Re: About executable
On 25 Aug 2013 21:47, "Luis José Novoa" wrote: > > Hi All. I am trying to create an executable file containing an optimization code using the pyomo package for optimization modeling along with ither packages like Numpy. When using py2exe to perform the task it generates the executable file, but when I try to run it it reports: Import Error: No module named pyomo. > > Any guidance on how to solve this problem would be really appreciated. Have you checked py2exe's documentation? Bundling external modules with an exe ought to be a very, very, common task. If all else fails, you can try cx_freeze too. I think it generates windows executables too. Good luck! -- http://mail.python.org/mailman/listinfo/python-list
Resetting state of http.client/httplib HTTPSConnection objects
This is a crosspost from python-tutor upon suggestion.
I am experiencing intermittent issues where an exception will be raised when
calling getresponse(), which makes the entire connection stuck in Request-sent
state. Is it possible to reset to idle state somehow without reinstantiating
the HTTPSConnection? I ideally want to keep the connection to the server, and
just reset the state to idle so that I can make another request (like you would
usually do by calling getresponse()).
>>> a.conn
>>> a.conn.getresponse()
Traceback (most recent call last):
File "", line 1, in
File "/usr/lib64/python3.3/http/client.py", line 1143, in getresponse
response.begin()
File "/usr/lib64/python3.3/http/client.py", line 354, in begin
version, status, reason = self._read_status()
File "/usr/lib64/python3.3/http/client.py", line 324, in _read_status
raise BadStatusLine(line)
http.client.BadStatusLine: ''
>>> a.conn.request("GET", "foo")
Traceback (most recent call last):
File "", line 1, in
File "/usr/lib64/python3.3/http/client.py", line 1061, in request
self._send_request(method, url, body, headers)
File "/usr/lib64/python3.3/http/client.py", line 1089, in _send_request
self.putrequest(method, url, **skips)
File "/usr/lib64/python3.3/http/client.py", line 944, in putrequest
raise CannotSendRequest(self.__state)
http.client.CannotSendRequest: Request-sent
pgpkTDZASsW7A.pgp
Description: PGP signature
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Peasy: an easy but powerful parser
I've released Peasy, which is an easy but powerful parser. Peasy brings a new method to write the parser. with Peasy, you write the parser by hand, just like to write any other kind of program. Do not be confused by "by hand", with the method brought by Peasy, it's easier and more powerful than using other tools or libraries. Peasy presents itself as a module of single file. To use Peasy, copy peasy.py to your project, read it, modify it, write the grammar rules, and remove any unnecessary stuffs in Peasy, and parse with the grammar. Peasy has an simple, elegant and fast support for direct/indirect left recursive grammar, See [here]( http://chaosim.github.io/peasy/doc/peasy.html#peasysample ) for a concrete sample. The [annotated code]( http://chaosim.github.io/peasy/doc/pypeasy.html ) is best document for Peasy at the moment. -- http://mail.python.org/mailman/listinfo/python-list
Getting request's source site
Hi all, I was wondering how i can get the source from which the request came from. If a user posted a link that directs to my server on facebook i'd like to know that a specific click was from facebook or twitter etc.. Thanks -- http://mail.python.org/mailman/listinfo/python-list
Re: Checking homogeneity of Array using List in Python
On 2013-08-25, sahil301...@gmail.com wrote: > I am unable to check homogeneity of Array. > I have take Array type Int to be default for my code. > > Instead of getting Error on NON-INT Values. > I want to take input as string. > Then check if all input is in (0-9) form, I typecast it into int and Accept. > Else, I would like to skip that input. > > eg. my input is ['1', ' ', 'asdasd231231', '1213asasd', '43242'] > I want it to be interpreted as: > [1, [None], [None], [None], 43242] > > NOTE: NO INBUILT FUNCTION BE USED. Impossible. I think. -- Neil Cerutti -- http://mail.python.org/mailman/listinfo/python-list
Re: Getting request's source site
On Mon, 26 Aug 2013 06:10:41 -0700, Guy Tamir wrote: > Hi all, > > I was wondering how i can get the source from which the request came > from. If a user posted a link that directs to my server on facebook i'd > like to know that a specific click was from facebook or twitter etc.. That would be the "referer" header in the HTTP request. (Note that it is an accidental misspelling of "referrer".) Including a referrer is not compulsory, so be prepared for it not to be available. -- Steven -- http://mail.python.org/mailman/listinfo/python-list
Re: Getting request's source site
On Mon, Aug 26, 2013 at 11:03 AM, Guy Tamir wrote: > On Monday, August 26, 2013 5:25:49 PM UTC+3, Steven D'Aprano wrote: >> On Mon, 26 Aug 2013 06:10:41 -0700, Guy Tamir wrote: >> >> >> >> > Hi all, >> >> > >> >> > I was wondering how i can get the source from which the request came >> >> > from. If a user posted a link that directs to my server on facebook i'd >> >> > like to know that a specific click was from facebook or twitter etc.. >> >> >> >> That would be the "referer" header in the HTTP request. (Note that it is >> >> an accidental misspelling of "referrer".) Including a referrer is not >> >> compulsory, so be prepared for it not to be available. >> >> >> >> >> >> >> >> -- >> >> Steven > > Thanks for reply, > In what cases will i have this header? is there something i can do to enforce > having it? > Are there any other ways? > -- You can look in the server logs if you have them available. If the visitor supplied a referer value in the header, it will be in the log. You don't have any say in this from your end. If you are the creator of your own website you might like to add google analytics to your pages. This is done with a little javascript that google provides. Although there may be a python angle to your question, it isn't apparent yet. > http://mail.python.org/mailman/listinfo/python-list -- Joel Goldstick http://joelgoldstick.com -- http://mail.python.org/mailman/listinfo/python-list
Re: python eval function
On Mon, 2013-08-26 at 00:55 +, Steven D'Aprano wrote: > On Sun, 25 Aug 2013 23:48:34 +0430, Mohsen Pahlevanzadeh wrote: > > > Dear all, > > > > eval doesn't run my code at the following link: > > http://stackoverflow.com/questions/18432198/eval-function-doesnt-work- > in-python > > > Are you asking a question or just sharing a useful link? > > > > > Thank you before your answer... > > What question do you want us to answer? The question on Stackoverflow has > already been answered correctly: there is no need to use eval (or exec) > for this basic task. > > Also, you're not writing C code. Get rid of the semi-colons, they are > just a waste of time, and make you look like an incompetent programmer. > > Using exec is not the right solution. That is unsafe, if the field name > and content come from a database or external input, your code now has a > *serious* Code Injection vulnerability. AND it is slow. So you have > written slow, unsafe code. Get rid of it, and use setattr like you have > already been told: > > setattr(self, fieldName, fieldValue) > > > > -- > Steven I didn't post a useful link,i questioned my problem.Of course, At first i put it @stackoverflow then post its link for the following idea: 1. collecting votes for me and someone answered. 2. If anyone have my question in future, can use it. Thank you for answer. --mohsen -- http://mail.python.org/mailman/listinfo/python-list
Re: Getting request's source site
On Monday, August 26, 2013 5:25:49 PM UTC+3, Steven D'Aprano wrote: > On Mon, 26 Aug 2013 06:10:41 -0700, Guy Tamir wrote: > > > > > Hi all, > > > > > > I was wondering how i can get the source from which the request came > > > from. If a user posted a link that directs to my server on facebook i'd > > > like to know that a specific click was from facebook or twitter etc.. > > > > That would be the "referer" header in the HTTP request. (Note that it is > > an accidental misspelling of "referrer".) Including a referrer is not > > compulsory, so be prepared for it not to be available. > > > > > > > > -- > > Steven Thanks for reply, In what cases will i have this header? is there something i can do to enforce having it? Are there any other ways? -- http://mail.python.org/mailman/listinfo/python-list
Python Global variable
Hi all, Please see the below code,in which i'm verifying the global value in python. CHK=10 def test1(): print "Value of CHK in test1",CHK def test2(): CHK=40 print "Value of CHK in test2",CHK test1() def test3(): global CHK test2() test3() When i ran above code ,I'm getting vlaue of CHK as 40 in test2 method and 10 in test1 method Can somone explain me why the value of CHK is different in method test1 and test2. Best Regards, Chandan -- http://mail.python.org/mailman/listinfo/python-list
Re: Python Global variable
On Mon, Aug 26, 2013 at 5:54 AM, chandan kumar wrote: > Hi all, > > Please see the below code,in which i'm verifying the global value in python. > > CHK=10 > > def test1(): > print "Value of CHK in test1",CHK > > def test2(): > CHK=40 > print "Value of CHK in test2",CHK > test1() > > def test3(): > global CHK > test2() > > test3() > > When i ran above code ,I'm getting vlaue of CHK as 40 in test2 method and 10 > in test1 method > Can somone explain me why the value of CHK is different in method test1 and > test2. First, you are using incorrect terminology. You are defining functions here, not methods. A method is a 'function' that is contained within a class. Now, on to your question. You define CHK = 10 at the top of your code. CHK is a name defined within the global namespace of your file. In test1 you print CHK which will be the value of the global CHK. This is because, in python if a referenced name isn't present in the most immediate namespace (test1), it will look in the successive containing namespaces. to find the value. In test2 you create a new name CHK which is not the same as the outer CHK. The test2 CHK is only visible within the function. You assign it the value 40. When it executes, it prints 40. In test3 you let test3 know that CHK refers to the global (outer) name CHK. However when you call test2, you do it with no parameters. test2 knows nothing of your test3 internal names. You need to look up python namespaces, and scoping. I believe these are covered in the python.org tutorial. Be aware that if you learned another language (C, Java) that names will confuse you for a while in python. > > Best Regards, > Chandan > > > -- > http://mail.python.org/mailman/listinfo/python-list -- Joel Goldstick http://joelgoldstick.com -- http://mail.python.org/mailman/listinfo/python-list
Re: Python Global variable
On 26/08/2013 10:54, chandan kumar wrote: Hi all, Please see the below code,in which i'm verifying the global value in python. CHK=10 def test1(): print "Value of CHK in test1",CHK def test2(): CHK=40 print "Value of CHK in test2",CHK test1() def test3(): global CHK test2() test3() When i ran above code ,I'm getting vlaue of CHK as 40 in test2 method and 10 in test1 method Can somone explain me why the value of CHK is different in method test1 and test2. In a function, if you bind to a name then Python assumes that the name is local to that function unless you declare that it's global. In test1, you refer to 'CHK' but don't bind to it, therefore it's global. In test2, you bind to 'CHK' with 'CHK=40', and you haven't declared that it's global, therefore it's local to test2. In test3, you declare that 'CHK' is global, but don't mention it anywhere else in that function, so it serves no purpose. -- http://mail.python.org/mailman/listinfo/python-list
optparse question (python 2.6)
Hi python-guru's, I am new to Python, coming from a long history of Unix/linux shell programming. I am creating a Python script (In Python 2.6) which should be able to read command line options and arguments. So far, I figured out how to do that with optparse. I can add options (and arguments ) . There are about 7 options that can be selected. However, I can't seem to figure out how to force that only one option is allowed when the script is invoked. In other words: How to restrict the script to accept only one of the available options ? cheers, Andy -- http://mail.python.org/mailman/listinfo/python-list
Re: optparse question (python 2.6)
Andy Kannberg wrote:
> Hi python-guru's,
>
> I am new to Python, coming from a long history of Unix/linux shell
> programming.
> I am creating a Python script (In Python 2.6) which should be able to
> read command line options and arguments.
> So far, I figured out how to do that with optparse. I can add options (and
> arguments ) .
> There are about 7 options that can be selected.
>
> However, I can't seem to figure out how to force that only one option is
> allowed when the script is invoked. In other words: How to restrict the
> script to accept only one of the available options ?
You have to do it manually, like in the example
http://docs.python.org/2.6/library/optparse.html#how-optparse-handles-errors
if options.a and options.b:
parser.error("options -a and -b are mutually exclusive")
which could be generalized to (untested)
option_names = ["foo", "bar", "baz", ...]
toggled_options = [name for name in option_names if getattr(options, name)]
if len(toggled_options) > 1:
s = repr(toggled_options).strip("[]")
parser.error("options %s are mutually exclusive" % s)
If you are not restricted to the standard library use
https://pypi.python.org/pypi/argparse
which was added to the stdlib in 2.7 and has "mutually exclusive groups",
see
http://docs.python.org/2/library/argparse.html#mutual-exclusion
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Re: Getting request's source site
On Mon, Aug 26, 2013, at 11:03, Guy Tamir wrote: > Thanks for reply, > In what cases will i have this header? In practice, you'll usually have it, except in cases where the user has bookmarked your site, typed/pasted the URL directly, had it opened by an external program, or taken action to block referers from being sent (this last one is uncommon) > is there something i can do to > enforce having it? You can refuse to serve the content if it's not present. But this will annoy users since they can't bookmark it or open it from an external program. -- http://mail.python.org/mailman/listinfo/python-list
How come StopIteration.__base__ is not BaseException?
Since StopIteration is not an error, how come does it inherit directly from Exception and not from BaseException? Thanks in advance, Marco -- Marco -- http://mail.python.org/mailman/listinfo/python-list
How to check client shutdown?
I'm currently learning about the socket module. My question is how can I detect
if a connection is closed from the other side, for example a KeyboardInterrupt
as I frequently use. My code below:
##
#server script:
class client(threading.Thread):
def __init__(self, connection):
super(client, self).__init__()
self.recv = connection.recv
print dir(connection)
def start(self):
self.run()
def run(self):
while True:
data = self.recv(2000)
if data:
msg = self.decode(data)
print msg
#break;
def decode(self, data):
return pickle.loads(data)
class bullet_server:
def __init__(self):
self.server = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
self.server.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
def start(self):
server_address = ("localhost", 9006)
print '/--server running--/'
print server_address
self.server.bind(server_address)
self.server.listen(5)
while True:
connection, client_address = self.server.accept()
c = client(connection)
c.start()
if __name__ == '__main__':
server = bullet_server()
server.start()
##
#client script:
# set IP and port
host = '127.0.0.1'
port = 9006
# connect to server
connection = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
connection.connect((host, port))
def loop():
print 'Enter message:'
msg = raw_input()
encoded = pickle.dumps(msg)
connection.send(encoded)
loop()
loop()
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Re: How to check client shutdown?
On Tue, Aug 27, 2013 at 5:45 AM, Paul Pittlerson wrote: > I'm currently learning about the socket module. My question is how can I > detect if a connection is closed from the other side, for example a > KeyboardInterrupt as I frequently use. My code below: > Once the remote end has terminated (as it will presumably do in this case), any attempt to write to the socket will eventually result in an error. You should be able to see that by simple experimentation. Be aware that it might take a bit of time for the error to filter back to you; it depends on whether the remote end actually sends back a RST (reset) packet or not. (In a sane system, hitting Ctrl-C should result in a clean shutdown and proper socket closure, but your server needs to handle the case where it doesn't get one.) Play around with it, you should be able to figure out what it's doing for you. A couple of tangential comments about your script: > ## > #server script: > > def decode(self, data): > return pickle.loads(data) MAJOR security issue here. You are taking data from a networked source and running it through a trusting system (pickle). This is NOT recommended. Also: You're using a stream socket, and depending - I think - on getting an entire message in a single read() call. This is definitely not guaranteed, though when you're working with localhost it's likely to be true. To make this reliable, you'll need to do something like prefix the message with its length (eg a Hollerith string), or use some system like JSON that lets you detect the end of the message. >From the client: > def loop(): > print 'Enter message:' > msg = raw_input() > encoded = pickle.dumps(msg) > connection.send(encoded) > loop() > > loop() Why recurse? Why not simply loop? No Python has tail-call optimization (as far as I know), so this will eventually blow up with a RuntimeError: maximum recursion depth exceeded. ChrisA -- http://mail.python.org/mailman/listinfo/python-list
Re: How come StopIteration.__base__ is not BaseException?
On Mon, Aug 26, 2013, at 15:37, Marco Buttu wrote: > Since StopIteration is not an error, how come does it inherit directly > from Exception and not from BaseException? The reason KeyboardInterrupt and SystemExit inherit from BaseException is because you often want them to escape (allowing the program to quit) from code that would otherwise catch them (by catching Exception). On the contrary, StopIteration is almost always used in a context that catches it specifically. -- http://mail.python.org/mailman/listinfo/python-list
Re: Which DLL did fail to load
> Wouldn't it > better to add a feature to Python to write the name of DLL which load > has been failed? If you start Python with the -v (verbose) flag, you can see all the calls to dlopen. -- http://mail.python.org/mailman/listinfo/python-list
Re: How to check client shutdown?
On 26/08/2013 20:45, Paul Pittlerson wrote: I'm currently learning about the socket module. My question is how can I detect if a connection is closed from the other side, for example a KeyboardInterrupt as I frequently use. My code below: [snip] When reading from a socket, it'll return as much data as is available, up to the given limit if specified. If _no_ data is available, then it'll block, unless the socket has been closed at the other end, in which case it'll return zero bytes (an empty bytestring). -- http://mail.python.org/mailman/listinfo/python-list
Re: How to check client shutdown?
On 2013-08-26, Paul Pittlerson wrote: > I'm currently learning about the socket module. My question is how > can I detect if a connection is closed from the other side, recv() will return an empty value of ''. send() will eventually throw an exception. [You may be able to call send() once or twice after the connection has been closed without getting the exception.] On Linux the exception is socket.error with errno 32 (broken pipe). -- Grant Edwards grant.b.edwardsYow! Is this an out-take at from the "BRADY BUNCH"? gmail.com -- http://mail.python.org/mailman/listinfo/python-list
Re: Checking homogeneity of Array using List in Python
On 26 August 2013 14:49, Neil Cerutti wrote:
> On 2013-08-25, sahil301...@gmail.com wrote:
>>
>> eg. my input is ['1', ' ', 'asdasd231231', '1213asasd', '43242']
>> I want it to be interpreted as:
>> [1, [None], [None], [None], 43242]
>>
>> NOTE: NO INBUILT FUNCTION BE USED.
>
> Impossible. I think.
class BoilerplateToStopCheating:
def __init__(self):
"""Factor things out to prevent cheating."""
self.digit_to_number = {"0":0, "1":1, "2":2, "3":3, "4":4,
"5":5, "6":6, "7":7, "8":8, "9":9}
def __call__(self, items):
def fudging():
"""More cheat-fudging."""
for item in items:
try:
as_number = 0
for char in item:
as_number *= 10
as_number += self.digit_to_number[char]
yield as_number
except KeyError:
yield [None]
[*z] = fudging()
return z
converter = BoilerplateToStopCheating()
# Can't use "print"...
# Erm...
converter(['1', ' ', 'asdasd231231', '1213asasd', '43242'])
# Output: [1, [None], [None], [None], 43242]
--
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Imaplib & Gmail - cannot move from inbox to custom folder (message remains in both)
I am using Imaplib and connecting to a Gmail account. I am issuing commands to copy the email to a custom folder then issuing delete. After expunge message still remains in inbox and customer folder. # COPY EMAIL TO FOLDER copyStatus = m.copy(emailid, 'CIRIMPORTED') print 'id of message copied is: %s status: %s' % (emailid,copyStatus) # SET THE MESSAGE TO HAVE '\Deleted' FLAG (EXPUNGE WILL COMPLETE DELETE PROCESS) storeStatus = m.store(emailid,"+FLAGS", r'(\Deleted)') print 'id of message stored is: %s status: %s %s' % (emailid,storeStatus[0],storeStatus[1]) #print '**' #DELETES ANY EMAIL MARKED \Deleted m.expunge() m.close() m.logout() Does anyone have any imaplib code the works with Gmail to move from inbox to another folder? -- http://mail.python.org/mailman/listinfo/python-list
Re: Imaplib & Gmail - cannot move from inbox to custom folder (message remains in both)
On 27/08/2013 00:34, r...@attoenterprises.com wrote: I am using Imaplib and connecting to a Gmail account. I am issuing commands to copy the email to a custom folder then issuing delete. After expunge message still remains in inbox and customer folder. # COPY EMAIL TO FOLDER copyStatus = m.copy(emailid, 'CIRIMPORTED') print 'id of message copied is: %s status: %s' % (emailid,copyStatus) # SET THE MESSAGE TO HAVE '\Deleted' FLAG (EXPUNGE WILL COMPLETE DELETE PROCESS) storeStatus = m.store(emailid,"+FLAGS", r'(\Deleted)') print 'id of message stored is: %s status: %s %s' % (emailid,storeStatus[0],storeStatus[1]) #print '**' #DELETES ANY EMAIL MARKED \Deleted m.expunge() m.close() m.logout() Does anyone have any imaplib code the works with Gmail to move from inbox to another folder? There's an example in docs which says: M.store(num, '+FLAGS', '\\Deleted') You have: m.store(emailid,"+FLAGS", r'(\Deleted)') Could it be that the flags should be r'\Deleted'? -- http://mail.python.org/mailman/listinfo/python-list
Re: Imaplib & Gmail - cannot move from inbox to custom folder (message remains in both)
On Monday, August 26, 2013 5:56:09 PM UTC-6, MRAB wrote: > On 27/08/2013 00:34, r...@attoenterprises.com wrote: > > > I am using Imaplib and connecting to a Gmail account. I am issuing > > commands to copy the email to a custom folder then issuing delete. After > > expunge message still remains in inbox and customer folder. > > > > > > # COPY EMAIL TO FOLDER > > > copyStatus = m.copy(emailid, 'CIRIMPORTED') > > > print 'id of message copied is: %s status: %s' % > > (emailid,copyStatus) > > > > > > # SET THE MESSAGE TO HAVE '\Deleted' FLAG (EXPUNGE WILL COMPLETE > > DELETE PROCESS) > > > storeStatus = m.store(emailid,"+FLAGS", r'(\Deleted)') > > > print 'id of message stored is: %s status: %s %s' % > > (emailid,storeStatus[0],storeStatus[1]) > > > #print '**' > > > > > > #DELETES ANY EMAIL MARKED \Deleted > > > m.expunge() > > > m.close() > > > m.logout() > > > > > > Does anyone have any imaplib code the works with Gmail to move from inbox > > to another folder? > > > > > There's an example in docs which says: > > > > M.store(num, '+FLAGS', '\\Deleted') > > > > You have: > > > > m.store(emailid,"+FLAGS", r'(\Deleted)') > > > > Could it be that the flags should be r'\Deleted'? I have tried it with the variations on the web of \\Deleted, r'\Deleted, and \Deleted. The Delete works because I see in the status 'Deleted'. However it does not remove from Inbox. -- http://mail.python.org/mailman/listinfo/python-list
Missing something on exception handling in Python 3
I have code in the pylockfile package that looks roughly like this
(apologies for the indentation - I'm growing to dislike Gmail for
typing code fragments):
try:
write_pid_to_lockfile(somefile)
except OSError as exc:
if conditions_i_can_handle:
do_other_stuff...
else:
raise LockFailed("Failed to create %s" % self.path)
Thinking I would just get the final exception (not the one I caught
originally), I was surprised to see this output on my screen:
>>> lock.acquire()
Traceback (most recent call last):
File "lockfile/pidlockfile.py", line 80, in acquire
write_pid_to_pidfile(self.path)
File "lockfile/pidlockfile.py", line 163, in write_pid_to_pidfile
pidfile_fd = os.open(pidfile_path, open_flags, open_mode)
OSError: [Errno 13] Permission denied: '/tmp/skip/lock'
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "", line 1, in
File "lockfile/pidlockfile.py", line 94, in acquire
raise LockFailed("failed to create %s" % self.path)
lockfile.LockFailed: failed to create /tmp/skip/lock
When I rung the same code with Python 2.7, I get the exception output
I anticipate:
>>> lock.acquire()
Traceback (most recent call last):
File "", line 1, in
File "lockfile/pidlockfile.py", line 94, in acquire
raise LockFailed("failed to create %s" % self.path)
LockFailed: failed to create /tmp/skip/lock
It appears exception handling changed in Python 3. How do I suppress
the lower level OSError?
Thx,
Skip
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Re: Missing something on exception handling in Python 3
On 27/08/2013 02:48, Skip Montanaro wrote:
I have code in the pylockfile package that looks roughly like this
(apologies for the indentation - I'm growing to dislike Gmail for
typing code fragments):
try:
write_pid_to_lockfile(somefile)
except OSError as exc:
if conditions_i_can_handle:
do_other_stuff...
else:
raise LockFailed("Failed to create %s" % self.path)
Thinking I would just get the final exception (not the one I caught
originally), I was surprised to see this output on my screen:
lock.acquire()
Traceback (most recent call last):
File "lockfile/pidlockfile.py", line 80, in acquire
write_pid_to_pidfile(self.path)
File "lockfile/pidlockfile.py", line 163, in write_pid_to_pidfile
pidfile_fd = os.open(pidfile_path, open_flags, open_mode)
OSError: [Errno 13] Permission denied: '/tmp/skip/lock'
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "", line 1, in
File "lockfile/pidlockfile.py", line 94, in acquire
raise LockFailed("failed to create %s" % self.path)
lockfile.LockFailed: failed to create /tmp/skip/lock
When I rung the same code with Python 2.7, I get the exception output
I anticipate:
lock.acquire()
Traceback (most recent call last):
File "", line 1, in
File "lockfile/pidlockfile.py", line 94, in acquire
raise LockFailed("failed to create %s" % self.path)
LockFailed: failed to create /tmp/skip/lock
It appears exception handling changed in Python 3. How do I suppress
the lower level OSError?
Do this:
raise LockFailed("Failed to create %s" % self.path) from None
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Re: Missing something on exception handling in Python 3
> Do this:
>
> raise LockFailed("Failed to create %s" % self.path) from None
Thanks. Is there some construct which will work in 2.x and 3.x?
Skip
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TypeError: 'int' object is not callable
dear friends when i try to execute following lines import time a = time.daylight() print(a) result is TypeError: 'int' object is not callable why is this error and how can i solve this problem? -- http://mail.python.org/mailman/listinfo/python-list
Re: TypeError: 'int' object is not callable
Hi, The problem is in the second line. a = time.daylight() The daylight is not a method in time module. It is clear here, http://docs.python.org/2/library/time.html Since it is not a method we cannot call it. It is just a integer variable . It returns zero if DST timezone is not defined and returns non zero if defined. >>> import time >>> a = time.daylight() Traceback (most recent call last): File "", line 1, in TypeError: 'int' object is not callable >>> a = time.daylight >>> a 0 >>> type(time.daylight) Regards, Krishnan On Tue, Aug 27, 2013 at 8:15 AM, wrote: > dear friends when i try to execute following lines > > import time > a = time.daylight() > print(a) > > > result is > TypeError: 'int' object is not callable > > > why is this error and how can i solve this problem? > -- > http://mail.python.org/mailman/listinfo/python-list > -- http://mail.python.org/mailman/listinfo/python-list
Re: Missing something on exception handling in Python 3
On 08/26/2013 07:49 PM, Skip Montanaro wrote:
Do this:
raise LockFailed("Failed to create %s" % self.path) from None
Thanks. Is there some construct which will work in 2.x and 3.x?
Something like this (untested):
exc = None
try:
write_pid_to_lockfile(somefile)
except OSError as exc:
exc = sys.exc_info()[0] # not sure of index
if exc:
if conditions_i_can_handle:
do_other_stuff...
else:
raise LockFailed("Failed to create %s" % self.path)
Since you're raising outside the try...except block you won't see the chained
exception in Python3.
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Phonon error: libv4l2: error getting pixformat: Invalid argument
Here is my code. I'm just trying to play an mp3 that I've clicked in a PyQT
listwidget:
@pyqtSlot()
def item_clicked(self):
row = self.listWidget.currentRow()
song = musiclist[row]
QCoreApplication.setApplicationName("Phonon")
output = Phonon.AudioOutput(Phonon.MusicCategory)
m_media = Phonon.MediaObject()
Phonon.createPath(m_media, output)
m_media.setCurrentSource(Phonon.MediaSource(song))
m_media.play()
I'm running OpenSUSE Linux 12.3
Any ideas?
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Re: Missing something on exception handling in Python 3
I found this question/answer on Stack Overflow: http://stackoverflow.com/questions/15123137 but after fiddling around with it, I can't find a solution that works for Python 3.2 and 3.3, let alone 2.x. In 3.2, exceptions have both __cause__ and __context__ attributes. I tried setting both to None (in 3.2), but I still get the full double traceback: >>> try: 1/0 ... except ZeroDivisionError: ...exc = TypeError() ...exc.__context__ = None ...exc.__cause__ = None ...raise exc ... Error in sys.excepthook: IndexError: tuple index out of range Original exception was: Traceback (most recent call last): File "", line 1, in ZeroDivisionError: division by zero During handling of the above exception, another exception occurred: Traceback (most recent call last): File "", line 6, in TypeError The sys.excepthook error is because I have a custom interactive sys.excepthook, which is itself apparently broken in Python 3.2. I've looked at PEP 409 and 415, but just get more confused. *sigh* Maybe I'll try again tomorrow when I've had a bit of sleep... and take a closer look at Ethan's suggestion. Skip -- http://mail.python.org/mailman/listinfo/python-list
Re: How come StopIteration.__base__ is not BaseException?
On 08/27/2013 08:17 AM, Marco Buttu wrote: But if I want to catch it specifically (except BaseIteration), Sorry, except StopIteration... -- Marco Buttu -- http://mail.python.org/mailman/listinfo/python-list
Re: How come StopIteration.__base__ is not BaseException?
On 08/26/2013 10:10 PM, random...@fastmail.us wrote: The reason KeyboardInterrupt and SystemExit inherit from BaseException is because you often want them to escape (allowing the program to quit) from code that would otherwise catch them (by catching Exception). On the contrary, StopIteration is almost always used in a context that catches it specifically. But if I want to catch it specifically (except BaseIteration), why doesn't it hinerit directly from BaseException? It's not an error and it's not a warning. I would like to see a piece of code in which it is useful to catch it generically with a except Exception clause instead of an except StopIteration... Regards -- Marco -- http://mail.python.org/mailman/listinfo/python-list
