settings file being imported four times
is it normal that the settings file is being imported four times? I'd give
more info, but I really have no clue what's going on
here's my manage.py:
from django.core.management import execute_manager
import imp
try:
imp.find_module('local_settings') # Assumed to be in the same directory.
except ImportError:
import sys
sys.stderr.write("""Error: Can't find the file 'local_settings.py' in
the directory containing %r.
It appears you've customized things.
You'll have to run django-admin.py, passing it your settings module.
(If the file local_settings.py does indeed exist, it's causing an
ImportError somehow.)
""" % __file__)
sys.exit(1)
import local_settings
if __name__ == '__main__':
execute_manager(local_settings)
And I printed a stacktrace at the top of my local_settings file. It does a
'from settings import *' at the top.
lacrymology@Roller:boilerplate$ ./manage.py runserver
local_settings
File "./manage.py", line 15, in
import local_settings
File
"/home/lacrymology/workspace/django/groupsolo/boilerplate/boilerplate/local_settings.py",
line 4, in
traceback.print_stack()
###
local_settings
File "./manage.py", line 18, in
execute_manager(local_settings)
File
"/home/lacrymology/workspace/django/groupsolo/boilerplate/env/local/lib/python2.7/site-packages/django/core/management/__init__.py",
line 438, in execute_manager
utility.execute()
File
"/home/lacrymology/workspace/django/groupsolo/boilerplate/env/local/lib/python2.7/site-packages/django/core/management/__init__.py",
line 379, in execute
self.fetch_command(subcommand).run_from_argv(self.argv)
File
"/home/lacrymology/workspace/django/groupsolo/boilerplate/env/local/lib/python2.7/site-packages/django/core/management/__init__.py",
line 252, in fetch_command
app_name = get_commands()[subcommand]
File
"/home/lacrymology/workspace/django/groupsolo/boilerplate/env/local/lib/python2.7/site-packages/django/core/management/__init__.py",
line 101, in get_commands
apps = settings.INSTALLED_APPS
File
"/home/lacrymology/workspace/django/groupsolo/boilerplate/env/local/lib/python2.7/site-packages/django/utils/functional.py",
line 276, in __getattr__
self._setup()
File
"/home/lacrymology/workspace/django/groupsolo/boilerplate/env/local/lib/python2.7/site-packages/django/conf/__init__.py",
line 42, in _setup
self._wrapped = Settings(settings_module)
File
"/home/lacrymology/workspace/django/groupsolo/boilerplate/env/local/lib/python2.7/site-packages/django/conf/__init__.py",
line 87, in __init__
mod = importlib.import_module(self.SETTINGS_MODULE)
File
"/home/lacrymology/workspace/django/groupsolo/boilerplate/env/local/lib/python2.7/site-packages/django/utils/importlib.py",
line 35, in import_module
__import__(name)
File
"/home/lacrymology/workspace/django/groupsolo/boilerplate/boilerplate/../boilerplate/local_settings.py",
line 4, in
traceback.print_stack()
###
No handlers could be found for logger "keyedcache"
local_settings
File "./manage.py", line 15, in
import local_settings
File
"/home/lacrymology/workspace/django/groupsolo/boilerplate/boilerplate/local_settings.py",
line 4, in
traceback.print_stack()
###
local_settings
File "./manage.py", line 18, in
execute_manager(local_settings)
File
"/home/lacrymology/workspace/django/groupsolo/boilerplate/env/local/lib/python2.7/site-packages/django/core/management/__init__.py",
line 438, in execute_manager
utility.execute()
File
"/home/lacrymology/workspace/django/groupsolo/boilerplate/env/local/lib/python2.7/site-packages/django/core/management/__init__.py",
line 379, in execute
self.fetch_command(subcommand).run_from_argv(self.argv)
File
"/home/lacrymology/workspace/django/groupsolo/boilerplate/env/local/lib/python2.7/site-packages/django/core/management/__init__.py",
line 252, in fetch_command
app_name = get_commands()[subcommand]
File
"/home/lacrymology/workspace/django/groupsolo/boilerplate/env/local/lib/python2.7/site-packages/django/core/management/__init__.py",
line 101, in get_commands
apps = settings.INSTALLED_APPS
File
"/home/lacrymology/workspace/django/groupsolo/boilerplate/env/local/lib/python2.7/site-packages/django/utils/functional.py",
line 276, in __getattr__
self._setup()
File
"/home/lacrymology/workspace/django/groupsolo/boilerplate/env/local/lib/python2.7/site-packages/django/conf/__init__.py",
line 42, in _setup
self._wrapped = Settings(settings_module)
File
"/home/lacrymology/workspace/django/groupsolo/boilerplate/env/local/lib/python2.7/site-packages/django/conf/__init__.py",
line 87, in __init__
mod = importlib.import_module(self.SETTINGS_MODULE)
File
"/home/lacrymology/workspace/django/groupsolo/boilerplate/env/local/lib/python2.7/site-packages/django/utils/importlib.py",
line 35, in import_module
__import__(name)
File
"/hom
Re: Forms for updating a compound model
I'm sorry to tell you that ModelForms don't seem to have this
functionality, but I'm happy to tell you that ModelAdmins do.
What it does, basically, is to return this:
{
'label': label_for_field(field, self.opts.model, self.opts),
'widget': {
'is_hidden': False
},
'required': False
}
when there's a field marked as readonly, so it can transparently be used
from the templates.
I recommend you go look at the code in
django.contrib.admin.helpers.InlineAdminFormSet to get a feel of what you
can do.
Annd... looking around, I found a ReadonlyWidget, look at the first answer
here:
http://stackoverflow.com/questions/2931884/odd-behavior-in-django-form-readonly-field-widget
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Re: problem with django model method save()
I don't see why wouldn't your model's .save() work, maybe we'd need to see
the model code, but I know you probably want to read this:
https://docs.djangoproject.com/en/dev/topics/forms/modelforms/
once you've implemented a ModelForm, you'd pretty much would just do
form = RoomForm(request.POST)
if form.is_valid():
form.save()
On Wed, Jul 4, 2012 at 3:58 PM, rafiee.nima wrote:
> Hi Im some how new to django . I write a view to handle ajax request
> but I find out that save() method dose not save model instance in to the
> database
> here is my code
>
> def add_room(request):
> context={}
> status=''
> if request.is_ajax:
> if request.POST:
> hotel_instance=Hotel.objects.get(id=request.POST['hotel'])
> room_id=int(request.POST['id'])
> if room_id > 0 :
> room=HotelRoom.objects.get(id=request.POST['id'])
> room.hotel=hotel_instance
> room.number=request.POST['number']
> room.bed_count=request.POST['bed_count']
> room.ground_sleep=request.POST['ground_sleep']
> room.view=request.POST['view']
> room.reserved=request.POST['reserved']
> room.tv=request.POST['tv'].capitalize()
> room.phone=request.POST['phone']
> room.refrigerator=request.POST['refrigerator']
> room.air_condition=request.POST['air_condition']
> room.toilet=request.POST['toilet']
> room.creator=request.user
> room.save()
> room_json=model_to_dict(room)
> status="room successfully updated"
> else:
> room = HotelRoom(
> hotel=hotel_instance,
> number=request.POST['number'],
> bed_count=request.POST['bed_count'],
> ground_sleep=request.POST['ground_sleep'],
> view=request.POST['view'],
> reserved=request.POST['reserved'],
> tv=request.POST['tv'],
> phone=request.POST['phone'],
> refrigerator=request.POST['refrigerator'],
> air_condition=request.POST['air_condition'],
> toilet=request.POST['toilet'],
> creator=request.user )
> room.save()
> status="new room successfully added "
> raw_data={'status':status,'data':room_json}
> data=simplejson.dumps(raw_data)
> return HttpResponse(data, mimetype="application/json")
>
> --
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Re: install a new model in my project
> (django_multiuploader), and i write in INSTALLED_APPS 'sorl.thumbnail',
> 'multiuploader', then i execute manager.py runserver and return "Error: No
> module named multiuploader" I dont understand how make a link for this
> module.
*How* did you install it? are you using pip and a virtualenv?
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Re: migration via south for inheritance change -> please help
You'll have to migrate your data manually in your migration, yes.
Besides that, if you don't want actual Base instances, then this is an
abstract class, and you should do this:
class Base(models.Model):
eggs
plants
class Meta:
abstract=True
class Foo(Base):
carpet=
class Bar(Base):
car=
On Wed, Jul 4, 2012 at 5:18 PM, Lachlan Musicman wrote:
> I'd like to know this too - but I think the real answer is "get better
> at python" - you are essentially (from what I can tell) in a django
> shell when south pops the "not blank, not null but no data" error -
> try pulling in some details from fixtures?
>
> cheers
> L.
>
> On Thu, Jul 5, 2012 at 2:30 AM, Daniel Walz wrote:
>> ...no one?
>>
>> regards, mcJack
>>
>> 2012/7/2 mcJack :
>>> Hi all,
>>>
>>> I've got a problem migrating some changes in the model, so I tried to
solve
>>> it with south.
>>> The situation:
>>> I implemented two classes, which share some functionality. Now that I
>>> improved a little with python, django and co. I wanted to use
inheritance
>>> for that issue.
>>> The model looks like this:
>>>
>>> class Foo(models.Model):
>>> eggs = models.TextField( null=True, blank=True )
>>> plants = models.TextField( null=True, blank=True )
>>> carpet = models.IntegerField()
>>>
>>> class Bar(models.Model):
>>> eggs = models.TextField( null=True, blank=True )
>>> plants = models.TextField( null=True, blank=True )
>>> car = models.IntegerField()
>>>
>>>
>>> And obviously I want to transform to:
>>> class Base(models.Model):
>>> eggs = models.TextField( null=True, blank=True )
>>> plants = models.TextField( null=True, blank=True )
>>>
>>> class Foo(models.Model):
>>> base = models.OneToOneField( 'Base', parent_link=True )
>>> carpet = models.IntegerField()
>>>
>>> class Bar(models.Model):
>>> base = models.OneToOneField( 'Base', parent_link=True )
>>> car = models.IntegerField()
>>>
>>> But how can I tell south to fill the super class with the data from the
old
>>> schema?
>>>
>>> Can I add this information manually in the created migration script? or
is
>>> there an option/switch I didn't notice?
>>>
>>> Any hints are very welcome, thanks a lot
>>>
>>> mcJack
>>>
>>> --
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Groups
>>> "Django users" group.
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>>> https://groups.google.com/d/msg/django-users/-/_6CYJ1yqh-sJ.
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>>
>>
>>
>> --
>> Daniel Walz - mcj...@gmail.com
>> Bremen, Germany
>>
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>
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Re: migration via south for inheritance change -> please help
By the way, if you do that, and I'm not crazy, you won't need to do any migration with south, since the Foo and Bar tables would both have all of base's columns (because Base is abstract). If Base can't be abstract (if you want Base instances that are neither Foo nor Bar), then you'll have to do this: First, create the Base class, without changing Foo or Bar. Create a south migration for this Second, create a south Data Migration, copy all the data over on that migration from Foo and Bar to Base instances Third, modify Foo and Bar, and create migrations for this On Wed, Jul 4, 2012 at 5:29 PM, Tomas Neme wrote: > You'll have to migrate your data manually in your migration, yes. > > Besides that, if you don't want actual Base instances, then this is an > abstract class, and you should do this: > > class Base(models.Model): > eggs > plants > class Meta: > abstract=True > > class Foo(Base): > carpet= > > class Bar(Base): > car= > > > On Wed, Jul 4, 2012 at 5:18 PM, Lachlan Musicman > wrote: > > I'd like to know this too - but I think the real answer is "get better > > at python" - you are essentially (from what I can tell) in a django > > shell when south pops the "not blank, not null but no data" error - > > try pulling in some details from fixtures? > > > > cheers > > L. > > > > On Thu, Jul 5, 2012 at 2:30 AM, Daniel Walz wrote: > >> ...no one? > >> > >> regards, mcJack > >> > >> 2012/7/2 mcJack : > >>> Hi all, > >>> > >>> I've got a problem migrating some changes in the model, so I tried to > solve > >>> it with south. > >>> The situation: > >>> I implemented two classes, which share some functionality. Now that I > >>> improved a little with python, django and co. I wanted to use > inheritance > >>> for that issue. > >>> The model looks like this: > >>> > >>> class Foo(models.Model): > >>> eggs = models.TextField( null=True, blank=True ) > >>> plants = models.TextField( null=True, blank=True ) > >>> carpet = models.IntegerField() > >>> > >>> class Bar(models.Model): > >>> eggs = models.TextField( null=True, blank=True ) > >>> plants = models.TextField( null=True, blank=True ) > >>> car = models.IntegerField() > >>> > >>> > >>> And obviously I want to transform to: > >>> class Base(models.Model): > >>> eggs = models.TextField( null=True, blank=True ) > >>> plants = models.TextField( null=True, blank=True ) > >>> > >>> class Foo(models.Model): > >>> base = models.OneToOneField( 'Base', parent_link=True ) > >>> carpet = models.IntegerField() > >>> > >>> class Bar(models.Model): > >>> base = models.OneToOneField( 'Base', parent_link=True ) > >>> car = models.IntegerField() > >>> > >>> But how can I tell south to fill the super class with the data from > the old > >>> schema? > >>> > >>> Can I add this information manually in the created migration script? > or is > >>> there an option/switch I didn't notice? > >>> > >>> Any hints are very welcome, thanks a lot > >>> > >>> mcJack > >>> > >>> -- > >>> You received this message because you are subscribed to the Google > Groups > >>> "Django users" group. > >>> To view this discussion on the web visit > >>> https://groups.google.com/d/msg/django-users/-/_6CYJ1yqh-sJ. > >>> To post to this group, send email to django-users@googlegroups.com. > >>> To unsubscribe from this group, send email to > >>> django-users+unsubscr...@googlegroups.com. > >>> For more options, visit this group at > >>> http://groups.google.com/group/django-users?hl=en. > >> > >> > >> > >> -- > >> Daniel Walz - mcj...@gmail.com > >> Bremen, Germany > >> > >> -- > >> You received this message because you are subscribed to the Google > Groups "Django users" group. > >> To post to this group, send email to django-users@googlegroups.com. > >> To unsubscribe from this group, send email to > django-users+unsubscr...@googlegroups.com. > >> For more options, visit this group at
Re: cannot access admin
ah, got it... your
url(r'^(\S+)/(\S+)', 'tacobakedotnet.dotnet_forms.views.home'),
is too permisive
On Wed, Jul 4, 2012 at 6:54 PM, Scott Somers
wrote:
>
> /Local Python Source Code/tacobakedotnet
> manage.py
> settings.py
> urls.py
> /Local Python Source Code/tacobakedotnet/media
> JavaScript files
> /Local Python Source Code/tacobakedotnet/dotnet_forms
> models.py
> tests.py
> views.py
> /Local Python Source Code/tacobakedotnet/dotnet_forms/static
> CSS files
>
> What it is having a hard time finding is
>
> So
>
> http://127.0.0.1:8000/source-code/c++ works
>
> and http://127.0.0.1:8000/admin/ actually works too
>
> But when I try and access anything inside the admin I get article not found.
>
> Now, and this might be interesting if I go
> http://127.0.0.1:8000/admin/sfsdfdsfsfd just doing gibberish it gives me the
> ArticleNotFound, as opposed to say 404, which it does if you do something
> that violates urlconf. So basically the database got corrupted somehow is
> that what happened?
>
>
>
> On Wednesday, July 4, 2012 2:05:22 PM UTC-4, Melvyn Sopacua wrote:
>>
>> On 4-7-2012 19:18, Scott Somers wrote:
>>
>> > My urls
>> >
>> > urlpatterns = patterns('',
>> > (r'^media/(?P.*)$', 'django.views.static.serve',
>> > {'document_root': settings.MEDIA_ROOT }),
>> > )
>> >
>> > urlpatterns += patterns('',
>> > url(r'^$', 'tacobakedotnet.dotnet_forms.views.home'),
>> > url(r'^(\S+)/(\S+)', 'tacobakedotnet.dotnet_forms.views.home'),
>>
>> It looks like you have the project name in the view, which suggests the
>> current working directory of the project is one directory too high.
>> Could you show the directory layout, including the location of
>> settings.py, admin.py for the app and views.py.
>>
>> --
>> Melvyn Sopacua
>>
>>
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Re: cannot access admin
On Wed, Jul 4, 2012 at 7:33 PM, Tomas Neme wrote:
> ah, got it... your
>
> url(r'^(\S+)/(\S+)', 'tacobakedotnet.dotnet_forms.views.home'),
>
> is too permisive
...
maybe?
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Re: migration via south for inheritance change -> please help
I wanted to chang the subject because I didn't want to spam someone's
plead for help into a design discussion, but then I thought, how am I
gonna make sure this is read by the right people? Also, context would
be lost, so.. sorry about this
But I don't see how what you say makes sense.
I mean, all the way starting from this:
> No, you /should/ not. You may do this, but you will end up with two
> tables that /do not share the records/.
> From the OP's post it's obvious these classes share the data. Think of
oh, yeah, completely obvious, of course. It's plain that Foo and Bar
are just MEANT to be just subtypes of Base, you can tell just from the
names!
Sorry, I don't mean to sound cocky, but you're making a hell of an
assumption about what Foo and Bar and Base are, here, and *I* and
making a completely different, but I think by no means less acceptable
one: that he just wants to share his python code.
> Base as a table 'fruit' and the other two as apples and oranges. In this
> case it doesn't make sense to duplicate the fruit data in the apples and
> oranges table.
As I said before, the only thing this *really* depends on is in this
question: do you need to be able to do something in the lines of:
Fruit.objects.all()? And even more so: will you EVER do fruit =
Fruit()? If not, there's no difference whatsoever, except you'd be
littering the database namespace with a useless table.
Very big apps, like, say django-blog-zinnia use abstract classes for
the ease of extension and share of information for VERY concrete
concepts like EntryBase, which defines all the fields the app uses in
it's views, so a user can define their own Entry(EntryBase) class.
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Re: ForeignKey on CharField and char operations
I might not be understanding this fully, but what about
A.objects.filter(type__mnemo__startswith="type1")?
On Thu, Jul 5, 2012 at 7:51 AM, Serg Shtripling wrote:
> Hello, community!
> Have anyone tried this:
> class AType(models.Model):
> #cut
> mnemo = models.CharField(u'Mnemocode', max_length=31, null=True,
> unique=True)
>
> class A(models.Model):
> #cut
> type = models.ForeignKey(AType, 'mnemo', verbose_name=u'A Type',
> null=True)
>
> class B(models.Model):
> #cut
> type_mnemo = models.CharField(u'A Type', max_length=31, null=True,
> blank=True)
> Mnemos = {type1, type1__plus, type1__minus, type2, type2__plus,}
> Now I want to get all A records, having AType starts with "type1", eg:
> "type1,type1__plus, type1__minus"
>
> r = A.objects.filter(type_id__startswith='type1')
> And got:
> TypeError: Related Field has invalid lookup: startswith
> As a workaround, I've replaced A model with B model - I do not have a
> relation, but query works as expected.
> Q: 1)Is it OK, that A.type_id, not just A.type field is a Related Field?
> q=AType.objects.all()[0]
type(q.type)
>
type(q.type_id)
>
> 2) Is there a more correct way to solve this issue?
>
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Re: migration via south for inheritance change -> please help
> Not really. But from the question:
> "But how can I tell south to fill the super class with the data from the
> old schema?"
Well, in aswer to this, and Tom's remarks, you assumed he wanted to
have a new table because he was asking how to populate it, I assumed
he maybe doesn't know about abstract models because he said he's just
getting started programming (or at least on py/dj) and maybe he wasn't
sure what behavior he needed, and what were his options. I *do* start
saying "if you don't want Base instances".
and from Tom's:
> In the example, it is evident that the OP wants MTI, since he includes
> the foreign key links in the class definition - there is no clearer
> indicator than this!
The evidency of this gets flimsy, AFAICS, if you take in consideration
that he's refactoring code, and having two separate tables was good
enough for him until he "got a little better with python and django".
So, yes, this goes down, I think, if at any point he has a view where
he joins both groups of objects.
> And you're spreading records over two different tables and making it
> impossible to enforce uniqueness on shared attributes. So it's not just
> about creating an instance.
tru dat..
And yeah, the holy war wouldn't be on inheritance types, but rather on
reading comprehension, it seems ;)
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Re: ForeignKey on CharField and char operations
> Wouldn't it create INNER JOIN query on a_type table? AFAIR it would and it's
> a bit overhead.
> But surely it is a better solution than mine one, thanks for that.
Well, in that case, I think your problem is that your AType PK isn't
the mnemo field, but some integer field, so type_id is integer, not
string.
Try defining it as
mnemo = models.CharField(u'Mnemocode', max_length=31, null=True,
unique=True, primary_key=True)
but I'm not sure if this is the behavior you want
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Re: ForeignKey problem
> But! I do have another problem. Lets ditch our football example. Let's say
> that I have something like that:
>
> class CherryTree(models.Model):
> name = models.IntegerField()
> cherries = models.ManyToManyField('CherryFruit')
>
> class CherryFruit(models.Model):
> name = models.CharField(max_length=50)
>
> More or less. The point is, I want to ass many CherryFruit to one
> CherryTree. How do I pass the additional information? I suspect this can
> have something to do with the 'through' argument, but I'm probably
> completely wrong. Or do I have to create additional Model, like:
>
> class CherriesOnTree(models.Model):
> name = models.ForeignKey('CherryFruit')
> tree = models.ForeignKey('CherryTree')
> amount = models.IntegerField()
>
> and add each fruit separately? Hope It's clear what I mean :).
well, no, no and no, but interesting anyways.
A tree and it's fruit is the same as a team and it's players.
You'd do
class CherryTree(models.Model):
name = models.IntegerField()
class CherryFruit(models.Model):
tree = models.ForeignKey(CherryTree)
name = models.CharField(max_length=50)
because each cherry belongs to a single tree. You can think of it as a
parent-child relationship, the children are the ones that have the
ForeignKey.
The "through" parameter in a many to many just defines the name of the
table to be used for that "CherriesOnTree" model you put there, which you
wouldn't need to define. Also, the "amount" field would be of no point,
would it?
then you would do this:
# create a new tree
my_tree = Tree("Tree on the corner")
# or maybe get a tree from the database
my_tree = Tree.objects.get(name="Tree on the corner")
# create a new cherry for this tree
cherry = Cherry(tree=my_tree, name="Some Cherry Name")
cherry.save()
## or if you don't need to do anything afterwards, you can simply
Cherry(tree=my_tree, name="Some Cherry Name").save()
a many-to-many would be used, for example, in a classes and students
scenario
Each student goes to many classes, each class has many students, so:
class Class(models.Model):
name = models.CharField(max_length=50)
class Student(models.Model):
name = models.CharField(max_length=50)
classes = models.ManyToManyField(Class)
# create class
math = Class(name="Math")
math.save()
# create student
student = Student(name="Charles")
student.save() # need to save before setting up many to manies
# Charles goes to Math class
student.classes.add(math)
Here an extra table will be created to hold the many-to-many relationships.
I think it's called _class_m2m_student, or something like that.
The through class is used if you want to add some extra data, like for
example, where does a student seat in a particular class, or what other
students he's in groups with in there, see
https://docs.djangoproject.com/en/dev/topics/db/models/#intermediary-manytomany
for more details
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Re: install a new model in my project
> I used pip for install sorl.thumbnail but "multiuploader" it isn't in
> the pip's repo
well, HOW did you install it? you can still tell pip to use a git or
mercurial repository, or a tarbal file, for example
(virtualenv) $ pip install git+git://
github.com/Lacrymology/cmsplugin_s3slider.git#egg=cmsplugin-s3slider
will install a cms plugin I forked that uses the s3 javascript slider
for image galleries in your virtualenv
But anyways, how *did* you install it? your issue is that your python
interpreter is not finding the package
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Re: ForeignKey problem
> I don't understand. It's the same wheel added four times, not four
> different wheels.
I guess you could implement it either way. The thing is that doing it
this way would become complicated at the time you need to define what
is attached where. For Lego pieces, I'd do this:
class LegoType(Model) has a description, maybe a picture, and it's behavior
model LegoPiece has a ForeignKey(LegoType), a ManyToMany to other
LegoPieces (the ones it's connected to).
You'd have one LegoType = wheel, and four LegoPiece who's type would
be wheel. When you defined the Type you'd need a way to link each
model to specific python code that controlled how many pieces it can
connect to, and how, but that's a song for another day.
Then you do LegoPiece.objects.filter(type__name="wheel").count(), and
voila, you have how many wheels you have.
You COULD have enough knowing the amount of pieces of each kind you
have, you'd be modeling something similar to an inventory, but
defining connections in that context would be unnecessarily
complicated, since you'd not only have to count how many pieces you
have of each type, but when you connect one to another, *which one*
are you connecting? one that's free, or one that's connected to
another one? How would you model the connections? Say one brick can
connect to as many as 8 other pieces, 4 on each side, say you have 3
bricks, so you know you can't have more than 24 connecctions, but..
how do you differentiate between A--B C--D--E and A--B--C--D or.. I
don't know how to draw it, but D--A--B D--A--C (A is connected to D on
one side, and to B and C both on the other).
It might be that you can model your needs this way, but AFAICS, it'd
be a lot harder to follow things and keep things consistent in an
Object Oriented way.
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Re: ForeignKey problem
> Thanks, but damn, isn't that overly complicated (for me). Using through
> looks like a easier way, but then I have to add Wheel four times and can't
> just type '4' in some field, since I don't need it to exist in database four
> time, just an information that there are four wheels.
as I said, it depends on what you want. If you want an inventory
(different types of blocks, and how many you have of each) then it's
good enough that way. If you want to model actually building stuff
with legos, it might not be enough, that's all I'm saying.
For an inventory I'd do this:
class LegoPiece(Model) has it's data, plus an IntegerField, total amount..
As I said before, with your car example.. if you just want to know how
many of a part are in a car, Then what you did is enough, then you
could have some cars, and some pieces, say
Cars = (Motorcycle, 4x4, Car)
Parts = (Tire, Transmission, Door)
PartsInCar = ((Motorcycle, Tire, 2),(Motorcycle, Transmission, 1),
(4x4, Tire, 4), (4x4, Transmission, 2), (4x4, Door, 2), (Car, Tire,
4), (Car, Transmission, 1), (Car, Door, 4))
This would achieve a description of how may parts you need to make a given car..
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Re: ForeignKey problem
oh, and the advantage is that you could have a car, for example
car = Car.objects.get(name="4x4")
car.parts.get(name="Transmission").partsincar.amount >> 2
The difference with doing it with another model is that you cannot do
this, for example (or not as easily)
Car.objects.filter(parts__name="Transmission", partsincar__amount=1)
>> Motorcycle + Car
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Re: Returning nothing from a view
Just return an empty response, with a 200 OK code:
return HttpResponse("")
I'm not sure whether you can omit the ""
On Fri, Jul 6, 2012 at 5:44 PM, Larry Martell wrote:
> I have a situation where I'm sending an ajax request to a function
> that updates a row in database. I then want to return control to the
> browser, with no changes to the page that was up. I am not returning
> anything from the function, and it's working the way I want, however I
> get an error in the browser's console:
>
> Failed to load resource: the server responded with a status of 500
> (INTERNAL SERVER ERROR)
>
>
> Is there some was to avoid this error?
>
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Re: migration via south for inheritance change -> please help
> The big difference is, -as I see it- I will not get real polymorphism,
> as the base class would need to do the join on all it's child classes.
> Is that true?
with abstract models you won't get polymorphism at all, in the
database level (this is, you WON'T be able to do Fruit.objects).
You'll mostly just be sharing structure and behavior, saving yourself
some repetition.
With multi table inheritane (MTI) you get three tables, one for Fruits
one for Oranges and one for Apples, Fruits have a row for every Orange
and every Apple, so you can do Fruit.objects.all(). Knowing whether
this is an orange or an apple is trickier, but not too much
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Re: migration via south for inheritance change -> please help
> and I do
> for fruit in Fruits.objects.all(): fruit.rott()
>
> will anything happen at all? I know in C++ this would work... ;-)
>
> on database-level I know how to do it, I just don't know if the django
> abstraction handles this automalically.
I.. don't know. I'd think yes, at least I wonder otherwise how does
the DB keep coherent if you do
BaseModel.objects.filter(foo=bar).delete(). "CASCADE" would deal with
it in PG, but mysql sometimes lacks that, and sqlite doesn't handle
foreign keys at all.
but you probably need to make some tests to make sure. It'd be quite
easy to do it from the shell
> Seems I have too little faith in the capabilities of python ;-)
Yah, and about that.. what you said WOULD work for any Objects of a
subclassed class in python, as it would in C. Actually, since you
don't declare types in python, you don't really know the class of your
parameters unless you ask, it is the concept of duck-typing that gets
used strongliest in python (you ask the parameter to respond to a
certain interface, you don't care what type it is).
The question is not whether python is able to know what the real class
of an object is, but rather whether django knows the real model of an
object it got from a supermodel's table.
my_fruit.apple returns the corresponding Apple instance, and
my_fruit.orange returns the corresponding Orange instance, but if you
call my_fruit.orange on an object that actually represents an Apple,
you'll get an Orange.DoesNotExist exception raised. But this behavior
is lazy (the Orange table doesn't get hit in the database until you do
.orange).
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Re: Problem with DetailView
> Turns out that's the problem. I wanted to use a field from my Car model:
> car_id, so the link on the website would look like:
> www.blablabla.com/cars/3421, where 3421 is the car_id. Unfortunately, the
> car_id is not the same as . Can I achieve something like that with class
what's car_id and why isn't it your PK?
you should post your full models when asking for help, in general.
As a general rule, having a car_id field in a Car model is
unnecessary. Models come with ids of their own by default, you don't
need to define them. If you have IDs of your own that you want to
reflect in your database, first of all, I'd call it just "id", so you
can do my_car.id, my_car.car_id sounds a little bit redundant to my
taste, and secondly, you can define it as id =
models.IntegerField(primary_key=True). If you do that, your pk will be
the ID you defined (you can do this with a CharField as well, I think)
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Re:
Are you importing your listeners.py from anywhere?
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Re:
> No, I'm not. I didn't think I need to...
the only things that are automatically included are your settings
file, your site urls file, and your apps' models file, everything else
depends on you (or them) to include them. For example, if you don't
call admin.autodiscover() sometime soon (your site's urls file is
about the soonest it makes sense to do this, and where it's usually
done), your ModelAdmins won't get registered. Likewise, unless you
include the call to signal.register() (or in your case the @listener
decorator), then your listener never gets registered in the signal.
The signal itself is working because you included it from your models
file in order to .send() it
I don't know exactly why is it working from the shell, I'm guessing
you included something more when you were fiddling in it, that got it
included.
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Re: Problem with DetailView
Man...
> (r'^sets/(?P\d+)/$', SetDetailView.as_view(
> model=Set,
> context_object_name="set_details",
> template_name='data/set_details.html',
> )),
>
> But the site is empty. Here's my extremely simple template:
>
> {% block title %}{{ set.text_name }}{% endblock %}
>
> {% block content %}
> Set:
>
> {{ set.theme }} - {{ set.subtheme }}
> {% endblock %}
and where, pray, would that 'set' variable be populated when you very
explicitly told the DetailView you wanted your context object named
'set_details'?
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Re: urlpatterns
Django isn't able to guess you want your polls urls under a /poll/ path.
To achieve this, you do url inclusion
you define something like polls/urls.py like you did and then do
url(r'^polls/', include('polls.urls'))
then your defined urls will work when prepended with a polls/ path.
You can change that polls to foo, and then the same views will work
under 'foo/' path (localhost:8000/foo/1/results will show the results
for poll#1 and so on)
On Sun, Jul 8, 2012 at 3:21 PM, Seyfullah Tıkıç wrote:
> Yes, in tutorial it is said to be done so. I expect it works as follows,
> after the commented lines.
> urlpatterns = patterns('',
> url(r'^$',
> ListView.as_view(
> queryset=Poll.objects.order_by('-pub_date')[:5],
> context_object_name='latest_poll_list',
> template_name='polls/index.html')),
> url(r'^(?P\d+)/$',
> DetailView.as_view(
> model=Poll,
> template_name='polls/detail.html')),
> url(r'^(?P\d+)/results/$',
> DetailView.as_view(
> model=Poll,
> template_name='polls/results.html'),
> name='poll_results'),
> url(r'^(?P\d+)/vote/$', 'polls.views.vote'),
> )
> urlpatterns += patterns('',
> url(r'^admin/', include(admin.site.urls)),
>
> 2012/7/8 Mario Gudelj
>>
>> But you've commented out all your URLs that start with /polls/, like
>> url(r'^polls/$', 'index')... r'^polls/$' will resolve to
>> http://127.0.0.1:8000/polls/, for example.
>>
>> -m
>>
>>
>> On 8 July 2012 23:01, Seyfullah Tıkıç wrote:
>>>
>>> http://127.0.0.1:8000/polls/34/
>>> http://127.0.0.1:8000/polls/
>>> http://127.0.0.1:8000/polls/34/results/
>>> 2012/7/8 Mario Gudelj
Which url are you trying to access when you get that 404?
On Jul 8, 2012 5:36 PM, "Seyfullah Tıkıç" wrote:
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>>>
>>>
>>>
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Re: Model for ListView needed?
> A queryset returns a /list/ of model instances. Thus you should queryset
> when you want more then one instance of the model displayed.
well, slightly wrong, let's clarify. While it's true a queryset
represents a list of model instances (it's not EXACTLY that, it's,
more like, a partially set up query that only gets ran when you
actually request the objects), in GenericViews the difference between
setting up a model and a queryset is that setting up model=Post is the
same as setting up queryset=Post.objects.all(). So if you want your
view to act upon ALL Post instances, and you don't care about
ordering, then you can do model=Post and save yourself some typing.
If, however, you want your view to act upon only a SUBSET of objects,
you can use queryset. If, for example, you are making a list of books
made by a specific author, you can do this:
url(r'^books/shakespeare/$',
ListView.as_view(queryset=Book.objects.filter(author='shakespeare')),...
(of course, this isn't the best example, since it'd be much smarter to
make a more specific view that filters authors by a parameter,
something like (r'books/(P\w+)/$')), but it serves as
example)
In the docs' example, the queryset= parameter is used, because they
want the view to show only the latest 5 Polls, hence the
queryset=Poll.objects.order_by('-pub_date')[:5]. If you wanted ALL,
but ordered by -pub_date (and this wasn't the default ordering for the
model), you would use the same queryset, but leaving out the [:5]
part.
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Re: Model for ListView needed?
Oh, and setting up a queryset in a DetailView means that it won't work
for instances that are not inside the queryset, if we did
url(r'/books/shakespeare/(P\d+)/$',
queryset=Book.objects.filter(author='shakespeare')), then
/books/shakespeare/1/ would work if the book with pk=1 was Romeo and
Juliet, but it wouldn't if it was Crime and Punishment (Fedor
Dostoievsky)
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Re: Adding a custom validation to Django's auth_user in admin
> Ah. I think the method is overriding the edit page. In other words, you have
> click on the editpage to see the effect of my fail code. So it doesn't
> trigger if you are on the list view page. Does anyone know what to do with
> the editable submission?
> It should use the same clean_ method, shouldn't it??
if you want this validation everywhere you should probably do
something in the model's .save() method, or even better (to avoid
monkey patching) register into the pre_save signal
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Re: masking only a small part of a template
http://djangosnippets.org/snippets/1376/
this is what you want, I'm using it and it works like a charm
you override in templates/path/to/template.html and do
{% extends "app:path/to/template.html" %}, and this loader searches in
`app`'s template dir by default
On Mon, Jul 9, 2012 at 3:06 AM, tWoolie wrote:
> Sorry, I should have been clearer. What I have is an external project that
> is included "as-is". It has it's templates and it's views are hardcoded
> against the template names.
> I want to know if it's possible to create a template called, say,
> "app/dashboard.html" in the global template dir that then extends
> "app/dashboard.html" in the app's template directory, thereby allowing me to
> change ONLY the block I need to change, without requiring me to copy-paste
> the entire template and re-edit every time I update that app.
>
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Re: rendering modelForms
There's a way, but you'll need to touch the form on the python side
quite a lot, changing the default widgets adding them the css classes
you want.
You can take a look at https://github.com/earle/django-bootstrap and
https://github.com/dyve/django-bootstrap-toolkit/ they provide some
shortcuts for this
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Re: getting variable from __init__ into clean_xxx function
also this:
http://docs.python.org/tutorial/classes.html
On Wed, Jul 11, 2012 at 12:58 PM, Nikolas Stevenson-Molnar
wrote:
> Change nbi_patch to self.nbi_patch, and you should be set. I.e:
>
>
> class PatchForm1(forms.Form):
> def __init__(self, *args, **kwargs):
> self.nbi_patch = kwargs.pop('nbi_patch', None)
> ...
>
> def clean_release_number(self):
> self.nbi_patch #use however you want here
>
> _Nik
>
>
> On 7/11/2012 8:06 AM, Leandro Alves wrote:
>
> Hi,
>
> I'm sending a variable from my views.py and getting it in my forms.py.
>
> My form looks like this now:
>
> class PatchForm1(forms.Form):
> def __init__(self, *args, **kwargs):
> nbi_patch = kwargs.pop('nbi_patch', None)
> super(PatchForm1, self).__init__(*args, **kwargs)
>
> release_number = forms.CharField(label='Release number:')
>
> def clean_release_number(self):
> #nbi_patch = I want to use the nbi_patch var from __init__ here
> release_number = self.cleaned_data.get("release_number")
> path = os.path.join(nbi_patch, release_number)
> if not os.path.exists(path):
> raise forms.ValidationError("Hmm... it looks like %s does not
> exist in nbi-patch." % release_number )
> return release_number
>
> I want to use my var nbi_patch from __init__ inside my
> clean_release_number() function. Is that possible?
>
> I tried pass it as a parameter but it didn't work...
>
> Thanks!!!
>
> Leandro
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Re: Error in blog
Have you done the django tutorial, first? it covers named urls
On Thu, Jul 12, 2012 at 11:06 AM, luthur wrote:
> why not post your example? It's too abstract.
>
> --
> luthur
>
> On Thursday, July 12, 2012 at 9:56 PM, jun wrote:
>
>
>
> On Thursday, July 12, 2012 7:40:46 PM UTC+8, lawgon wrote:
>
> On Wed, 2012-07-11 at 23:29 -0700, jun wrote:
>> I was trying out the blog example in Django by Example but ran into
>> this error:
>> Reverse for 'blog_post_add' with arguments '()' and keyword arguments '{}'
>> not found.
>>
>> I think it has something to do with the urlpatterns since there is
>> no /blog/post/add configuration there, and tried a few variations but
>> nothing worked.
>>
>> What should I do next? Any django docs I can refer to, as in how to
>> link the blog_post_add with the main url?
>
> what version of django are you using - is it the same version that is
> being used in the example?
> --
> regards
> Kenneth Gonsalves
>
> Hi I'm using Django 1.4 now. Understand that the example is using 1.2. Would
> this have an effect?
>
> Regards,
> jun
>
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Re: django-admin.py makemessages issue
"django-admin.py makemessages -l de"
"django-admin.py makemessages -l es"
On Thu, Jul 12, 2012 at 2:59 PM, Phil wrote:
> Hi,
>
> (django version 1.3.1, Python2.7)
>
> (at the end of my settings file)
>
> # translation support
> ugettext = lambda s: s
>
> LANGUAGES = (
> ('en', ugettext('English')),
> ('es', ugettext('Spanish')),
> ('de', ugettext('German')),
> )
>
> LOCALE_PATHS = (
> '/home/phil/project/locale',
> )
>
>
> I am implementing languages into my django website. It's working fine but
> when I run "django-admin.py makemessages" on the command line it gives the
> following error
>
> "Error: This script should be run from the Django SVN tree or your project
> or app tree. If you did indeed run it from the SVN checkout or your project
> or application, maybe you are just missing the conf/locale (in the django
> tree) or locale (for project and application) directory? It is not created
> automatically, you have to create it by hand if you want to enable i18n for
> your project or application."
>
> So like it says, I create the "locale" folder manually then(it's in the root
> of my project directory) run makemessages again but I just get another error
> saying...
>
> "Error: Type 'django-admin.py help makemessages' for usage information."
>
> Any idea's where I could be going wrong?
>
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Re: Tasking? A fluid user experience with Uploading Media.
Well, first of all, you're gonna have to set up quite a big amount of
parallel connections for this to work,
> A new user could be uploading media/music files or something at the same
> time as uploading a video of themselves. I want it to be efficient and fast
> to the point where it all gets updated but the user can leave this task
> going and leave the page that is updating the file and just check back in
Well, this whole part, I don't see happening, because you need to have
some application on the client side sending the data, this is usually
the browser, which unless it stays on the sending page, will close all
outstanding connections to your server. You'd need a client-side
application for something like this to work, like Picasa and Dropbox
do. I also would recommend against letting users upload more than one
file at any given time, because multiple files per client means
multiple connections. Of course, you could add a "send file" link that
actually only adds stuff to a queue, but again, this will always
depend on the browser page not being closed, or changed, not even
refreshed, I've seen this worked-around with popups (have the popup
window handle the connection, so the user can keep browsing on his
main window, but he cannot close the popup, in that case).
As for the actual solution tools for your problem, I don't know them,
but I do know enough to just mark that thing up there
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Re: ajax loading html
an "html page" can't be located within the templates directory, an
HTML file might, but what is it you want to do, exactly? you want to
render a static file? does it make sense going through django for
this?
URLs point to views, not templates, the views are which decide what
templates to use (the same view could use different templates in case
there's errors, or depending on whether the user is logged in or not,
for example).
In any case, you should set up an URL to make your ajax call to, if
you want to go through django for this, something like
url(r'path/to/tip/$',
TemplateView.as_view(template="path/to/template.html"),
name="ajax_tooltip")
docs on the matter of TemplateViews:
https://docs.djangoproject.com/en/dev/ref/class-based-views/base/#django.views.generic.base.TemplateView
If you don't want to write an url for this, then you don't want to
handle it through django. If that's the case, as someone explained,
you can just put the html file somewhere OFF your templates directory,
and have your webserver (apache, or nginx, or whatever you're using)
serve that url by itself (you'll still have to set up the URL in the
webserver's config files)
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Re: ajax loading html
On Sat, Jul 14, 2012 at 2:11 PM, ledzgio wrote:
> If I use the TemplateViews method, should I have to set anything on the
> views.py? and how can I point that file from template?
the TemplateView is a view, it's already been written for you, so you
can use it without adding anything new. If you want to add some custom
behavior to it, you can subclass it, or skip it completely and make a
new view, either out of mixin classes, or function-based (though that
method's being deprecated in the future). That you'd usually do in
your views.py file (bearing in mind that it's not mandatory that it's
called that, it's just a convention), but for this case (at least as
far as you've described it) I don't think you need any specific
behavior.
And how can you point what file from which template?
That being said: My real recommendation would be go do the tutorial
and understand the concepts. Then go read about Class-based views, and
understand all that on a conceptual level, as well.
I.. don't mean to sound harsh, but all your questions and the place
they seem to point to give out a feeling that you're not really
understanding django and it's underlying concepts, it'll be very hard
for you to ask the right questions unless you figure it out first, and
even harder for us to answer them.
A template is just some text that can be mixed with some programming
structures (loops, ifs, and other template tags and filters) and
variables. The HTML you actually send the client could be (and usually
is) built from a mixture of a number of different templates, so you
should get yourself rid of that concept of "HTML page" = "template
file" you seem to be carrying.
At this point, I think the best thing you could do is be a little more
explicit, tell us what you're trying to do, possibly paste some models
and urls files
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Re: satchmo and django-admin-tools
Yes, you'll need to get your hands dirty, and merge the two admin
templates, since both apps redefine templates/admin/index.html and
some other templates.
The best approach, I think, is just use django-admin-tools' templates
and create custom dashboard/modules to duplicate satchmo's templates'
behavior
On Sun, Jul 15, 2012 at 7:12 PM, אברהם סרור wrote:
> Hi,
>
> I'm trying to use django admin tools with satchmo, I installed satchmo in my
> dev machine and made a store with clonesatchmo.py
> after that the store seemed to be running fine, so I installed
> django-admin-tools using the instructions on their website
>
> but I didn't manage to make it work, I spent about a week googling, I think
> I must be doing some obvious mistake
>
> anyone had success using both together? where can I see an example
> settings.py?
>
> Also I have in mind grappelli, can the three work together?
>
> any help is appreciated
> thanks
>
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Re: Is Tutorial / Part 4 wrong? (or is it me?)
It's the second time this issue appears in the list in two weeks, maybe
it's time to recheck the tutorial?
There's no "polls" in your results' url, doesn't the tutorial say you
should have two urls file? one in project/urls.py and another one in
polls/urls.py ?
the polls-specific urls shouldn't start with "^polls/" and be in
polls/urls.py, and in project/urls.py there should be a line with
url(r'^polls/', include('polls.urls')),
On Mon, Jul 16, 2012 at 1:59 PM, Bill Torcaso wrote:
>
> Django is great, and the tutorial is great. I'm having a problem at the
> very end of tutorial-4.
>
> I try to use generic views, and I get an error when I Redirect from the
> POST request in vote() to the Results page. Details below.
>
> The tutorial code says to put this in my urls.py:
>
> url(r'^(?P\d+)/results/$',
> DetailView.as_view(
> model=Poll,
> template_name='polls/results.html')
> ,name="poll_results"
> ),
>
> And this in my views.py:
>
> from django.shortcuts import get_object_or_404, render_to_response
> from django.http import HttpResponseRedirect, HttpResponse
> from django.core.urlresolvers import reverse
> from django.template import RequestContext
> from polls.models import Choice, Poll
>
>
> def vote(request, poll_id):
> p = get_object_or_404(Poll, pk=poll_id)
> try:
> selected_choice = p.choice_set.get(pk=request.POST['choice'])
> except (KeyError, Choice.DoesNotExist):
> # Redisplay the poll voting form.
> return render_to_response('polls/detail.html', {
> 'poll': p,
> 'error_message': "You didn't select a choice.",
> }, context_instance=RequestContext(request))
> else:
> selected_choice.votes += 1
> selected_choice.save()
> # Always return an HttpResponseRedirect after successfully dealing
> # with POST data. This prevents data from being posted twice if a
> # user hits the Back button.
>
>
>
> return HttpResponseRedirect(reverse('polls_results', args=(p.id
> ,)))
> ### OKAY:return HttpResponseRedirect("/polls/%i/results" %
> p.id)
> ### OKAY:return render_to_response("polls/results.html",
> {"poll": p})
> ### BAD: return
> HttpResponseRedirect(reverse('polls.views.results', args=(p.id,)))
>
>
>
> NoReverseMatch at /polls/4/vote/
>
> Reverse for 'polls_results' with arguments '(4,)' and keyword arguments
> '{}' not found.
>
> *Request Method:*
>
> POST
>
> *Request URL:*
>
> http://127.0.0.1:8000/polls/4/vote/
>
> *Django Version:*
>
> 1.4
>
> *Exception Type:*
>
> NoReverseMatch
>
> *Exception Value:*
>
> Reverse for 'polls_results' with arguments '(4,)' and keyword arguments
> '{}' not found.
>
> *Exception Location:*
>
> /Library/Python/2.7/site-packages/django/core/urlresolvers.py in
> _reverse_with_prefix, line 407
>
> *Python Executable:*
>
> /usr/bin/python
>
> *Python Version:*
>
> 2.7.1
>
> *Python Path:*
>
> ['/Users/s3/Desktop/CODE/APPSS3/EdAssistant/experiments/djtest',
>
>
>
> '/Library/Python/2.7/site-packages/mercurial-2.0.2-py2.7-macosx-10.7-intel.egg',
>
>
> '/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python27.zip',
>
> '/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7',
>
>
>
> '/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/plat-darwin',
>
>
>
> '/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/plat-mac',
>
>
>
> '/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/plat-mac/lib-scriptpackages',
>
>
> '/System/Library/Frameworks/Python.framework/Versions/2.7/Extras/lib/python',
>
>
>
> '/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/lib-tk',
>
>
>
> '/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/lib-old',
>
>
>
> '/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/lib-dynload',
>
>
>
> '/System/Library/Frameworks/Python.framework/Versions/2.7/Extras/lib/python/PyObjC',
>
> '/Library/Python/2.7/site-packages']
>
> *Server time:*
>
> Mon, 16 Jul 2012 11:53:21 -0500
>
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Re: satchmo and django-admin-tools
> I thought they extended the templates instead of trying to replace
> everything
they don't replace everything. But the admin site's index template is
called 'admin/index.html', so it's not easy to extend them. They DO
extend admin/base.html.
This is my dashboard.py file, where I create a module that emulates
satchmo's template additions.
https://gist.github.com/3124534
There's a couple of things that are MY PREFERENCES, so it might not
all be to your liking, please do try to read, understand, and modify
as you like.
with this, I just use dashboards' admin/index.html template
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Re: satchmo and django-admin-tools
> thanks for sharing, I'll try to understand it.
>
> where should I put this file? inside localsite?
>
> what admin template are you talking about? the admin tools or the plain
> admin?
dashboard's (it's part of admin_tools) admin/index template.
> I thought of using the admin tools templates and building from that, but all
> I got was noReverseMatch erros, looks like the INSTALLED_APPS order is
> significative and I don't understand it well.
well, I should probably just point you to this:
http://django-admin-tools.readthedocs.org/en/latest/index.html
and specifically this:
http://django-admin-tools.readthedocs.org/en/latest/quickstart.html
You probably didn't add dashboard to INSTALLED_APPS and you're
probably missing the urls as well.
> how can I configure it to ignore the satchmo admin templates?
and some of django's documentation as well..
https://docs.djangoproject.com/en/dev/ref/templates/api/#loading-templates
The short version is, usually, you put under
yourproject/templates/admin/index.html whatever template you want to
be used, but do go and read those docs
> btw, could I make all this work with grappelli? it seems I could enjoy some
> of the image uploading and wysiwyg editor
you can most probably make everything work with everything, I don't
know what grappelli is, bear in mind you might need to dig deep in the
admin templates to make javascript (specially jquery) play nice with
every app you use
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Re: Directory indexes are not allowed here. for Grappilli
On Mon, Jul 16, 2012 at 2:56 PM, Dott. Tegagni Alessandro
wrote:
>
> write the urls.py code and var. static in settings.py, please.
do as he says.
Also you could try asking the grapelli user group, if there is one,
this seems to be specific
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Re: Tutorial question
> Do these just get stuck onto the end of my class Poll(models.Model):? like
> this...
Yes, that's right
perhaps you should start here:
http://docs.python.org/tutorial/classes.html
you should probably at least be comfortable enough with python to know
how to define classes before diving into django
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Re: Prepopulating a contact form
user = request.user
initial = {}
if user.is_authenticated:
initial.update({ 'name': user.name, 'email_address': user.email_address
})
form = MyContactForm(initial=initial)
On Wed, Jul 18, 2012 at 11:23 AM, Sithembewena Lloyd Dube
wrote:
> Hi everyone,
>
> I have a contact form in my app and would like to prepopulate it with user
> details where a user is logged in. Basically, I do the following:
>
> reg_user = get_registered_user(request)
> # get my form object
>
>
> I would like to do something like:
> if reg_user:
> my_form.name = reg_user.name
> my_form.email_address = reg_user.email_address
> # and so on ...
>
> Any ideas? Thanks ...
>
> --
> Regards,
> Sithembewena Lloyd Dube
>
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Re: one field of modelForm doesn't being displayed
> You could override your ModelForm's save() method to save some data to that
> field. And then modify the same ModelForm to exclude that field. For example,
or maybe, just maybe, he might show us his model, form, and rendered
html so we can actually help him identify and possibly fix his
problem! ;)
I mean, perhaps he wants to be able to fill that field as well?
But unless we know the type and the output, we won't be able to help you
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Re: Query with 3 models
> {Empresa1, Sucursal1, Platillo1, Horario1},
> {Empresa1, Sucursal1, Platillo2, Horario1},
> {Empresa2, Sucursal1, Platillo1, Horario1}...
I'm guessing the Sucursal1 in the first and third lines are not the same? I
mean, each Sucursal points to only one Empresa, so I'm guessing you want
only the related objects
if this is the case, you can do something like this:
[(empresa, sucursal, platillo, horario) for empresa in
Empresa.objects.all().select_related()
for sucursal in
empresa.sucursal_set.all()
for platillo in
empresa.platillo_set.all()
for horario in
empresa.horario_set.all()]
that if what you want is a list. If you want just to loop through those,
you can do
for empresa in Empresa.objects.all().select_related():
for sucursal in empresa.sucursal_set.all():
for platillo in empresa.platillo_set.all():
for horario in empresa.horario_set.all():
do_something(empresa, sucursal, platillo, horario)
and about the same thing if you want to cycle through them in a template,
in which case you can just pass { 'empresas':
Empresa.objects.all().select_related() } and then loop like above on the
template side
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Re: Can a method call inside save() display its return on template?
> In my models.py I override the save method like this:
>
> def save(self, *args, **kwargs):
> self.directiondb = get_direction_db(self.nod_id1.id,
> self.nod_id2.id)
> get_direction_descr(self.nod_id1.id, self.nod_id2.id)
> get_vrd_code(self.nod_id1.id, self.nod_id2.id)
> self.vrd_id = get_vrd_id(self.nod_id1.id, self.nod_id2.id)
> super(Webrequests, self).save(*args, **kwargs)
>
> and it works fine.
> Is it now possible what get_direction_descr() and get_vrd_code() return to
well, what does get_vrd_code do? why aren't you saving the value
anywhere? same question with get_direction_descr.
The easy answer will be:
self.vrd_code = get_vrd_code(self.nod_id1.id, self.nod_id2.id)
and then use that on the template, but that save() method seems
awfully redundant, so.. can you explain what your model does better?
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Re: Query with 3 models
> Thanks, the first example is exactly that i want. I try it in the Django
> Shell and it works, but; How I show the results in the template?
>
> Maybe I'm wrong, but I try to pass like { 'empresas':
> Empresa.objects.all().select_related() } ,and only can show the 'Empresa'
> attributes on the loop.
>
> I do something like this
>
> {% for a in empresa%}
> a.slogan
> a.descripcion
> a.platillo.fotografia
> {% endfor %}
as I said, you need to do a loop like the one I showed in python, but
in the template
say, for example
{% for empresa in empresas %} {# keeping your plurals straight is good
practice! #}
{% for sucursal in empresa.sucursal_set.all %}
{% for platillo in empresa.platillo_set.all %}
{% for horario in empresa.horario_set.all %}
empresa.slogan
empresa.descripcion
platillo.fotografia
horario.foobar
{% endfor %}
{% endfor %}
{% endfor %}
{% endfor %}
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Re: Can a method call inside save() display its return on template?
You can still do self.something = foobar even if "something" is not a
database Field.
What I mean is, doing self.vdr_code = get_vdr_code() will save it for
THIS INSTANCE and then you can use it in your template.
If you really need this to be only at .save() (instead of, say, at
__init__, because it feels like once the object's been saved this
could be get in object initialization), you just have to make sure
this is the same instance you pass to the template context.
Something like:
myobject.save()
.
render_to_response(template, { 'object': myobject })
then in your template you can do {{ object.vdr_code }}
Although all in all, I *really* hope you have a good reason to use db
backend-specific SQL instead of making a django model of those
DirectionDescr whatever they are
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Re: Boolean always returns False?
why do you have your own User model? Are you sure you're logging in
the right user and loading the right user instance?
On Fri, Jul 20, 2012 at 12:37 PM, Sithembewena Lloyd Dube
wrote:
> Hi everyone,
>
> I have a user model in which i have a newsletter boolean field. When the
> user subscribes to a newsletter, this is checked.
> I am then instantiating that user and checking the property, so that if it
> is False (i.e. unchecked) = I can display a subscription box.
>
> In the model:
> newsletter = models.BooleanField(verbose_name=u'Sign up to the newsletter',
> default=False)
>
> .. and in the view:
> print registered_user.newsletter
>
> The print outputs False even though this same user's 'newsletter' field
> appears checked in the admin. What am I missing?
>
> Thanks.
>
> --
> Regards,
> Sithembewena Lloyd Dube
>
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Re: How is the label_tag's attrs parameter supposed to specified?
{% for field in form %}
{{ field.label
}}{{ field }}
{% endfor %}
although I think the custom form class is not such a bad solution
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Re: How To Display Non-Modal Popup From Resulting Asynchronous Javascript Request
your error's got nothing to do with AJAX. As the very helpful error
message you're getting, there's no URL that matches your requested
path:
> Request URL:
>
> http://127.0.0.1:8000/mediahelp/mediaHelpPopup.html
>
> Using the URLconf defined in streamingmedia.urls, Django tried these URL
> patterns, in this order:
> 1.^mymedia/
> 2.^mediaadmin/
> 3.^mediahelp/ ^$
> 4.^mediahelp/ ^comphelp/$
> 5.^admin/
I don't know where did you get the 'mediaHelpPopup.html' part of your
URL, but it's quite clear it doesn't match any of those urls you've
got set up.
So if you give us some more details on your idea for this popup, where
does the data come from, and why do you feel the need to make a call
to some phantom html file
(https://docs.djangoproject.com/en/1.4/topics/http/urls/, and
especially http://www.w3.org/Provider/Style/URI).
Basically, you need to have a view that renders your popup's HTML, and
that view needs to be linked to an URL.
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Re: How To Display Non-Modal Popup From Resulting Asynchronous Javascript Request
> The current URL, mediahelp/comphelp/mediaHelpPopup.html, didn't match any of
> these.
>
> The code from the comphelp url view is very basic and looks like this:
> def component_help(request):
> view = "component_help"
> dctnry = {}
> reqGET = request.GET.copy()
> if reqGET.has_key('fieldId'):
> field_value = reqGET['fieldId']
> else:
> field_value = "NONE FOUND"
> message = "This is a test message!...FIELD-ID="+field_value
> dctnry['helpdata'] = message
> return HttpResponse(message)
then why are you calling /mediahelp/comphelp/mediaHelpPopup.html?
what exactly do you think that html filename in the end does to your call?
And.. no, I could make a lot of questions trying to lead you slowly to
the answer, but what I really think is that you need to do the
tutorial again, and understand urlconfs, views and templates.
https://docs.djangoproject.com/en/dev/intro/tutorial01/
I'll give you the short of it because I'm not your teacher: what you
actually want to do is call '/mediahelp/comphelp/' and from the view
you'll want to `return render_to_response('mediaHelpPopup.html',
dctnry)`
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Re: ManyToMany relationship with intermediate model and admin list display with each realtion with value as diferent column
> as shown in the picture, this i could do by add a method in the model
> getTienda1 and return the stock and do it for each store, but i want it to
> be created dinamically because the user could create a new store and it
will
> not be there.
>
> so this is my cuestion: can i do that?
Interesting question. You COULD try the following:
in the ProductAdmin ModelAdmin's class' __init__ you can define
list_display like
from store.models import Tienda
for store in Tienda.objects.all():
self.list_display.append('stock_tienda_{id}'.format(id=store.id))
this would give you the list of existing stores at server init time.
and then you could define your Product model's __getattr__ method something
like this:
def __getattr__(self, attr):
base = 'stock_tienda_'
if attr[:len(base)] == base:
return
Product.objects.filter(tienda=Tienda.objects.get(id=attr[len(base):]))
return super(Product, self).__getattr__(self, attr)
this should make the ModelAdmin's hack work
finally, you need a way to add new columns for newly created stores, so
maybe a post_save signal on Tienda objects
@receiver(post_save, sender=Tienda)
def add_to_product_list_display(sender, instance, new, **kwargs):
if new:
# I don't know how to get the ModelAdmin's instance for a given
class,
# but it must be something in django.contrib.admin.site
product_admin.list_display.append('stock_tienda_{id}'.format(id=
instance.id))
you probably need another listener before .delete of stores, and I'm not
certain the __getattr__ hack will work, but this sounds interesting.
Please try on those lines, and let me know if this worked, I'm most
interested
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Re: 'QuerySet' object has no attribute '_meta' ... but I'm not using a QuerySet!
The ArtworkForm AND the full view code would be helpful, yes
also, maybe you'll want to install django-extensions, werkzeug, and
run your devserver with runserver_plus, that'll give you full
debugging capabilities on your browser, and will be able to see what's
each object (that instace object, specifically)
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Re: ignore field during form validation
> class Form(forms.Form):
>
> check = forms.BooleanField(
> required=False,
> )
> # take into account only when 'check' is True
> len = forms.IntegerField(
> min_value=3,
> max_value=5,
> required=True,
> )
>
>
> What I want is to validate the 'len' field only when 'check' is True.
> I could define the clean method of the form and validate the required,
> min_value and max_value stuff only when 'check' is True but the case when
> someone types a non integer value into the input is still there. How could I
> skip that? That check is done by the IntegerField.
well, you could override clean_len() and not do anything in it, and
then override clean() and do your check there.
The only problem is that you won't be able to raise the issue as a
field-specific error
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Re: Can i use django book
While the things on the djangobook are probably still compatible,
they're far of being best practices nowadays, and will lead you down
old and abandoned roads, more times than not.
As it's been said, I'd rather stay by the official docs, they're very
clear and pretty helpful, not purely technical at all.
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Re: REMOVE ME
I'm very sorry. I got completely out of line.
It's just something that irritates me a lot, and I'm not a native
english speaker, and it may be I don't know the actual "value" of the
word, I felt it was more funny than insulting. And I hadn't read your
first reply.
It won't happen again.
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Re: Is there a way to use 'request.user' in a custom template tag without an inclusion tag?
>
> class EditableNode(template.Node):
> def __init__(self, location_name):
> self.location_name = location_name.encode('utf-8').strip("'")
> def render(self, context):
> obj = Placeholder.objects.filter(location=self.location_name)
> if request.user.is_authenticated():
> for x in obj:
> return "%sedit" % (x, self.location_name)
> else:
> for x in obj:
> return x
>
>
>
>
that `request` variable isn't declared anywhere, that's what that "global
name `` does not exist" error mean.
I *think* you've got to use context['user'], try that. Else, try
context['request'].user
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Re: Variable # of fields in a form
maybe this will help?
https://docs.djangoproject.com/en/dev/ref/templates/builtins/#regroup
On Mon, Jul 30, 2012 at 5:06 AM, Alex Strickland wrote:
> On 2012/07/25 12:41 PM, Daniel Roseman wrote:
>
>> You could probably subclass the CheckboxSelectMultiple widget and
>> override the `render` method to get what you want.
>>
>> See the original code here:
>> https://github.com/django/django/blob/master/django/forms/widgets.py#L749
>> unfortunately you'll need to copy-and-paste most of that code but that
>> should give you the output you need while still leaving Django to do the
>> "messy data handling" .
>
>
> Thanks Daniel. I am looking at that code distributed with 1.4, amazing how
> different it is in the head version already.
>
> I think I'll try and do something similar to Select() which caters for
> , and if I can make that work then I'll override the
> render method to suit my layout purposes (try, being the operative word).
>
> If I can make it work nicely it might be nice to upgrade it to the same
> style as the head version and offer it back as a snippet - that looks a long
> way off though!
>
> --
> Regards
> Alex
>
>
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Re: access the state of a Model object prior to it's modification ?
uhm, if you register a listener to the pre_save signal, then you can do
this:
if instance.published:
# the instance about to be saved has the published flag on
dbojb = MyModel.objects.get(id=instance.id)
# did it have it on the database?
if not dbobj.published:
do_stuff()
you probably need to check the "created" argument on the listener that
tells you if the object is a new one, or a modification
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Re: Dynamic forms
Just to be clear, sandeep, jQuery is not java, javascript is not java.
Get yourself clear on that, because it can become a big confusion.
Besides that, yes, without javascript, the only way you've got to do
that, is having the user submit a form where he selects the options,
and then return another form with the appropriate options rendered.
Maybe you can use a form wizard for this
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returning a zip file for download
Down here's the code in which I'm creating a zip file with a bunch of pdf
labels, and returning it on the HttpResponse for the user to DL it.
The weird thing is that I'm getting just a pdf file (ok, I'm testing with a
single file, so I don't know if that's the problem) and I can't set the
downloaded filename to anything (it's always "download")
Can someone see what I'm doing wrong?
files = []
for detail in queryset:
for parcel in
detail.parceldescription_set.select_related().all():
shipment = parcel.shipment
if not shipment.label:
try:
shipment.download_label(args['username'],
args['password'])
except Shipment.Wait:
self.message_user(_("Failed downloading label for "
"shipment {id} because the "
"Canada Post server is busy, "
"please wait a couple of
minutes "
"and try again").format(
id=shipment.id))
files.append(shipment.label.file)
tmp = tempfile.mkstemp(suffix=".zip")
tf = zipfile.ZipFile(tmp[1], mode="w")
for file in files:
filename = os.path.basename(file.name)
tf.write(file.name, filename)
tf.close()
return HttpResponse(open(tmp[1]), mimetype="application/zip")
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Re: returning a zip file for download
OK, I got it working, I'm not sure what the problem was, but calling the
loop variable 'file' was overriding the python default file object class
now I'm doing this:
response = HttpResponse(File(file(tmp[1])),
mimetype="application/zip")
response['Content-disposition'] = ('attachment; '
'filename="{}"').format(os.path.basename(tmp[1]))
return response
and I'm wondering, what happens with that File object after the response is
sent? when does it get closed? isn't there some cleanup code missing?
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Re: Noob question
as Kurtis says, drop the explicit Primary Keys, and drop the hungarian
notation as well (don't declare the variable type on it's name): I
don't need to be reminded that the name of a project will be a string,
it's pretty obvious. Also, python standards talk against using
underscore in class names, so standard naming would be HeaderEnrich
instead of Header_Enrich. Underscores for field names are good. I'd
also use less abbreviations.
also, I'd name the FK on that model just "projeto", since what you'll
get when you do `headerenrichobject.projeto` will be a Projeto object,
not it's ID
Try to forget the underlying database, the ORM is there to abstract you from it.
But all these are style things, the syntax looks good, so it's all
your call, but getting used to standardized style will make your life
easier, as well as the life of people who try to help you in mailing
lists and IRC channels
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showing a second level of indirection in an admin change_form page
Anyone knows of any trick that will let me show a second-level
indirection inline
via a one2one, so ModelA <-FK- ModelB <-one2one- ModelC, and show A,
B-C-B-C-B-C kind of thing?
Maybe I can override the get_formsets in the admin?
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Re: DRYing up my forms.py
But if you subclass the widget, then you'll need to override every
form's widget with
{
forms.DateField: MyDateWidget
}
so overriding and using your own MyDateField would be less verbose and
repetitive
On Sat, Aug 4, 2012 at 6:17 PM, Melvyn Sopacua wrote:
> On 3-8-2012 18:23, Lee Hinde wrote:
>>
>> On Aug 3, 2012, at 9:01 AM, Melvyn Sopacua wrote:
>>
>>> On 3-8-2012 17:37, Lee Hinde wrote:
>>>
self.fields['photo_response'].widget.attrs["class"] = 'date-field
input-small'
self.fields['photo_response'].widget.format = '%m-%d-%Y'
>
>> Thanks, that got me looking in the right place. I think I need to
>> sublcass the widget, since I'm concerned with the display of the data,
>> not how it's saved/stored?
>
> Yes, if the data doesn't need special handling you can stick to
> subclassing the widget.
>
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>
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Re: How to override an attribute?
> There is a class (let's call it Foo) which is a subclass of User.
> Foo has the following line in its Meta:
> proxy = True
if you don't provide full minimal data, it's hard for us to help. If I
had known you were using a proxy model, I'd have proposed something
different.
In general, unless you got a good reason, I'd recommend against
subclassing User, use a profile instead. If you *really* need to
subclass or override it, first go read the docs about overriding the
User class, *and* all the documentation about models and model
inheritance.
Things should be pretty clear, whether you want a proxy model or not,
where in the inheritance tree it should be, and how to set it up.
THEN, if you have some issue with your class schema, you'll be able to
realize what you need, and be sure whether you really need to do what
django is complaining about, or if there's a better way of doing it.
For the time being, I suggest you drop all the Foos and Bars, post
some real code, and explain why do you feel the need to subclass the
User model
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Re: How to override an attribute?
I don't mean to say you shouldn't need to ask questions, I just say
that using or not "proxy" is not a "let's see what happens" choice,
and having the docs read and halfway understood will help you ask *the
right* questions
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Re: multiple profile
Well, it depends on what you want to do exactly, you could create something
like this:
class UserProfile(models.Model):
common_data
class ClientProfile(UserProfile):
specific_data
class StudentProfile(UserProfile):
specific_data
class TeacherProfile(UserProfile):
specific_data
...
AUTH_PROFILE_MODULE = 'appname.UserProfile'
This would ensure that 3rd party apps that don't know about your
3-user-types system work in your site, but whether you do this, or ignore
AUTH_PROFILE_MODULE, you'll have to set up a specific way of creating the
profiles on user creation. Save signals are your friend here, probably,
and/or the views you use to create the different types of user.
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Re: Hot to use widgets with generic views
well, for starters, you won't magically get "on keyup" behavior by
adding something on your backend, you'll need to use ajax for this,
and, depending on your expected number of elements, it might be better
to send everything and do any filtering on the client side (if you're
handling, say, up to a few thousands of records, and not up to tens of
thousands or more).
In any way, you'll need to give your view some parameter to do the
filtering. For this, I'd recommend passing a ?q=keywords GET argument
to your view, and with that in mind, I link you here:
https://docs.djangoproject.com/en/dev/topics/class-based-views/generic-display/#dynamic-filtering
Just do something like that, but instead of using self.args or
self.kwargs, use self.request.GET for the filtering
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Re: New to dj: relational limitations
> On Tue, Aug 14, 2012 at 8:49 PM, Russell Keith-Magee
> wrote:
I'm just glad I didn't come back with a half-assed response
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Re: How well does South work in a team?
Well, if you push without pulling, this might happen, if you always
pull before pushing, then you'd have to manually merge both migrations
(which would probably mean letting the other migration as 001, and
changing yours so it adds your wanted changes on top of THAT
And as an answer: using south is always better than NOT using it
(unless you want to roll out your own migrations system)
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Re: How well does South work in a team?
>> Well, if you push without pulling, this might happen,
>
> *Implicit git usage* :D
Implicit VCS usage, whichever you choose.
If you don't, you shouldn't be doing team work
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Re: How well does South work in a team?
>>> Well, if you push without pulling, this might happen,
>>
>> *Implicit git usage* :D
>
> Implicit VCS usage, whichever you choose.
>
> If you don't, you shouldn't be doing team work
ah, I see now. CVS wouldn't complain in that scenario...
neither would git/hg when you pull, for that case.. yes , you need to
be careful, but it's better than the alternative
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Re: How to create a formset that contains forms with a dropdown? (Crucial)
DropDownMultiple widget
http://djangosnippets.org/snippets/747/
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Re: django makemessages doesn't recognize trans in templates
> For example for this link
>
> {% trans "contacts" %}
>
> I have the msgstr="Contactos". I expect to see "Contactos" in the browser,
> but I still see "contacts". Any suggestion?
1) case-sensitive. Are you sure you haven't translated "Contacts"
instead of "contacts"?
2) fuzzy-mark. I've noticed that if a translation is marked as
"fuzzy", sometimes gettext doesn't use it
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Re: [old question]NoReverseMatch.. I am sorry.
either remove the quotes from {% url 'blog.views.add_comment' %} (so it's
{% url blog.views.add_comment %}) or {% load url from future %}
Loading from future is the better option, I think.
and for future reference:
Reverse for ''blog.views.add_comment'' with arguments '(1L,)' and
keyword arguments '{}' not found.
notice how there's two single quotes there, not a double quote? that's your
clue, right there
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Re: [old question]NoReverseMatch.. I am sorry.
> But I am confused.
> For example,
> the following code needs to add single quote.
>
> {% block content %}
> Add Todo items
https://docs.djangoproject.com/en/dev/releases/1.3/#changes-to-url-and-ssi
also, that won't work with double quotes either, unless you import
future, and a bunch of other things.
Just import url from future, since this will be the default behavior
in the near future
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Re: Full auth solution
> http://www.django-userena.org/
++
I've successfully combined it with django-social-auth to have
facebook/twitter/google/openId login
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Re: Hard time debugging an strange problem
I'd like to see some of your management commands' code.
It smells somewhat like you're running a shell subprocess and not
waiting for it to be done before going on to the next thing
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Re: To Use or Not to Use the admin backend
> Anyway, to the question. Once the models, the intermediate models and
> the interactions between all of them start getting sufficiently
> complex, you will need to put new forms on front. Theoretically, you
I've a question about this. I tried to do something like this, but
using the main capabilities and hacking on the ModelAdmin classes,
changing the formsets and the like, and reusing as much as possible,
including of course the admin templates.
Of course, it wasn't possible. I was trying to do something as simple
as a double-indirection inline, a second-level foreign key, and ended
up just showing a link to the other model's admin page, creating,
indeed, a complex workflow where none was needed.
To what extent and how particularly would one need override a specific
admin page to do this kind of thing? Is reusing the templates at all
possible if you've customized things? Maybe the templates yes, but the
ModelAdmin views are impossible, I was in a hurry so I wasn't able to
do a good diagnosis of what would have been needed to do this.
Tomas
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Django-admin (was: tastypie - some feedback / comments)
Since this came up, are there any more-or-less packaged alternatives
to django-admin? More than twice I've had to give up in something as
simple as rendering two-level FK indirections, lest I wanted to
override most of the ModelAdmin classes.
The thing is that I don't trust myself to be throughout enough with
security and the such when rolling my own.
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Re: Django-admin (was: tastypie - some feedback / comments)
The admin templates and views themselves are convoluted enough (the
price of having them work with anything), and full of enough magic
that it's not really feasible to build on top of them to add the
required capabilities. Maybe adding new admin views would be a
posibility, but what happens when you want an admin page that does not
exactly correspond to a given model? You can usually twist things
around to make it so, but the fact stands that the admin is in the end
just a way of managing the database, and that the user must *really*
know what they're doing to avoid screwing up big time. Maybe careful
permission handling and/or different admin site instances are a
(partial) solution to this, but I haven't played with those myself.
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Re: OR together multiple extra clauses
I haven't done this, so I might be wrong, but...
> queryset.extra(
> where=['unaccent("table_name"."column_name"::text) LIKE
> unaccent(%s)'],
> params=['%%%s%%' % value]
> )
first, wouldn't just setting params=[value] work? furthermore, isn't
that the whole point of the params thing? maybe unaccent(%%%s%%)'
params=[value].
secondly.. wouldn't chaining .extra() methods work?
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Re: Django: language in field description in forms won't change
you probably are using ugettext and should be using ugettext_lazy
On Sat, Sep 22, 2012 at 8:44 PM, Patrick wrote:
> When I change language on my Django-powered site, everything works fine
> except the translation of the field descriptions in the forms. The
> description is still displayed in the old language. Only the forms already
> visited that session are affected.
>
> It seems like some sort of caching problem, but I don't use any caching (as
> far as I know) and all other parts of the site behave as expected (templates
> and random text using django.utils.translaction.ugettext work just fine).
>
> Summarized:
>
> When I open the site and change language, and then visit a form: everything
> works as expected. All text is translated.
> When I visit a form, change language and return to the form: everything is
> translated, but the form stays in the old language.
> Restarting the web server forces the language to change: then Django behaves
> as in (1) for the current session. Until the language is changed again.
>
> Help is appreciated!
>
> Kind regards, Patrick
>
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Re: Making form label a href
> Is there some way to have the form label be a href?
you'll have to change the forms templates to something like
{% for field in form %}
{{
field.label }}
{{ field }}
{% endfor %}
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Re: Facebook like button in django
You should probably start by reading this:
http://developers.facebook.com/docs/reference/plugins/like/
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Re: Facebook like button in django
> I want to create a website facebook like, but real simple and I want to have
> a button that I can give to blogger to add them on their blog entries. It
> have nothing to do with facebook.
Ah! so you want your own "facebook button"!
It'll be mostly a javascript task, rather than django-specific. In
order to protect your users' identities, you won't be giving the
client (blog) an actual HTML form, but rather (like the FB button) a
link to a JS library, and some markup that the library will use to
create an iframe to your website where you'll send the actual rendered
markup
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Re: implement of view
>
> how can i implements now these "def sql(request):" into my html code? pls
> help me...
>
you're saying next to nothing, but I *guess* you could do something like
return render_to_response("sql.html", { 'row': row })
at the bottom of your sql view, and write an sql.html template that
shows it the way you want...
Also, you'll better go on and learn that pyodbc library and how to
pass parameters into your queries, which will protect you against SQL
injection attacks.. and you should probably learn SOME python if
you're going to be coding in it.
And you shuold *really* at least run through the django tutorial at
least once, in order to get a grip on some of the basic django
concepts, like forms and models, which will help you a lot
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Re: implement of view
>> Thank you for your answer. i have chapter 1-4 of
>> http://www.djangobook.com/en/2.0/index.html done, but not much time to go
>> throught the hole book atm. i will try it with your code. :)
the django book is somewhat outdated, and long.
https://docs.djangoproject.com/en/dev/intro/tutorial01/
do that tutorial, it's quite short, you can get through it in a couple of hours.
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Re: Displaying a custom field (PickledObjectField) in the admin
maybe restate the problem, give some more code, show your models, and
your admin files, and someone may be able to help a little
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Re: Displaying a custom field (PickledObjectField) in the admin
Just by the way, I'm looking at django-picklefield code and README
https://github.com/gintas/django-picklefield and it says NOTHING about
a widget, or an admin representation, so.. maybe it's not DESIGNED to
be shown on the admin? it'd make sense, too, since it's.. well, it can
be ANYTHING
On Wed, Oct 24, 2012 at 3:03 PM, Tomas Neme wrote:
> maybe restate the problem, give some more code, show your models, and
> your admin files, and someone may be able to help a little
>
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Re: implement of view
>>> How can i create 2 views on one page?
>>> def sql(request): and def portal(request):
You can't. A View *is* a page. Do the tutorial.
You could use class-based views and have a view that inherits from
both, and combines the contexts (this is _not_ in the tuto)
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Modernizing the Tutorial
Now that function-based views are being deprecated, or at least that
class-based views are being favored, there should be a tutorial with
them in the docs, shouldn't it?
I don't mean replacing the current one, because that'd raise the entry
point a lot, but cloning the original tutorial, but implementing it
with class-based views, possibly placing a link to it in the generic
views docs page, would go a long way towards generating "good" habits
amongst new users, I think.
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Re: Modernizing the Tutorial
> However, there is also scope for a focussed tutorial about class-based views
> in general. IMHO one of the biggest uptake problems around class-based
This is what I meant. Something that brings in, easy and clearly, the
concept of mixins, the different mixins,something that, for example,
take two mixins that alter the context, and combines them, stuff like
that, simple, but useful, and that gives you a glimpse of "real world"
usage and customization.
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Re: 1.5: syntax of AUTH_USER_MODEL
> Thanks, yup! I just figured it out too. I didn't realize all the "apps" are
> in the path as well.
the apps aren't NECESSARILY in the path. Django has a concept of app
label, which is the name of the directory where the models module
exists.
For example, django-cms has plugins, which in order to use, you need
to add to INSTALLED_APPS:
'cms.plugins.text',
'cms.plugins.picture'
but the app label of these plugins are just 'text' and 'picture'
respectively, and the "app model" path to their models are just
'text.TextPlugin', and 'picture.PicturePlugin'.
This is, IMO, the biggest and most stupid problem in django core
design, because it stops you from having an otherwise completely legal
configurations, like having a 'cms.plugins.picture' app alongside a
'myproject.custom.picture' one which might do something completely
different. I.E.: you can't have apps with repeated app labels even if
there's no python path conflict between them.
I don't know what the reason behind this is. I know it allows you to
make a model part of any given app regardless of where it's located
(via Meta.app_label), but this could very easily be extended (in a
backwards-incompatible way, I'm afraid) to require to be the fully
qualified name of the app package
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Re: Django URL pattern - template tags
I'll still answer this just in case. You should have the following in
your urls.py:
urlpatterns += (..,
url(r'(P)\w+/(P)\d+/(P)\[w-]+/', your_view,
name='yoururlname'), )
and then you can have in your template
{{
n.title }}
I hope I didn't make any mistakes.
tomas
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Re: Too many TCP connections
shot in the dark: aren't they connections to the database, maybe?
On Sat, Sep 3, 2011 at 12:56 AM, shacker wrote:
> Hmm, appreciate the feedback, but we don't have KeepAlives enabled on our
> Django servers and it's never been a problem. And remember, the other Django
> site on the same server doesn't have the problem. As for serving lots of
> resources - we're just talking about viewing/saving seven User pages in the
> Admin before we've built up over 600 open TCP connections. This is a small
> and very lightly trafficked site - just a little bit of Admin activity
> triggers this (it's not an end user problem either - I can reproduce it
> easily).
> Thanks.
>
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Re: Initial data for ManyToMany field
Look into formsets. It's what the admin inlines use.
On Tue, Sep 6, 2011 at 5:40 PM, Nan wrote:
>
> Because SymptomeForm is a ModelForm, it will initialize its "parent"
> field as a ModelMultipleChoiceField, which I believe must be
> initialized with a queryset instead of a list.
>
> On Sep 6, 4:30 pm, Thomas49 wrote:
> > Hello,
> >
> > I have two models, and the second contains a ManyToMany relationship:
> >
> > class TypeMedical(models.Model):
> >...
> >
> > class Symptome(TypeMedical):
> > ...
> > parent =
> > models.ManyToManyField(TypeMedical,related_name='Parent',blank=True)
> > ...
> >
> > Then, I use a ModelForm in order to save data.
> >
> > class SymptomeForm(ModelForm):
> > class Meta:
> > model = Symptome
> >
> > When I create a form, sometimes I want to select a field in "parent".
> > How can I do that? I tried many things but nothing works. Ex:
> > sform = SymptomeForm(initial={'parent':["Acupuncture",]})
> >
> > I hope someone can help! Thanks,
> >
> > Thomas.
>
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Re: Initial data for ManyToMany field
> Look into formsets. It's what the admin inlines use.
that is
class TypeMedicalForm(forms.ModelForm):
class Meta:
model = TypeMedical
TypeMedicalFormSet=formset_factory(TypeMedicalForm)
take a look at the django docs for more details
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