracted by certain third-party tools, but it will not be recognised as a docstring by the Python interpreter and will not be available as the __doc__ attribute of K.x. > So things like the one below are something I got used to do, but that > don't work after all, as I learned today: > > value_factory = lambda _, row: row[0] > """Row factory. To be used with single-column queries.""" > > There are other things I could possibly do, like turning that lambda > into a function, or document attributes in the module docstring. They > are fair responses. For the record, the lambda is already a function. lambda is just an alternative syntax for creating functions, not a different kind of object. > But did I read docstring extraction rules in PEP 258 wrong by assuming > that the above example would make into the __doc__ attribute? And if > so, short of documenting attributes in the module docstring, is there > another way I can document individual attributes? In a word, no. Even if there was support from the compiler to extract the docstring, where would it be stored? Consider: spam = None """Spammy goodness.""" eggs = None """Scrambled, not fried.""" There's only one None object, and even if it could take a docstring (and it can't), which docstring would it get? Presumably the second, which would make help(spam) confusing, but when we say eggs = 23 the docstring would disappear too. Python's data model is not compatible with the idea of associating docstrings with arbitrary attributes or variables. The docstring has to be associated with an object, and only certain objects at that. That applies to documentation which is introspectable at runtime. But of course you can do anything you like by parsing the source code! It may be that the docutils library will parse the source code and extract docstrings, associating them to their variable or attribute. If not, perhaps some other third-party library, or you can write your own. -- Steven -- https://mail.python.org/mailman/listinfo/python-list
Monkey patch an entire file in a python package
This question is about python 2.7 on Windows 7 I am trying to use multiprocessing with freeze. It appears there is some bug when using multiprocessing on freezed python code on windows platforms. There is this patch which made its way to python 3.2, and works in 2.7: http://bugs.python.org/file20603/issue10845_mitigation.diff I would like to monkey patch it. Problem is, this patch is for "forking.py", used by multiprocessing.Pools Multiprocessing is using forking.py to launch processes. I would like to monkey patch this way : import multiprocessing import multiprocessing_fixed multiprocessing_fixed: import multiprocessing.forking as mpf def prepare(data): [include fixed code for this method] mpf.prepare = prepare_pyz It's not working because forking.py is launched like a python module. How to solve this problem ? Thanks -- https://mail.python.org/mailman/listinfo/python-list
Re: Monkey patch an entire file in a python package
On Tue, Mar 24, 2015 at 10:50 PM, wrote: > I am trying to use multiprocessing with freeze. It appears there is some bug > when using multiprocessing on freezed python code on windows platforms. There > is this patch which made its way to python 3.2, and works in 2.7: > > http://bugs.python.org/file20603/issue10845_mitigation.diff > > I would like to monkey patch it. Do you have to monkey-patch at run-time? It might be better to simply patch your Python installation once, and then have the change deployed globally. Given that it was applied to 3.2, I doubt it's going to break much, so you can probably afford to just edit the file and have done with it. Alternatively, you may be able to put your own forking.py earlier in PYTHONPATH, and thus shadow the stdlib module. That might require you to shadow all of multiprocessing, though. ChrisA -- https://mail.python.org/mailman/listinfo/python-list
Re: To Change A Pdf Ebook To Kindle
On Tue, 24 Mar 2015 00:05:46 -0700, jeffreyciross wrote: > PDF Converter for Mac is a fantastic and easyto-use instrument for > converting PDF documents on Macos. Macintosh PDF Converter can pdf to > excel converter to Word, Shine, PowerPoint, EPUB, Text format for Mac. > With PDF Converter Mac, the PDF documents, select certain websites of > the PDF files etc that are huge can be also previewed by Mac users. > > https://sourceforge.net/projects/pdftoexcelconverter/ Calibre does a very god job as well. -- Most people want either less corruption or more of a chance to participate in it. -- https://mail.python.org/mailman/listinfo/python-list
Re: Monkey patch an entire file in a python package
Le mardi 24 mars 2015 13:11:33 UTC+1, Chris Angelico a écrit : > On Tue, Mar 24, 2015 at 10:50 PM, wrote: > > I am trying to use multiprocessing with freeze. It appears there is some > > bug when using multiprocessing on freezed python code on windows platforms. > > There is this patch which made its way to python 3.2, and works in 2.7: > > > > http://bugs.python.org/file20603/issue10845_mitigation.diff > > > > I would like to monkey patch it. > > Do you have to monkey-patch at run-time? It might be better to simply > patch your Python installation once, and then have the change deployed > globally. Given that it was applied to 3.2, I doubt it's going to > break much, so you can probably afford to just edit the file and have > done with it. > > Alternatively, you may be able to put your own forking.py earlier in > PYTHONPATH, and thus shadow the stdlib module. That might require you > to shadow all of multiprocessing, though. > > ChrisA Unfortunately, I would need to do it at runtime. I will look into the PYTHONPATH idea, thanks -- https://mail.python.org/mailman/listinfo/python-list
Re: fibonacci series what Iam is missing ?
On Tue, Mar 24, 2015 at 5:41 AM, Steven D'Aprano wrote: > Python does not automatically print all return statements. If you want it to > print the intermediate values produced, you will need to add print before > each return: > > > py> def fib(n): > ... if n == 0: > ... result = 0 > ... elif n == 1: > ... result = 1 > ... else: > ... result = fib(n-1) + fib(n-2) > ... print result, # trailing comma means no newline > ... return result > ... > py> fib(3) > 1 0 1 1 2 > 2 > py> fib(5) > 1 0 1 1 2 1 0 1 3 1 0 1 1 2 5 > 5 > > > If you want to print a list of Fibonnaci values, you need to call the > function in a loop. Removing the "print result" line again, you can do > this: > > py> for i in range(6): > ... print fib(i), > ... > 0 1 1 2 3 5 Thanks you Steven and others ( Dave, Chris and Terry ) , for having such good discussion on this topic and benefiting me in more than one way's. Thank you -- https://mail.python.org/mailman/listinfo/python-list
Re: To Change A Pdf Ebook To Kindle
On 03/24/2015 01:05 AM, jeffreyciross wrote: > probable spam I'm wondering whether this is appropriate use of sourceforge. Hosting a proprietary program on SF's web site for free, doesn't seem honest to me. Should I report this to SF as inappropriate content? -- https://mail.python.org/mailman/listinfo/python-list
Re: fibonacci series what Iam is missing ?
On Tue, Mar 24, 2015 at 12:20 AM, Rustom Mody wrote: > On Tuesday, March 24, 2015 at 10:51:11 AM UTC+5:30, Ian wrote: >> Iteration in log space. On my desktop, this calculates fib(1000) in >> about 9 us, fib(10) in about 5 ms, and fib(1000) in about 7 >> seconds. >> >> def fib(n): >> assert n >= 0 >> if n == 0: >> return 0 >> >> a = b = x = 1 >> c = y = 0 >> n -= 1 >> >> while True: >> n, r = divmod(n, 2) >> if r == 1: >> x, y = x*a + y*b, x*b + y*c >> if n == 0: >> return x >> b, c = a*b + b*c, b*b + c*c >> a = b + c > > This is rather arcane! > What are the identities used above? It's essentially the same matrix recurrence that Gregory Ewing's solution uses, but without using numpy (which doesn't support arbitrary precision AFAIK) and with a couple of optimizations. The Fibonacci recurrence can be expressed using linear algebra as: F_1 = [ 1 0 ] T = [ 1 1 ] [ 1 0 ] F_(n+1) = F_n * T I.e., given that F_n is a vector containing fib(n) and fib(n-1), multiplying by the transition matrix T results in a new vector containing fib(n+1) and fib(n). Therefore: F_n = F_1 * T ** (n-1) The code above evaluates this expression by multiplying F_1 by powers of two of T until n-1 is reached. x and y are the two elements of the result vector, which at the end of the loop are fib(n) and fib(n-1). a, b, and c are the three elements of the (symmetric) transition matrix T ** p, where p is the current power of two. The last two lines of the loop updating a, b, and c could equivalently be written as: a, b, c = a*a + b*b, a*b + b*c, b*b + c*c A little bit of algebra shows that if a = b + c before the assignment, the equality is maintained after the assignment (in fact the elements of T ** n are fib(n+1), fib(n), and fib(n-1)), so the two multiplications needed to update a can be optimized away in favor of a single addition. -- https://mail.python.org/mailman/listinfo/python-list
Re: To Change A Pdf Ebook To Kindle
On 24/03/2015 14:23, Michael Torrie wrote: On 03/24/2015 01:05 AM, jeffreyciross wrote: probable spam I'm wondering whether this is appropriate use of sourceforge. Hosting a proprietary program on SF's web site for free, doesn't seem honest to me. Should I report this to SF as inappropriate content? Yes. -- My fellow Pythonistas, ask not what our language can do for you, ask what you can do for our language. Mark Lawrence -- https://mail.python.org/mailman/listinfo/python-list
Re: To Change A Pdf Ebook To Kindle
On 03/24/2015 08:27 AM, Mark Lawrence wrote: > On 24/03/2015 14:23, Michael Torrie wrote: >> Should I report this to SF as inappropriate content? > > Yes. Done. And yes I agree with alister, Calibre is an amazing program and it's all 100% python! And a large-scale app at that. GPLv3. Putting a link here for the search engines. Hopefully if anyone finds this thread they'll find this instead of the spammy SF link. http://calibre-ebook.com/ -- https://mail.python.org/mailman/listinfo/python-list
Re: fibonacci series what Iam is missing ?
On Tuesday, March 24, 2015 at 10:24:59 PM UTC+8, Ian wrote: > On Tue, Mar 24, 2015 at 12:20 AM, Rustom Mody wrote: > > On Tuesday, March 24, 2015 at 10:51:11 AM UTC+5:30, Ian wrote: > >> Iteration in log space. On my desktop, this calculates fib(1000) in > >> about 9 us, fib(10) in about 5 ms, and fib(1000) in about 7 > >> seconds. > >> > >> def fib(n): > >> assert n >= 0 > >> if n == 0: > >> return 0 > >> > >> a = b = x = 1 > >> c = y = 0 > >> n -= 1 > >> > >> while True: > >> n, r = divmod(n, 2) > >> if r == 1: > >> x, y = x*a + y*b, x*b + y*c > >> if n == 0: > >> return x > >> b, c = a*b + b*c, b*b + c*c > >> a = b + c > > > > This is rather arcane! > > What are the identities used above? > > It's essentially the same matrix recurrence that Gregory Ewing's > solution uses, but without using numpy (which doesn't support > arbitrary precision AFAIK) and with a couple of optimizations. > > The Fibonacci recurrence can be expressed using linear algebra as: > > F_1 = [ 1 0 ] > > T = [ 1 1 ] > [ 1 0 ] > > F_(n+1) = F_n * T > > I.e., given that F_n is a vector containing fib(n) and fib(n-1), > multiplying by the transition matrix T results in a new vector > containing fib(n+1) and fib(n). Therefore: > > F_n = F_1 * T ** (n-1) > > The code above evaluates this expression by multiplying F_1 by powers > of two of T until n-1 is reached. x and y are the two elements of the > result vector, which at the end of the loop are fib(n) and fib(n-1). > a, b, and c are the three elements of the (symmetric) transition > matrix T ** p, where p is the current power of two. > > The last two lines of the loop updating a, b, and c could equivalently > be written as: > > a, b, c = a*a + b*b, a*b + b*c, b*b + c*c > > A little bit of algebra shows that if a = b + c before the assignment, > the equality is maintained after the assignment (in fact the elements > of T ** n are fib(n+1), fib(n), and fib(n-1)), so the two > multiplications needed to update a can be optimized away in favor of a > single addition. Well, solving a homogeneous difference equation of 2 degrees and generating the solution sequence for a particular one like the Finbnaci series is a good programming practice. A more general programming practice is to generate the solution series of an arbitrary homogeneous difference euqation of integer coefficients when a real or complex solution does exist. -- https://mail.python.org/mailman/listinfo/python-list
Regex Python Help
I am creating a tool to search a filesystem for one simple string.
I cannot get the syntax correct.
Thank you in advance for your help.
import sys
import re
import os
path='/'
viewfiles=os.listdir(path)
for allfiles in viewfiles:
file= os.path.join(path, allfiles)
text=open(file, "r")
for line in text:
if re.match("DECRYPT_I", line):
print line,
--
This should search every file for the simple regex "DECRYPT_I"
This is from the root down.
The error is:
SyntaxError: Missing parentheses in call to 'print'
Please help.
Gregg Dotoli
--
https://mail.python.org/mailman/listinfo/python-list
Re: Regex Python Help
On Tue, Mar 24, 2015 at 1:13 PM, wrote: > SyntaxError: Missing parentheses in call to 'print' It appears you are attempting to use a Python 2.x print statement with Python 3.x Try changing the last line to print(line.rstrip()) Skip -- https://mail.python.org/mailman/listinfo/python-list
Re: Regex Python Help
On 03/24/2015 11:13 AM, gdot...@gmail.com wrote:
I am creating a tool to search a filesystem for one simple string.
I cannot get the syntax correct.
Thank you in advance for your help.
import sys
import re
import os
path='/'
viewfiles=os.listdir(path)
for allfiles in viewfiles:
file= os.path.join(path, allfiles)
text=open(file, "r")
for line in text:
if re.match("DECRYPT_I", line):
print line,
--
This should search every file for the simple regex "DECRYPT_I"
This is from the root down.
The error is:
SyntaxError: Missing parentheses in call to 'print'
Please help.
Gregg Dotoli
You appear to be using Python3, but have written code for Python2.
There are a number of differences between the two, but your particular
error runs into the different syntax for prints.
Python2: print line # This is a statement
Python3 print(line) # This is a procedure call
--
Dr. Gary Herron
Department of Computer Science
DigiPen Institute of Technology
(425) 895-4418
--
https://mail.python.org/mailman/listinfo/python-list
subprocess and stdin.write(), stdout.read()
The docs for the subprocess.Popen() say:
Use communicate() rather than .stdin.write, .stdout.read
or .stderr.read to avoid deadlocks due to any of the other
OS pipe buffers filling up and blocking the child process
But if I want to send a string to stdin, how can I do that without
stdin.write()?
This seems to work:
import subprocess as s
thing = """
hey
there
foo man is here
hey foo
man is there
so foo
"""
p = s.Popen(['grep', 'foo'], stdin = s.PIPE, stdout = s.PIPE)
p.stdin.write(thing)
print p.communicate()
##
('\they foo\n \tfoo there\n', None)
Will this always avoid the deadlock problem?
This also works:
p = s.Popen(['grep', 'foo'], stdin = s.PIPE, stdout = s.PIPE)
p.stdin.write(thing)
p.stdin.close()
print p.stdout.read()
Is that vulnerable to deadlock? Is there a better way
to write to and read from the same process?
Thanks!
Tobiah
--
https://mail.python.org/mailman/listinfo/python-list
Re: Regex Python Help
Thank you Gary, that got rid of the error, but now there is no tree walk, it
runs and immediatley finishes. I just need to grep each file. I have this
working with the windows "for /r %a and redirecting that to Python, but want to
use Python only. I do have dummy files with the regex string.
Thanks again,
Gregg
On Tuesday, March 24, 2015 at 2:34:20 PM UTC-4, Gary Herron wrote:
> On 03/24/2015 11:13 AM, gdot...@gmail.com wrote:
> > I am creating a tool to search a filesystem for one simple string.
> > I cannot get the syntax correct.
> > Thank you in advance for your help.
> >
> > import sys
> > import re
> > import os
> > path='/'
> > viewfiles=os.listdir(path)
> > for allfiles in viewfiles:
> > file= os.path.join(path, allfiles)
> > text=open(file, "r")
> > for line in text:
> > if re.match("DECRYPT_I", line):
> > print line,
> >
> > --
> > This should search every file for the simple regex "DECRYPT_I"
> > This is from the root down.
> >
> > The error is:
> >
> > SyntaxError: Missing parentheses in call to 'print'
> >
> > Please help.
> > Gregg Dotoli
>
> You appear to be using Python3, but have written code for Python2.
>
> There are a number of differences between the two, but your particular
> error runs into the different syntax for prints.
>
> Python2: print line # This is a statement
> Python3 print(line) # This is a procedure call
>
>
>
> --
> Dr. Gary Herron
> Department of Computer Science
> DigiPen Institute of Technology
> (425) 895-4418
--
https://mail.python.org/mailman/listinfo/python-list
Re: Regex Python Help
Thank you! But
The print error is gone, but now the script quickly finishes and doesnt walk
the OS tree or search.
Gregg
On Tuesday, March 24, 2015 at 2:14:32 PM UTC-4, Gregg Dotoli wrote:
> I am creating a tool to search a filesystem for one simple string.
> I cannot get the syntax correct.
> Thank you in advance for your help.
>
> import sys
> import re
> import os
> path='/'
> viewfiles=os.listdir(path)
> for allfiles in viewfiles:
> file= os.path.join(path, allfiles)
> text=open(file, "r")
> for line in text:
> if re.match("DECRYPT_I", line):
> print line,
>
> --
> This should search every file for the simple regex "DECRYPT_I"
> This is from the root down.
>
> The error is:
>
> SyntaxError: Missing parentheses in call to 'print'
>
> Please help.
> Gregg Dotoli
--
https://mail.python.org/mailman/listinfo/python-list
Re: module attributes and docstrings
On 3/24/2015 4:55 AM, Mario Figueiredo wrote: Reading PEP 257 and 258 I got the impression that I could document module attributes and these would be available in the __doc__ attribute of the object. So things like the one below are something I got used to do, but that don't work after all, as I learned today: value_factory = lambda _, row: row[0] """Row factory. To be used with single-column queries.""" There are other things I could possibly do, like turning that lambda into a function, You have discovered one of advantages of a def statement over a name=lambda assignment statement. In Python, there is no good reason to use the latter form and PEP 8 specifically discourages it: "Always use a def statement instead of an assignment statement that binds a lambda expression directly to an identifier." -- Terry Jan Reedy -- https://mail.python.org/mailman/listinfo/python-list
Re: Regex Python Help
Le 24/03/2015 20:38, Vincent Vande Vyvre a écrit :
Le 24/03/2015 20:22, Gregg Dotoli a écrit :
Thank you! But
The print error is gone, but now the script quickly finishes and
doesnt walk
the OS tree or search.
Gregg
On Tuesday, March 24, 2015 at 2:14:32 PM UTC-4, Gregg Dotoli wrote:
I am creating a tool to search a filesystem for one simple string.
I cannot get the syntax correct.
Thank you in advance for your help.
import sys
import re
import os
path='/'
viewfiles=os.listdir(path)
for allfiles in viewfiles:
file= os.path.join(path, allfiles)
text=open(file, "r")
for line in text:
if re.match("DECRYPT_I", line):
print line,
--
This should search every file for the simple regex "DECRYPT_I"
This is from the root down.
The error is:
SyntaxError: Missing parentheses in call to 'print'
Please help.
Gregg Dotoli
Your indentation is wrong.
for allfiles in viewfiles:
file= os.path.join(path, allfiles)
text=open(file, "r")
for line in text:
if re.match("DECRYPT_I", line):
print line,
Vincent
... and me too
for allfiles in viewfiles:
file= os.path.join(path, allfiles)
text=open(file, "r")
for line in text:
if re.match("DECRYPT_I", line):
print line,
--
https://mail.python.org/mailman/listinfo/python-list
Re: Regex Python Help
On Tue, Mar 24, 2015 at 2:22 PM, Gregg Dotoli wrote: > The print error is gone, but now the script quickly finishes and doesnt > walk > the OS tree or search. > You need to walk the directory tree recursively. Take a look at os.walk(). Skip -- https://mail.python.org/mailman/listinfo/python-list
Re: Regex Python Help
On Tue, 24 Mar 2015 12:10:24 -0700, Gregg Dotoli wrote: > > Thank you Gary, that got rid of the error, but now there is no tree > walk, it runs and immediatley finishes. I just need to grep each file. I > have this working with the windows "for /r %a and redirecting that to > Python, but want to use Python only. I do have dummy files with the > regex string. > > Thanks again, > Gregg > Gregg -- First, please don't top-post. Secondly, os.listdir only does exactly that; it lists everything on one directory. You're looking for os.walk. -- Rob -- Rob Gaddi, Highland Technology -- www.highlandtechnology.com Email address domain is currently out of order. See above to fix. -- https://mail.python.org/mailman/listinfo/python-list
Re: Regex Python Help
This works fine , but I have to pipe the filename to the script python stool
I am creating a tool to search a filesystem for one simple string.
> I cannot get the syntax correct.
> Thank you in advance for your help.
>
> import sys
> import re
> import os
> path='/'
> viewfiles=os.listdir(path)
> for allfiles in viewfiles:
> file= os.path.join(path, allfiles)
> text=open(file, "r")
> for line in text:
> if re.match("DECRYPT_I", line):
> print line,
>
> --
> This should search every file for the simple regex "DECRYPT_I"
> This is from the root down.
>
> The error is:
>
> SyntaxError: Missing parentheses in call to 'print'
>
> Please help.
> Gregg Dotoli
--
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Re: Regex Python Help
Le 24/03/2015 20:22, Gregg Dotoli a écrit :
Thank you! But
The print error is gone, but now the script quickly finishes and doesnt walk
the OS tree or search.
Gregg
On Tuesday, March 24, 2015 at 2:14:32 PM UTC-4, Gregg Dotoli wrote:
I am creating a tool to search a filesystem for one simple string.
I cannot get the syntax correct.
Thank you in advance for your help.
import sys
import re
import os
path='/'
viewfiles=os.listdir(path)
for allfiles in viewfiles:
file= os.path.join(path, allfiles)
text=open(file, "r")
for line in text:
if re.match("DECRYPT_I", line):
print line,
--
This should search every file for the simple regex "DECRYPT_I"
This is from the root down.
The error is:
SyntaxError: Missing parentheses in call to 'print'
Please help.
Gregg Dotoli
Your indentation is wrong.
for allfiles in viewfiles:
file= os.path.join(path, allfiles)
text=open(file, "r")
for line in text:
if re.match("DECRYPT_I", line):
print line,
Vincent
--
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Re: subprocess and stdin.write(), stdout.read()
On Tue, Mar 24, 2015 at 12:08 PM, Tobiah wrote:
> The docs for the subprocess.Popen() say:
>
> Use communicate() rather than .stdin.write, .stdout.read
> or .stderr.read to avoid deadlocks due to any of the other
> OS pipe buffers filling up and blocking the child process
>
> But if I want to send a string to stdin, how can I do that without
> stdin.write()?
>
> This seems to work:
>
> import subprocess as s
>
> thing = """
> hey
> there
> foo man is here
> hey foo
> man is there
> so foo
> """
> p = s.Popen(['grep', 'foo'], stdin = s.PIPE, stdout = s.PIPE)
> p.stdin.write(thing)
> print p.communicate()
>
> ##
>
> ('\they foo\n \tfoo there\n', None)
>
>
> Will this always avoid the deadlock problem?
What you should do is use "print p.communicate(thing)". That will
always avoid the deadlock issue.
Your code MAY deadlock in some cases as the stdin pipe could fill up
fully, but the other process is not reading it as it is waiting for
you to read output. What this means is that, you must be reading from
stdout AND stderr if you are possibly waiting for the process (such as
when writing to stdin or using .wait() or looping on .poll()).
subprocess.communicate() takes care of that issue internally, however
you can write your own variations (useful if you need to process
stdout to produce stdin, for example), however you must either be
using a select or threads to be sure to be reading stdout and stderr.
You should also pay attention to the note on communicate - if
potentially large amounts of data will be produced, you may need to
write your own method to avoid memory paging/OOM issues due to
communicate filling up the system's RAM.
In the example you provide, you will probably never hit the deadlock
as the data being written is small enough that it should never fill
the buffers (typically, they are ~2k). Additionally, if you know the
process never produces output on stdout or stderr, you can ignore them
(but then, why would you pipe them?).
>
> This also works:
>
> p = s.Popen(['grep', 'foo'], stdin = s.PIPE, stdout = s.PIPE)
> p.stdin.write(thing)
> p.stdin.close()
> print p.stdout.read()
>
> Is that vulnerable to deadlock? Is there a better way
> to write to and read from the same process?
This is more likely to cause deadlocks as, if the process writes too
much to stderr, it may stall waiting for you to read it, while you are
waiting for it to close stdout.
--
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Re: Regex Python Help
On 3/24/2015 2:13 PM, gdot...@gmail.com wrote:
I am creating a tool to search a filesystem for one simple string.
I cannot get the syntax correct.
Thank you in advance for your help.
import sys
import re
import os
path='/'
viewfiles=os.listdir(path)
listdir is not recursive, so this code will only search files in the one
directory, not the whole filesystem. You need to use os.walk and modify
the code to do the latter.
for allfiles in viewfiles:
file= os.path.join(path, allfiles)
text=open(file, "r")
for line in text:
if re.match("DECRYPT_I", line):
print line,
You appear to have used a mixture of spaces and tabs for indents. That
works in 2.x, but not in 3.x. You open but do not close files, which
could be a problem if you open and search 10 files in a filesystem.
Use a with statememt. 'allfiles' is a bad name because it get bound
to a single file.
for file in viewfiles:
with open(os.path.join(path, file)) as text:
for line in text:
if re.match("DECRYPT_I", line):
print(line)
--
Terry Jan Reedy
--
https://mail.python.org/mailman/listinfo/python-list
Re: Regex Python Help
On Tue, 24 Mar 2015 12:43:38 -0700, Gregg Dotoli wrote: > [context snipped due to top posting] > > All I need is a loop, should I bag Python and use a simple shell for loop? Honestly, yes. You're not even using a regular expression, just a fixed string you're trying to search for. You can do the entire thing as $ find . -type f | xargs grep DECRYPT_I -- Rob Gaddi, Highland Technology -- www.highlandtechnology.com Email address domain is currently out of order. See above to fix. -- https://mail.python.org/mailman/listinfo/python-list
Pillow bug?
Judging from the message archive, the image-sig list is (just about) dead?
Disclaimer: Am a newbie - so anything is possible
using 'RGB' works fine
img = Image.new('RGB', (inktile[0], inktile[1]), bgcolor)
using '1' or 'L' does not (see trace below)
img = Image.new('L', (inktile[0], inktile[1]), bgcolor)
I change nothing else but the first parameter. If I switch the 'L' back to
'RGB' it works again.
img = Image.new('L', (inktile[0], inktile[1]), bgcolor)
File "C:\Python27\lib\site-packages\PIL\Image.py", line 2015, in new
return Image()._new(core.fill(mode, size, color))
TypeError: an integer is required
The docs say that '1' and 'L' are supported - something broken? Something I do
not understand?
Thanks for any pointers,
Kai
--
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Re: Pillow bug?
On Tue, Mar 24, 2015 at 1:52 PM, wrote:
> Judging from the message archive, the image-sig list is (just about) dead?
>
> Disclaimer: Am a newbie - so anything is possible
>
>
> using 'RGB' works fine
>
> img = Image.new('RGB', (inktile[0], inktile[1]), bgcolor)
>
> using '1' or 'L' does not (see trace below)
>
> img = Image.new('L', (inktile[0], inktile[1]), bgcolor)
>
>
> I change nothing else but the first parameter. If I switch the 'L' back to
> 'RGB' it works again.
>
>
> img = Image.new('L', (inktile[0], inktile[1]), bgcolor)
> File "C:\Python27\lib\site-packages\PIL\Image.py", line 2015, in new
> return Image()._new(core.fill(mode, size, color))
> TypeError: an integer is required
>
> The docs say that '1' and 'L' are supported - something broken? Something I
> do not understand?
What is the value of bgcolor that you're passing in? Per the docs: "If
given, this should be a single integer or floating point value for
single-band modes, and a tuple for multi-band modes (one value per
band)." So if you're changing from a multi-band mode to a single-band
mode, you would need to change the color argument as well.
--
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Re: Pillow bug?
On 3/24/2015 3:52 PM, kai.pet...@gmail.com wrote: Judging from the message archive, the image-sig list is (just about) dead? PIL and/or pillow should have their own lists. -- Terry Jan Reedy -- https://mail.python.org/mailman/listinfo/python-list
Re: Pillow bug?
On Tuesday, 24 March 2015 13:15:42 UTC-7, Ian wrote:
> On Tue, Mar 24, 2015 at 1:52 PM, Kai wrote:
> > Judging from the message archive, the image-sig list is (just about) dead?
> >
> > Disclaimer: Am a newbie - so anything is possible
> >
> >
> > using 'RGB' works fine
> >
> > img = Image.new('RGB', (inktile[0], inktile[1]), bgcolor)
> >
> > using '1' or 'L' does not (see trace below)
> >
> > img = Image.new('L', (inktile[0], inktile[1]), bgcolor)
> >
> >
> > I change nothing else but the first parameter. If I switch the 'L' back to
> > 'RGB' it works again.
> >
> >
> > img = Image.new('L', (inktile[0], inktile[1]), bgcolor)
> > File "C:\Python27\lib\site-packages\PIL\Image.py", line 2015, in new
> > return Image()._new(core.fill(mode, size, color))
> > TypeError: an integer is required
> >
> > The docs say that '1' and 'L' are supported - something broken? Something I
> > do not understand?
>
> What is the value of bgcolor that you're passing in? Per the docs: "If
> given, this should be a single integer or floating point value for
> single-band modes, and a tuple for multi-band modes (one value per
> band)." So if you're changing from a multi-band mode to a single-band
> mode, you would need to change the color argument as well.
Good catch - that was it.
Thanks much!
--
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Re: Regex Python Help
Here you go. Windows shell was easier!!! for /f %a in (c:\gonow) do echo %a | c:\Python34\python c:\python34\unopy.py %a Now I can use any regex pattern, I need. On Tuesday, March 24, 2015 at 3:54:25 PM UTC-4, Rob Gaddi wrote: > On Tue, 24 Mar 2015 12:43:38 -0700, Gregg Dotoli wrote: > > > [context snipped due to top posting] > > > > All I need is a loop, should I bag Python and use a simple shell for > loop? > > Honestly, yes. You're not even using a regular expression, just a fixed > string you're trying to search for. You can do the entire thing as > > $ find . -type f | xargs grep DECRYPT_I > > -- > Rob Gaddi, Highland Technology -- www.highlandtechnology.com > Email address domain is currently out of order. See above to fix. -- https://mail.python.org/mailman/listinfo/python-list
Daylight savings time question
Is there a way of "adding" 4 hours and getting a jump of 5 hours on
March 8th, 2015 (due to Daylight Savings Time), without hardcoding
when to spring forward and when to fall back? I'd love it if there's
some library that'll do this for me.
#!/usr/bin/python
import pytz
import datetime
def main():
# On 2015-03-08, 2:00 AM to 2:59AM Pacific time does not exist -
the clock jumps forward an hour.
weird_naive_datetime = datetime.datetime(2015, 3, 8, 1, 0,
0).replace(tzinfo=pytz.timezone('US/Pacific'))
weird_tz_aware_datetime =
weird_naive_datetime.replace(tzinfo=pytz.timezone('US/Pacific'))
print(weird_tz_aware_datetime)
four_hours=datetime.timedelta(hours=4)
print('Four hours later is:')
print(weird_tz_aware_datetime + four_hours)
print('...but I want numerically 5 hours later, because of
Daylight Savings Time')
main()
Thanks!
--
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Re: Daylight savings time question
On 03/24/2015 03:24 PM, Dan Stromberg wrote:
Is there a way of "adding" 4 hours and getting a jump of 5 hours on
March 8th, 2015 (due to Daylight Savings Time), without hardcoding
when to spring forward and when to fall back? I'd love it if there's
some library that'll do this for me.
#!/usr/bin/python
import pytz
import datetime
def main():
# On 2015-03-08, 2:00 AM to 2:59AM Pacific time does not exist -
the clock jumps forward an hour.
weird_naive_datetime = datetime.datetime(2015, 3, 8, 1, 0,
0).replace(tzinfo=pytz.timezone('US/Pacific'))
weird_tz_aware_datetime =
weird_naive_datetime.replace(tzinfo=pytz.timezone('US/Pacific'))
print(weird_tz_aware_datetime)
four_hours=datetime.timedelta(hours=4)
print('Four hours later is:')
print(weird_tz_aware_datetime + four_hours)
print('...but I want numerically 5 hours later, because of
Daylight Savings Time')
main()
Thanks!
The pyzt module (which you've imported) has lots to say about this. Look
at its procedures "localize' and 'normalize' and all the rest of the
pyzt documentation.
--
Dr. Gary Herron
Department of Computer Science
DigiPen Institute of Technology
(425) 895-4418
--
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Re: Daylight savings time question
On Wed, Mar 25, 2015 at 9:24 AM, Dan Stromberg wrote: > Is there a way of "adding" 4 hours and getting a jump of 5 hours on > March 8th, 2015 (due to Daylight Savings Time), without hardcoding > when to spring forward and when to fall back? I'd love it if there's > some library that'll do this for me. Fundamentally, this requires knowledge of timezone data. That means you have to select a political time zone, which basically means you want the Olsen database (tzdata) which primarily works with city names. I'm not sure whether "US/Pacific" is suitable; I usually use "America/Los_Angeles" for Pacific US time. But that aside, what Gary said is what I would recommend. ChrisA -- https://mail.python.org/mailman/listinfo/python-list
Re: subprocess and stdin.write(), stdout.read()
On Tue, 24 Mar 2015 12:08:24 -0700, Tobiah wrote: > But if I want to send a string to stdin, how can I do that without > stdin.write()? p.communicate(string) > This seems to work: Only because the amounts of data involved are small enough to avoid deadlock. If both sides write more data in one go than will fit into a pipe buffer, you will get deadlock. The parent will be blocked waiting for the child to consume the input, which doesn't happen because the child will be blocked waiting for the parent to consume its output, which doesn't happen because he parent will be blocked waiting for the child to consume the input, ... That's a textbook example of deadlock: each side waiting forever for the other side to make the first move. This is exactly why POSIX' popen() function lets you either write to stdin (mode=="w") or read from stdout (mode=="r") but not both. > Will this always avoid the deadlock problem? No. > This also works: Again, only because the amounts of data involved are small enough to avoid deadlock. > Is that vulnerable to deadlock? Yes. > Is there a better way to write to and read from the same process? Use threads; one for each descriptor (stdin, stdout, stderr). Non-blocking I/O is an alternative (and that's what .communicate() uses on Unix), but threads will work on all common desktop and server platforms. If you need to support platforms which lack threads, either a) have the parent first write to a file (instead of .stdin), then have the child read from the file while the parent reads .stdout and .stderr, or b) have the parent write to .stdin while the child writes its stdout/stderr to files (or a file). Once the child completes, have the parent read the file(s). Using files allows for potentially gigabytes of data to be buffered. With pipes, the amount may be as low as 512 bytes (the minimum value allowed by POSIX) and will rarely be much more (a typical value is 4096 bytes, i.e. one "page" on x86). -- https://mail.python.org/mailman/listinfo/python-list
OpenID + Python 3.4
I was looking on the Internet regarding the use of OpenID in Python apps but I only found Flask/web related stuff. Is there any module that provides OpenID implementation for desktop level? I currently have a Python desktop script that needs to authenticate in a OpenID server, but I don't know how to implement it. -- https://mail.python.org/mailman/listinfo/python-list
Re: Daylight savings time question
This appears to do what I wanted:
#!/usr/bin/python
from __future__ import print_function
import pytz
import datetime
# Is there a good way of jumping ahead 5 hours instead of 4 on 2015-03-08?
def main():
# On 2015-03-08, 2:00 AM to 2:59AM Pacific time does not exist -
the clock jumps forward an hour.
us_pacific = pytz.timezone('US/Pacific')
weird_naive_datetime = datetime.datetime(2015, 3, 8, 1, 0, 0)
print('weird_naive_datetime: ', weird_naive_datetime)
weird_tz_aware_datetime = us_pacific.localize(weird_naive_datetime)
print('weird_tz_aware_datetime', weird_tz_aware_datetime)
four_hours=datetime.timedelta(hours=4)
print('Four hours later is: ',
us_pacific.normalize(weird_tz_aware_datetime + four_hours))
print('...we want numerically 5 hours later (so 6AM), because of
Daylight Savings Time')
main()
On Tue, Mar 24, 2015 at 3:24 PM, Dan Stromberg wrote:
> Is there a way of "adding" 4 hours and getting a jump of 5 hours on
> March 8th, 2015 (due to Daylight Savings Time), without hardcoding
> when to spring forward and when to fall back? I'd love it if there's
> some library that'll do this for me.
>
> #!/usr/bin/python
>
> import pytz
> import datetime
>
> def main():
> # On 2015-03-08, 2:00 AM to 2:59AM Pacific time does not exist -
> the clock jumps forward an hour.
> weird_naive_datetime = datetime.datetime(2015, 3, 8, 1, 0,
> 0).replace(tzinfo=pytz.timezone('US/Pacific'))
> weird_tz_aware_datetime =
> weird_naive_datetime.replace(tzinfo=pytz.timezone('US/Pacific'))
> print(weird_tz_aware_datetime)
> four_hours=datetime.timedelta(hours=4)
> print('Four hours later is:')
> print(weird_tz_aware_datetime + four_hours)
> print('...but I want numerically 5 hours later, because of
> Daylight Savings Time')
>
> main()
>
>
> Thanks!
--
https://mail.python.org/mailman/listinfo/python-list
Re: To Change A Pdf Ebook To Kindle
On Tue, 24 Mar 2015 11:32 pm, alister wrote: > On Tue, 24 Mar 2015 00:05:46 -0700, jeffreyciross wrote: [off-topic spam] > > Calibre does a very god job as well. Please don't reply to spam. Unless the product is a Python library, or is given in direct reply to an explicit request for an application which is usable by Python, it is off-topic and spam. I see Calibre is a Python application, not sure if it is importable by Python scripts though. Thank you, -- Steven -- https://mail.python.org/mailman/listinfo/python-list
Re: Best way to calculate fraction part of x?
On Mon, Mar 23, 2015 at 8:38 PM, Emile van Sebille wrote:
> On 3/23/2015 5:52 AM, Steven D'Aprano wrote:
>
> Are there any other, possibly better, ways to calculate the fractional
>> part
>> of a number?
>>
>
> float (("%6.3f" % x)[-4:])
In general you lose a lot of precision this way...
--
https://mail.python.org/mailman/listinfo/python-list
Re: Regex Python Help
On Wed, 25 Mar 2015 05:13 am, gdot...@gmail.com wrote: > The error is: > > SyntaxError: Missing parentheses in call to 'print' I cannot imagine how the message could be more explicit: the call to print is missing parentheses. If you're not going to read the error messages you are given, you are truly going to struggle as a programmer. Read the error message. If you don't understand the error message, please say so. And choose a relevant subject line: this has nothing to do with regexes. You might as well have called it "Import Python Help". -- Steven -- https://mail.python.org/mailman/listinfo/python-list
test1
body {color:black;}
h1 {text-align:center;color:maroon;font-size:30px;font-style:normal;}
td {font-size:12;font-style:monospace;}
}
{% block title %}{% endblock %}
IPDB Data Input Window
Address:{{ form.address }}
Filename:{{ form.filename }}
{{ form.box }}
Delete Selected
Description:{{ form.description }}
Expiry date:{{ form.expiry }}
function submitReset()
{
document.getElementById("frm1").reset();
}
function add()
{
window.location.replace="http://127.0.0.1:8000/add/";
}
function clearForms()
{
// variable declaration
var x, y, z, type = null;
// loop through forms on HTML page
for (x = 0; x < document.forms.length; x++) {
// loop through each element on form
for (y = 0; y < document.forms[x].elements.length; y++) {
// define element type
type = document.forms[x].elements[y].type;
// alert before erasing form element
//alert('form='+x+' element='+y+' type='+type);
// switch on element type
switch (type) {
case 'text':
case 'textarea':
case 'password':
//case "hidden":
document.forms[x].elements[y].value = '';
break;
case 'radio':
case 'checkbox':
document.forms[x].elements[y].checked = '';
break;
case 'select-multiple':
for (z = 0; z <
document.forms[x].elements[y].options.length; z++) {
document.forms[x].elements[y].options[z].selected =
false;
}
case 'iframe'
} // end switch
} // end for y
} // end for x
//x = window.frames["frame1"];
//x.document.body.innerHTML = "";
}
---
body {
font-size:10px;
color:black;
backgrounc:CC;
}
h1 {
text-align:center;
color:maroon;
font-size:30px;
font-style:normal;
}
td {
font-size:12;
font-style:monospace;
}
select {
background: transparent;
width: 500;
height: 300;
padding: 5px;
font-size: 16px;
border: 1px solid #ccc;
height: 34px;
}
#righty {
float:right ;
width:20% ;
}
#des {
float:right ;
width:50% ;
}
#tab {
font-size:12;font-style:normal;
}
#msg {
font-size:12;font-style:monospace;background:FFCC66;
}
#id_box {
width:300px;height:150;border:1px solid
black;background-color:ivory;padding:8px;
}
IPDB Asset Input