Re: DjangoProject

[S D]

Hi Desh,

Welcome to Django :)

Like Adam said, you should unsubscribe from the django-developers mailing
list for now. That list is for people who are actually working on the
Django framework itself.

The django-users mailing list is the one where people who are learning to
use Django communicate.

Have fun + stay safe.


Kind regards,
~ SD


On Tue, Aug 11, 2020 at 6:54 PM Desh Deepak  wrote:

> Hello everyone, I want to developing a django project. Who wants to
> collaborate to do a project and learn django share your github user id for
> github reposetory access.
>
> Live on Heroku
> http://kidszania.herokuapp.com/
>
>
> Thanks
> Desh Deepak
> +91 7011101001
>
>
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> 
> .
>

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Re: Necessary to learn React/ Angular with backend Django

[S D]

Hi Balaji,

You can convert your web app into a PWA to gain maximum benefit. Just look
it up.

Data shows that PWAs are the way to go.



Kind regards,
- SD

On Tue, Jan 7, 2020, 19:47 Balaji Shetty  wrote:

> Hi
>
> Currently i deployed application on pythonanywhere. It is online office
> file management system with around 100 users under 10 different department
> in hierarchical manner.
>
> User and department may increase in future.
>
> Entire application is developed in Django back end.
>
> Used bootstrap for custom report generation.
>
> question arises in My mind is
>
> Is it Necessary to learn and implement in React/ Angular for front end.
>
>
> Because I am comfortable with current implementation.
>
>
> May I know what are gains i may get or what are the disadvantage i may
> suffer in future.
>
> Kindly guide me to avoid future inconvenience.
>
>
> --
> Mr Shetty Balaji
> Asst. Prof.
> IT Department
> SGGS I&T
> Nanded. My. India
>
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> 
> .
>

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URL pattern for URL with query string

[S D]

Hey guys. SOS please. How do I write a URL pattern for a URL like this?

weather/?current_location=-33.927407,18.415747&booking_location=-32.927407,19.415747

When I do reverse(‘weather’, kwargs={‘current_location’: some_value,
'booking_ location’: another_value}) I am getting a NoReverseMatch
exception.


Kind regards,
- SD

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Re: URL pattern for URL with query string

[S D]

Thanks Jason.



Kind regards,
- SD

On Mon, Jan 13, 2020, 16:28 Jason  wrote:

> The url resolver does not include GET query params in a URL, you need to
> add them manually after the string.
>
> for example
>
> url =
> f"{reverse('weather')}/?current_location={some_value}&booking_location={another_value}"
>
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> 
> .
>

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Getting the first item in a dict

[S D]

I have a dictionary which contains one item (“current_location”, which is a
nested dict) and I would like to access that nested dict. However, I cannot
use the key as the code will break if a different key is passed, e.g.
“different_location”.

How can I access the first item in a dictionary without using a key? The
dict looks like this:

`
{'current_location': {'date': '2020-01-27T10:28:24.148Z', 'type_icon':
'partly-cloudy-day', 'description': 'Mostly Cloudy', 'temperature': 68.28,
'wind': {'speed': 10.48, 'bearing': 178, 'gust': 12.47}, 'rain_prob': 0.02,
'latitude': '-33.927407', 'longitude': '18.415747', 'request_id': 31364,
'request_location': 'Current location'}}
`

Kind regards,
- SD

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Re: Getting the first item in a dict

[S D]

I ended up using `dict[next(iter(dict))]`

I am getting the dict as one of two dicts nested in a list from a weather
service API. I do this using a list comprehension to call the API with
coordinates for each location in another list. A mouthful.

`resp = [fetch_api_data(location, request_id) for location in
REQUEST_LOCATIONS]`

I then cycle through the list and, for each dict, persist a WeatherRequest
instance to db like so:

`
for item in weather_data:
data = item[next(iter(item))]
WeatherRequest(
date=data['date'],
request_id=data['request_id'],
request_location=data['request_location'],
type_icon=data['type_icon'],
description=data['description'],
temperature=data['temperature'],
wind_speed=data['wind']['speed'],
wind_bearing=data['wind']['bearing'],
wind_gust=data['wind']['gust'],
rain_prob=data['rain_prob'],
latitude=data['latitude'],
longitude=data['longitude']
).save()
`

Thanks.


Kind regards,
- SD


On Mon, Jan 27, 2020 at 2:51 PM Bill Freeman  wrote:

> Note that these give the only value.  This won't work if you have more
> than one value in the dict, since you won't know which you will get.  Where
> d is the dict:
>
> list(d.values())[0]
>
> or
>
> for i in d.values():
> # use i here
> print(i)
>
> or
>
> d[list(d)[0]]
>
> I'm sure that there are other ways.  There is certainly at least a way to
> play with the iterator protocol without using "for", but it may be harder
> to read.  You could put break at the end of the loop above to make it more
> apparent that it only runs once.
>
> On Mon, Jan 27, 2020 at 6:58 AM S D  wrote:
>
>> I have a dictionary which contains one item (“current_location”, which is
>> a nested dict) and I would like to access that nested dict. However, I
>> cannot use the key as the code will break if a different key is passed,
>> e.g. “different_location”.
>>
>> How can I access the first item in a dictionary without using a key? The
>> dict looks like this:
>>
>> `
>> {'current_location': {'date': '2020-01-27T10:28:24.148Z', 'type_icon':
>> 'partly-cloudy-day', 'description': 'Mostly Cloudy', 'temperature': 68.28,
>> 'wind': {'speed': 10.48, 'bearing': 178, 'gust': 12.47}, 'rain_prob': 0.02,
>> 'latitude': '-33.927407', 'longitude': '18.415747', 'request_id': 31364,
>> 'request_location': 'Current location'}}
>> `
>>
>> Kind regards,
>> - SD
>>
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>> "Django users" group.
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>> email to django-users+unsubscr...@googlegroups.com.
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>> <https://groups.google.com/d/msgid/django-users/CAH-SnCBnnOsoTURnSzCrqqXsCWF5EEjghm9Q1UTQKrnTBAJ3iA%40mail.gmail.com?utm_medium=email&utm_source=footer>
>> .
>>
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