Re: Login & Register
Use django-allauth package. On 26 Feb 2022, at 15:09, Ankit Chaurasia wrote: Hey, I am new in Djnaog and I want to make Login and Register Page with Email Verification. Can anone share the code ? and please gide me for the same. -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/C8B0DB95-4812-421B-9355-5FB3E9CC6DDB%40indx.co.uk.
Re: How to create dynamic models in django??
On 27 Feb 2022, at 17:54, Steve Smith wrote: ...the documentation on Formsets is scarce in my opinion and to get them to work is a lot of trial and error... To massively simplify formsets try django-extra-views -- Clive -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/5F1D5ACB-C5D8-460A-B471-D4B537A010F6%40indx.co.uk.
Re: How to create dynamic models in django??
On 28 Feb 2022, at 16:24, Prashanth Patelc wrote: Any example? Just read the django-extra-views documentation. Essentially a formset can be as simple to use as any of the built-in class-based views, eg: from extra_views import InlineFormSetView class EditContactAddresses(InlineFormSetView): model = Contact inline_model = Address template_name = … https://django-extra-views.readthedocs.io/en/latest/pages/formset- views.html#inlineformsetview -- Clive -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/ACAAA816-D3DF-4732-9A45-8DFABABA0DEA%40indx.co.uk.
Re: Reusable django templates
On 12 Mar 2022, at 17:43, Heman Okumbo wrote:
How comes I'm not able to modify my templates after extending from
a base template.eg can't add extra contents,the template only
display contents of the inherited template.
Some code might help. It's not really clear to me what you are asking.
But at a guess, you can use the {% include … %} template function to
extend templates.
-- Clive
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Re: OperationalError at /admin/login database or disk is full
On 27 May 2022, at 22:37, Andrew Rea wrote: OperationalError at /admin/login/ database or disk is full Is this because my SQLite database is full from other projects? Or possibly because I have too many virtual envs from those same other projects? Or is it due to my personal computer's disk being too full? I wouldn't bet on it, but I suspect that you do not have the correct permissions to write to the database. Because your HD really isn't full, is it? -- Clive -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/CE3C33E3-7796-4ED5-92E5-190DDEBDE91E%40indx.co.uk.
Re: dynamic formular
Try django-extra-views https://github.com/AndrewIngram/django-extra-views Hugely simplifies formsets On 10 Nov 2022, at 11:14, Arnold Falanga wrote: Hello can anyone help me to design a dynamic form with Django the idea is to have two parts in this form. a link to add the lines -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/ d/msgid/django-users/f9c74264-7cc0-448d-bcee-9110f7a91292n% 40googlegroups.com. -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/1F81F7CA-604F-4EF1-A707-B790B8A3B09B%40indx.co.uk.
Re: Single Sign On in Django
You can use django-allauth: https://github.com/pennersr/django-allauth On 10 Nov 2022, at 09:59, venkat Bukka wrote: Hello all, Could anyone please let me know how we can implement SSO in the django...for authenticating multiple apps in a base application. -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/ d/msgid/django-users/cc932efa-f41d-458d-901c-844e32bb1b5dn% 40googlegroups.com. -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/47C61FB0-FE30-4119-B4BD-934B366691F5%40indx.co.uk.
Re: Quiz app
Questions.objects.all().order_by('?')[:5]
ie get all the rows from the Questions table, in a random order, then
show me the first five.
https://docs.djangoproject.com/en/dev/topics/db/queries/#limiting-
querysets
-- Clive
On 16 Nov 2022, at 01:14, Lakshyaraj Dash wrote:
Hello everyone,
I'm on my way to create a quiz app. I want that a loggedin user
should get 5 questions randomly when he/she is visiting everytime.
Eg:
On first visit
Q1. Who's the CEO of Facebook ?
On second visit
Q2. Who's the CEO of Google ?
Thanks and regards
Lakshyaraj Dash
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Re: Need to Replace django default I'd with UUID field
It's more or less the same problem, use a new field to insert your new foreign keys (UUIDs), looking them up via your old foreign keys to get the new UUID values. Or, as the other Jason suggests, if you can, just use the UUIDs for external access. -- Clive On 22 Nov 2022, at 19:02, Rajesh Kumar wrote: Hi Jason, Thanks for a quick reply. I got your point, but I am worry about my existing data/records which is already associated with id , which is default one. On Wed, 23 Nov, 2022, 12:29 am Jason Turner, wrote: I would just add another column that holds the UUID value instead of changing the default ID. On Tue, Nov 22, 2022, 12:55 PM Rajesh Kumar wrote: Hi everyone! Hope everyone is doing well... Actually I have 100+ existing data in my database with default I'd field of django Now I need to replace that default I'd to UUID. How I can do this without loosing any records of my database. If anyone can give me suggestions that would be great. Thanks Rajesh Kumar -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/ d/msgid/django-users/CAKNDe%3D%3DEa0ZagzpZ-Y_bXKrCi3ZHdG_PNr5% 3DgxeJCTbKdM_tdA%40mail.gmail.com. -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/ d/msgid/django-users/CADoyC17Ar%2B5aHx2GHCdqTuHJagbJx6% 3DFzj9zHP19-4-E1j6Pew%40mail.gmail.com. -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/ d/msgid/django-users/CAKNDe%3Dks0Gc%2BR8Hs6u%3DmhtQv3PjwyxaRqF2% 3D7pwyP1NF34t5bQ%40mail.gmail.com. -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/0DC12C1C-84CA-4102-8B05-8BA2329D3ED0%40indx.co.uk.
Re: join on plain integerfield
Try Django Relativity: https://pypi.org/project/django-relativity/ -- Clive On 21 Nov 2022, at 10:11, Marek Rouchal wrote: Any suggestion how I can model such an integerfield, so that I can do joins on it using the Django ORM queryset syntax? -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/847DD166-E3C3-42D1-A10A-CDF0F19B7D75%40indx.co.uk.
Re: How to access the value of a field that failed validation
If you print:
dir(form_instance)
You'll get the methods available to the form. From memory, amongst
these you will find "data" and "initial", I think that "data"
contains the information submitted in the form action. So, to show that:
print(form.data)
-- Clive
On 2 Jan 2023, at 00:12, Noel Duffy wrote:
I'm new to Django, though not to programming. I'm using Django
4.1.4 on AlmaLinux 9.
My question is this. Is it possible to access a ModelForm field's
value if that form field failed validation?
I'm writing a small ticketing system for a helpdesk to handle spam
reports. Users submit spam messages which the system will then
process. I'm using a ModelForm, and the database schema specifies
that the spam message is unique. That is, each spam message can be
reported only once, so there's just one ticket but possibly many
different actions taken depending on what's in the spam.
This is the model:
class AbuseReport(models.Model):
report_date = models.DateTimeField(auto_now_add=True)
report_subject = models.CharField(max_length=255)
report_msgid = models.CharField(max_length=255, unique = True)
report_spam_text = models.TextField(unique = True)
def __str__(self):
return report_subject
class Meta:
ordering = ['-report_date']
Now, the problem is that a spam message will fail form validation
in the form.is_valid call if the spam message fails the "unique"
constraint. Why is this a problem? Because I want to get my hands
on the spam message if it's already in the DB so that instead of
just re-showing my form with an error message saying the spam
already exists, I want to redirect to the existing ticket. But so
far I've not been able to figure out how to do this, and when I
dump the contents of the form in debugging, the spam message just
isn't there.
I should add that the ModelForm only creates a field for the
report_spam_text field. I.e,
class AbuseReportForm(ModelForm):
def __init__(self, *args, **kwargs):
super(ModelForm, self).__init__(*args, **kwargs)
def clean(self):
[...]
class Meta:
model = AbuseReport
fields = ['report_spam_text']
widgets = {'report_spam_text':
Textarea(attrs={
'rows': 20,
'class':'textarea',
'placeholder':'Paste spam with full headers
here..'
}),}
This is what my view looks like (stripped down for simplicity):
def spamsubmit(request):
# if this is a POST request we need to process the form data
if request.method == 'POST':
# create a form instance and populate it with data from the
request:
form = AbuseReportForm(request.POST)
# check whether it's valid:
if form.is_valid():
# process the data in form.cleaned_data as required
[.]
else:
## show the form again with errors displayed
## if spam already exists this is what gets run.
return render(request, 'abuse/spam_form.html',
{'form':form})
As I understand it, fields aren't bound to data until is_valid is
called, and if is_valid fails then only fields that didn't fail
validity go into cleaned_data. But it seems everything else is
lost. But I'm not 100% sure about this and this is why I'm asking.
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Re: How to fetch 10000 above record within second in django?
On 17 Jan 2023, at 05:01, Prashanth Patelc wrote: I written query it's taking more time like 38 seconds, how to to fetch the lac of records within seconds any example in django using orm or MySQL query ? Are you saying that you have a raw SQL query, or you are using a Django query? My experience is that the biggest lag in database retrieval is the amount of data retrieved, so if you can reduce the number of fields returned, that would be a good start. If you are using a Django query, and it has related elements, then the biggest boost you can give is using "select_related" and "prefetch_related". -- Clive -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/9EF46118-6870-46AD-BF58-12AEC8C6A518%40indx.co.uk.
Re: How to fetch 10000 above record within second in django?
The easiest way to debug this is to install django_debug_toolbar and look at the sql queries to see where the hold-up is. As previously, restrict the number of fields returned using "values" and/or use "select_related" or "prefetch_related" to get related data in one or two queries, rather than having Django getting that data on (potentially) multiple queries per record. -- Clive On 17 Jan 2023, at 07:43, Prashanth Patelc wrote: I'm using orm query fetching all data and showing into html templates , it's taking more time for get the data , On Tue, Jan 17, 2023, 12:40 PM Clive Bruton wrote: On 17 Jan 2023, at 05:01, Prashanth Patelc wrote: > I written query it's taking more time like 38 seconds, how to to > fetch the lac of records within seconds any example in django using > orm or MySQL query ? Are you saying that you have a raw SQL query, or you are using a Django query? My experience is that the biggest lag in database retrieval is the amount of data retrieved, so if you can reduce the number of fields returned, that would be a good start. If you are using a Django query, and it has related elements, then the biggest boost you can give is using "select_related" and "prefetch_related". -- Clive -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/ d/msgid/django-users/9EF46118-6870-46AD-BF58-12AEC8C6A518% 40indx.co.uk. -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/ d/msgid/django-users/CAMCU6CrAKQL6qA6hWHPDFbfpCT1R9v5%2BY_Qi-HOkPf% 3DOXYt2yA%40mail.gmail.com. -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/52330EF7-BBD9-44E6-94E3-C0A733F4EF36%40indx.co.uk.
Re: How to fetch 10000 above record within second in django?
On 17 Jan 2023, at 12:06, Ayanfeoluwa Koyinsola wrote: You might now have to display all the data at once, see if you can use paginisation to reduce the numbers of queries I think this will only help if there are related lookups. -- Clive -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/3ADD9645-859E-4452-9460-0917C367669B%40indx.co.uk.
Re: WHAT OTHER REAL TIME MAP CAN I USE IN MY PROJECT ASIDE GOOGLE MAP?
Here maps: https://www.here.com https://heremaps.github.io/ -- Clive -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/1F083D04-1CC7-4C84-AB45-BD82AD1521AF%40indx.co.uk.
Re: CSS with Django forms
On 12 May 2020, at 22:41, Anubhav Madhav wrote:
Is there any way to display the forms with my HTML CSS files.
Use {% include %} (https://docs.djangoproject.com/en/3.0/ref/
templates/builtins/#include) in your HTML template files for an
embedded style sheet, or just use a link in the head of your template
to serve the .css from the "static" folder (or other remote server
location).
-- Clive
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Viewing available functions and variables
I am using django-allauth for a user registration/log-in system. I
have this working, however, as a general question, I would like to
understand how one can view the functions/variables available on a
given template.
For example I see that in some templates these are included:
{% user_display confirmation.email_address.user as user_display %}
{{ emailaddress.email }}
But I cannot, for example, access these in templates used for sending
email.
Hope that is clear.
-- Clive
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Re: CSS with Django forms
You can use bootsrap4, or look at the output from the forms and set
up your CSS around that.
-- Clive
On 14 May 2020, at 19:40, Anubhav Madhav wrote:
Thankyou Clive!! I know I can use CSS like that, but if I do that
the problem I'll face is that the 'form' or the 'input' tags or
'submit' button, which are rendered using django forms, cannot be
modified using CSS in this way. Is there any other way to fix it?
On Wednesday, 13 May 2020 18:58:08 UTC+5:30, Clive Bruton wrote:
On 12 May 2020, at 22:41, Anubhav Madhav wrote:
> Is there any way to display the forms with my HTML CSS files.
Use {% include %} (https://docs.djangoproject.com/en/3.0/ref/
templates/builtins/#include) in your HTML template files for an
embedded style sheet, or just use a link in the head of your template
to serve the .css from the "static" folder (or other remote server
location).
-- Clive
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Re: Bootstrap drop down menu not clickable.
On 16 May 2020, at 15:03, sunday honesty wrote: I did that and got a TemplateSyntaxError stating that bootstrap4 is not a registered tag library Did you put it in your installed_apps? -- Clive -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/AF951EBC-2228-4CB5-92CA-F7207A31DE0B%40indx.co.uk.
Re: Bootstrap drop down menu not clickable.
On 16 May 2020, at 15:43, sunday honesty wrote: I included it to installed app and got an error message on the console. "Module not found, no module named bootstrap 4" "bootstrap4" -- Clive -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/7552335C-16B0-4114-B1F3-5A3F8C1CD02A%40indx.co.uk.
Re: Categories and shoe Subcategories according to the parent category.
There are django modules for hierarchical navigation https://djangopackages.org/grids/g/navigation/ -- Clive On 19 May 2020, at 23:20, saqlain abbas wrote: Please tell me if anyone knows about this. On Mon, May 18, 2020 at 4:50 PM saqlain abbas wrote: Hi, if i add Categories , for example 1)accessories 2)sports 3)books Subcategories: accessories is the parent category child categories are watches jewlry caps how can i show if user selects the parent category accessories then the subcategories show according to parent categories like subcategories are watches jewlry etc -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/ d/msgid/django-users/1530c511-072f-44ee-83fa-3555bd090a89% 40googlegroups.com. -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/ d/msgid/django-users/CAP6Ddn3zr%2BsfaL6DGMHb- xsLpE1zKcToKjKEqoPU6PCgGqjh1w%40mail.gmail.com. -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/3E93BF89-D7B4-4715-A666-30EAE076418B%40indx.co.uk.
Date comparison as a filter
I would like to add a date comparison filter to a lookup, to find items in a database table that have not yet expired. I tried: .filter(expires>=datetime.today()) \ But this does not appear to have any effect. "expires" is a column in the table of datetime type, that looks like this: "2020-07-08 01:17:27.952874" Or do I have to format "datetime.today()" to match the format displayed in the database table? Thanks -- Clive -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/D59D05A5-02D8-42BD-A410-3ECDE22A9974%40indx.co.uk.
Re: Python 3.8 Installed, yet Django 1.11 is Automatically Being Installed on Mac
You have to use the correct python install: python3 -m pip install django You can test your versions and locations: which python3 which python python3 -V python -V When you are running the development server: python3 manage.py runserver You can have multiple python versions installed, you just need to understand which one you are addressing/using. -- Clive On 9 Jun 2020, at 03:37, arhoon io wrote: Hello, I have installed and successfully confirmed that Python 3.8 works on my Mac. However, when I pip installed the latest version of Django, it automatically installed Django 1.11 even though I have Python 3.8. When typing in "python" into terminal, it runs Python 2.7 - so that is my guess. If that is true, how do I get the actual latest version of Django (3.0)? Thanks -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/ d/msgid/django-users/d02c23bd-0c04-47c1-8602-63c74e35e144o% 40googlegroups.com. -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/842AFD7C-4F75-4F68-84AC-B86E4C98ED0F%40indx.co.uk.
Compare logged-in user against record owner in filter
I am trying to create a queryset that filters against the logged-in user's id and the user_id in the record, ie so that only the relevant user can see the record. Without the filter, when I display the page I can capture elements in the template that would allow this comparison, ie: object.user.id # the record owner user.id # the logged-in user's id object.user # the record owner's user name user # the logged-in user’s user name So, in models.py I made a new query manager: class EditManager(models.Manager): def get_queryset(self): return super(EditManager, self).get_queryset().filter( user.id==object.user.id, expires__gte=datetime.now(timezone.utc), is_active=True) Then the debug gives the following error: Exception Value:name 'user' is not defined Even if I try fields that are obviously in the table, just to get a nonsensical filter, I get similar errors, eg "id==user_id". I have tried variations on the user id comparison, but have not got any further. Or, am I going about this completely the wrong way? Any help greatly appreciated. -- Clive -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/3F70FF33-445A-4EB4-A582-6C20268B0355%40indx.co.uk.
Updating a date field
I am trying to update an existing date field, however when I do that I get the following exception: Exception Type: TypeError Exception Value: expected string or bytes-like object The query looks like this: queryset = Item.edit.filter(**kwargs).update (expires=set_expires,is_active=True) and set_expires looks like this: def set_expires(): return datetime.now(timezone.utc) + timedelta(days=30) I am using "set_expires" in the model for "Item", to set the initial value, without issue. Do I have to convert to a string when doing an update? Thanks -- Clive -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/8B6B6771-0E9C-4E4A-A696-18CF9B7ED355%40indx.co.uk.
Re: Updating a date field
Apparently the magic is: queryset = Item.edit.filter(**kwargs).update(expires=set_expires (),is_active=True) -- Clive On 14 Jun 2020, at 03:24, Clive Bruton wrote: I am trying to update an existing date field, however when I do that I get the following exception: Exception Type: TypeError Exception Value: expected string or bytes-like object The query looks like this: queryset = Item.edit.filter(**kwargs).update (expires=set_expires,is_active=True) and set_expires looks like this: def set_expires(): return datetime.now(timezone.utc) + timedelta(days=30) I am using "set_expires" in the model for "Item", to set the initial value, without issue. Do I have to convert to a string when doing an update? Thanks -- Clive -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/ d/msgid/django-users/8B6B6771-0E9C-4E4A-A696-18CF9B7ED355% 40indx.co.uk. -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/29D80E69-FDDF-4736-9AA0-2E4DBB9C972E%40indx.co.uk.
Re: Custom Primary Key
On 23 Jun 2020, at 23:32, Oleg Kishenkov wrote: Hello Soumen, you should use a CharField with the primary_key=True attribute for your model. This way no no automatic primary key field is generated, your field will be implicitly unique and non- null though. Only one primary key is allowed in a model. class Foo(models.Model) id = models.CharField(max_length=15, primary_key=True) Just to clarify this, are you indicating that when you create the record you generate a unique custom key yourself and insert this? -- Clive -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/E9317D0D-0A25-48CE-9396-5FB181075045%40indx.co.uk.
Form theory - locking a field
I have a form in which, after filing, I would like one field to be
locked for editing, the forms.py looks like this:
**
class ProfileForm(forms.ModelForm):
status = forms.ChoiceField(choices=Profile.status_choices,
widget=forms.RadioSelect)
class Meta:
model = Profile
fields = (
'status', 'phone', 'display_phone', 'display_address',
'display_email', 'display_loginoverride'
)
widgets = {
'phone': PhoneWidget
}
**
While the user will be able to come back and change the other
information on the form, I want to be able to lock the "status"
field, so that it just shows the input they selected, not the radio
buttons and is no longer editable by the user.
Is there a way to do this in forms.py, or would I have to construct
the logic in a template (or perhaps some other way)?
Thanks
-- Clive
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Re: Custom Primary Key
On 24 Jun 2020, at 06:24, Soumen Khatua wrote: Yes, at the time of add a new record in model, automatically I want to create a custom ID and insert it into model There is a post about this at Stack Overflow: https://stackoverflow.com/questions/52070462/django-generate-custom-id -- Clive -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/7722F772-8C9D-4E4C-8B86-45AEF488036A%40indx.co.uk.
Re: Form theory - locking a field
On 24 Jun 2020, at 23:03, Chetan Ganji wrote:
Try this one
https://docs.djangoproject.com/en/3.0/ref/forms/fields/#disabled
Ok, well that's a little help, because I can disable the input:
status = forms.ChoiceField(choices=Profile.status_choices,
widget=forms.RadioSelect(attrs={'disabled': True}))
And I can put a "useless" if statement around it to get different
outputs:
if 1 == 1 :
status = forms.ChoiceField(choices=Profile.status_choices,
widget=forms.RadioSelect(attrs={'disabled': True}))
else :
status = forms.ChoiceField(choices=Profile.status_choices,
widget=forms.RadioSelect(attrs={}))
But, I can't work out how to get a meaningful if comparison, like:
if Profile.status == 'personal' :
status = forms.ChoiceField(choices=Profile.status_choices,
widget=forms.RadioSelect(attrs={'disabled': True}))
else :
status = forms.ChoiceField(choices=Profile.status_choices,
widget=forms.RadioSelect(attrs={}))
Any string I put in 'personal' always returns false, so I can switch
the output with "==" or "!=", but I can't assess the output in
reference to what I expect to be in the database fields. Django
accepts "Profile.status" as a relevant property, so I am a bit lost
as to how to continue, or debug this. If I try "print(locals()) or
print(Profile.status) I get no output in the terminal.
-- Clive
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Re: CSS file not Loading
If you are testing the site with manage.py runserver, then you have
to make sure debug is on. And you have to ensure the app knows where
the static directories are.
-- Clive
On 28 Jun 2020, at 12:21, Suny wrote:
Do I need to add STATICFILES_DIRS in settings.py file
TREE STRUCTURE for reference :
.
├── db.sqlite3
├── Fotografie
│ ├── asgi.py
│ ├── __init__.py
│ ├── __pycache__
│ │ ├── __init__.cpython-38.pyc
│ │ ├── settings.cpython-38.pyc
│ │ ├── urls.cpython-38.pyc
│ │ └── wsgi.cpython-38.pyc
│ ├── settings.py
│ ├── urls.py
│ └── wsgi.py
├── Home
│ ├── admin.py
│ ├── apps.py
│ ├── __init__.py
│ ├── migrations
│ │ ├── 0001_initial.py
│ │ ├── __init__.py
│ │ └── __pycache__
│ │ ├── 0001_initial.cpython-38.pyc
│ │ └── __init__.cpython-38.pyc
│ ├── models.py
│ ├── __pycache__
│ │ ├── admin.cpython-38.pyc
│ │ ├── apps.cpython-38.pyc
│ │ ├── __init__.cpython-38.pyc
│ │ ├── models.cpython-38.pyc
│ │ ├── urls.cpython-38.pyc
│ │ └── views.cpython-38.pyc
│ ├── static
│ │ └── Home
│ │ └── main.css
│ ├── templates
│ │ └── Home
│ │ ├── about.html
│ │ ├── base.html
│ │ ├── contact.html
│ │ └── home.html
│ ├── tests.py
│ ├── urls.py
│ └── views.py
├── manage.py
└── Users
├── admin.py
├── apps.py
├── __init__.py
├── migrations
│ ├── __init__.py
│ └── __pycache__
│ └── __init__.cpython-38.pyc
├── models.py
├── __pycache__
│ ├── admin.cpython-38.pyc
│ ├── apps.cpython-38.pyc
│ ├── __init__.cpython-38.pyc
│ ├── models.cpython-38.pyc
│ ├── urls.cpython-38.pyc
│ └── views.cpython-38.pyc
├── templates
│ └── Users
│ └── register.html
├── tests.py
├── urls.py
└── views.py
base.html file
{% load static %}
https://maxcdn.bootstrapcdn.com/
bootstrap/4.0.0/css/bootstrap.min.css" integrity="sha384-
Gn5384xqQ1aoWXA+058RXPxPg6fy4IWvTNh0E263XmFcJlSAwiGgFAW/dAiS6JXm"
crossorigin="anonymous">
https://fonts.googleapis.com/css?
family=Sofia">
https://fonts.googleapis.com/css?
family=Annie Use Your Telescope">
rel='stylesheet'>
Fotografie
css file with main.css name
body {
background-color: #181818; /*background of page*/
color: #FF; /*color of text*/
margin-top: 1000rem;/*margin from top*/
}
h1, h2, h3, h4, h5, h6 {
color: #FF;
text-transform: uppercase;
}
ul {
margin: 0;
}
setting.py file
"""
Django settings for Fotografie project.
Generated by 'django-admin startproject' using Django 3.0.7.
For more information on this file, see
https://docs.djangoproject.com/en/3.0/topics/settings/
For the full list of settings and their values, see
https://docs.djangoproject.com/en/3.0/ref/settings/
"""
import os
# Build paths inside the project like this: os.path.join
(BASE_DIR, ...)
BASE_DIR = os.path.dirname(os.path.dirname(os.path.abspath(__file__)))
# Quick-start development settings - unsuitable for production
# See https://docs.djangoproject.com/en/3.0/howto/deployment/
checklist/
# SECURITY WARNING: keep the secret key used in production secret!
SECRET_KEY = ')!e)l*b%z(ywdugroidcrjq4a%&dt7ha2*^amf8s150ndy%+@i'
# SECURITY WARNING: don't run with debug turned on in production!
DEBUG = True
ALLOWED_HOSTS = []
# Application definition
INSTALLED_APPS = [ #list collector
'Home.apps.HomeConfig',
'Users.apps.UsersConfig',
'django.contrib.admin',
'django.contrib.auth',
'django.contrib.contenttypes',
'django.contrib.sessions',
'django.contrib.messages',
'django.contrib.staticfiles',
]
MIDDLEWARE = [
'django.middleware.security.SecurityMiddleware',
'django.contrib.sessions.middleware.SessionMiddleware',
'django.middleware.common.CommonMiddleware',
'django.middleware.csrf.CsrfViewMiddleware',
'django.contrib.auth.middleware.AuthenticationMiddleware',
'django.contrib.messages.middleware.MessageMiddleware',
'django.middleware.clickjacking.XFrameOptionsMiddleware',
]
ROOT_URLCONF = 'Fotografie.urls'
TEMPLATES = [
{
'BACKEND': 'django.template.backends.django.DjangoTemplates',
'DIRS': [],
'APP_DIRS': True,
'OPTIONS': {
'context_processors': [
'django.template.context_processors.debug',
'django.template.context_processors.request',
'django.contrib.auth.context_processors.auth',
'django.contrib.messages.context_processors.messages',
],
},
},
]
WSGI_APPLICATION = 'Fotografie.wsgi.application'
# Database
# https://docs.djangoproject.com/en/3.0/ref/settings/#databases
DATABASES = {
'default': {
'ENGINE': 'django.db.backends.sqlite3',
'NAME': os.path.join(BASE_DIR, 'db.sqlite3'),
}
}
# Password validation
Re: Primary keys using sequences
On 2 Jul 2020, at 00:06, Stats Student wrote: Hi, I am using a Postgres database and have been populating the primary key from a sequence. Is there any way to define this behavior through Django's ORM? Thanks I think you are basically asking how to create a custom key. This was discussed a few days ago, look for the thread "Custom Primary Key". -- Clive -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/762F7935-2DA1-4334-B706-48675E8E5D2A%40indx.co.uk.
Trouble getting kwargs into filter
I am struggling with getting kwarg values into a queryset filter:
class UsersItemsView(ListView):
template_name = 'testapp/user_item_list.html'
def get_queryset(self, **kwargs):
print('kwargs-userlist')
print(kwargs)
#return Item.objects.filter(user__username='clive')
#return Item.objects.filter(user__id=2)
return Item.objects.filter(user__id=kwargs['userlist'])
def dispatch(self, *args, **kwargs):
print('kwargs-userlist')
print(kwargs['userlist'])
return super(UsersItemsView, self).dispatch(*args, **kwargs)
On dispatch, I can see the value for "kwargs['userlist']" printed in
the terminal.
But, the queryset returns an error:
Exception Type: KeyError
Exception Value: 'userlist'
I understand this to mean that the key 'userlist' is not in kwargs,
and this is confirmed if I "print(kwargs)" inside the get_queryset
If I use the hard-coded filters, commented-out above
("user__username='clive'", "user__id=2"), I get the result (from the
template) that I expect.
So, how do I get the "kwargs['userlist']" passed to the queryset?
Thanks
-- Clive
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Re: Trouble getting kwargs into filter
Thank you. On 6 Jul 2020, at 05:24, Stephen J. Butler wrote: def get_queryset(self): qs = super().get_queryset() return qs.filter(user__id=self.kwargs['userlist']) -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/06B8D1F3-83B7-4EB0-A44A-0916DF93321A%40indx.co.uk.
Adding an 'or' to filter
I am working into someone else's solution, with this code in forms.py:
***
class SearchForm(forms.Form):
area = forms.ModelChoiceField(label=_('Area'),
queryset=Area.objects.all(), required=False)
group = forms.ModelChoiceField(label=_('Group'),
queryset=Group.objects.all(), required=False)
q = forms.CharField(required=False, label=_('Query'),)
def filter_by(self):
# TODO search using more than one field
# TODO split query string and make seaprate search by words
filters = {}
if self.cleaned_data['group']:
filters['group'] = self.cleaned_data['group']
if self.cleaned_data['area']:
filters['area'] = self.cleaned_data['area']
filters['description__icontains'] = self.cleaned_data['q']
return filters
***
I understand that 'filters' is a dictionary.
However, what I would like to do is have the final input ('q') be an
'or' search on two fields, ie:
filter(Q(description__icontains = self.cleaned_data['q']) | Q
(title__icontains = self.cleaned_data['q'])]
Not sure how to implement that in this dictionary style.
Thanks
-- Clive
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Re: transforming form input
On 7 Jul 2020, at 22:58, Kai Kobschätzki wrote: I render one input field surname. And if the user writes one string in the input field it should be saved to surname (so forename is None). If the user writes two strings (separated through a white space) than the first part should be saved to forename and the second one to surname (and perhaps I want to make some string manipulation further). This isn't a "safe" way of delineating forename/surname. It isn't that uncommon for people to have unhyphenated compound surnames, eg: Bruce Smith Jones To see the confusion this may cause: https://en.wikipedia.org/wiki/Arthur_Conan_Doyle It is better to ask for the forename input separately, or at least give the user the option to override your decision. -- Clive -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/E644135A-7C74-4689-B3CB-6AA03224AC84%40indx.co.uk.
Django conditional field display on form
I am trying to make a simple form, that conditionally shows the
"website" input field based on the value of another database field
(that is not on the form) "status". For the sake of this process the
"status" field is not editable by the user, just by the admin. Both
fields are in the same table: "profile".
After working at this for a while I copped-out and just did the
conditional hiding and showing on the template. But, I realise this
is the unsophisticated method, and would like to improve it.
What I tried so far in forms.py:
class WebsiteForm(forms.ModelForm):
class Meta:
model = Profile
fields = ( 'e-mail', 'website', )
if Profile.status == 'personal' :
exclude = ('website',)
This method in forms.py works effectively, in that I can
conditionally show and hide the field if I use test comparitors in
the if statement like:
if 1 == 1:
or
if 1 != 1:
But, I cannot get an effective test using the field "Profile.status",
the value in the field seems to be unavailable at the point the "if"
test in forms.py is performed.
If I use "print(Profile.status)" I get the following output in the
terminal: "user__profile__status__isnull", so I think this means that
I am at least testing the correct field in the database. Although I
am also noting that this output only shows at initialisation of
"runserver", not when the form page is accessed.
One final point, the user is authenticated and editing their own record.
Any help very much appreciated.
-- Clive
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Re: Dynamic Logo
On 18 Oct 2020, at 12:53, Asaduzzaman Sohel wrote: I am creating a django application. now I would like to create logo, site name & info which will be dynamic. I want to create Model for this , but problem is use create many logo, site name or info. but Use can create or edit only one logo, one site name. How can I do this? There are probably endless ways to create dynamic/changing content and design/logos, you need to be a bit more specific about what you want to achieve. The easiest way to create a changing site name is to put words in a table and randomly choose one or more. -- Clive -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/C1213021-216E-470A-9A33-544465E298B6%40indx.co.uk.
Get datetime now, not at server initialisation
I have a function that uses the current date to set up a file path
for uploaded images:
def upload_path():
dtnow = datetime.now(timezone.utc)
dtstr = '{:%Y/%m/%d/%H/%M/%S}'.format(dtnow)
print('dtstr: ')
print(dtstr)
dtstr = 'images/items/' + dtstr
return dtstr
class Image(models.Model):
item = models.ForeignKey(Item, on_delete=models.CASCADE)
#file = ImageField(_('image'), upload_to='images')
file = ImageField(_('image'), upload_to=upload_path())
The problem is that when the Image class calls 'upload_path' the
datetime portion of this is always the runserver initialisation time,
rather than the time when 'upload_path' is called/used.
How to fix this?
Thanks
-- Clive
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Re: Get datetime now, not at server initialisation
Thanks, that was very helpful. I had another pointer on this and
found out that the easiest way to do this is just to change the
```file``` line in the class to:
```
file = ImageField(_('image'), upload_to='images/items/%Y/%m/%d/%
H/%M/%S')
There are a few things that I do not understand, however, after
playing around with some code for a while.
If I just pass a string to ```file``` it understands that this is a
partial path, and it has to stick ```filename``` on the end. eg:
```file = ImageField(_('image'), upload_to='images/items')```
Likewise with the version above with the date formatting.
This is also the case when I used my initial ```upload_path```
function, calling it with ```upload_to=upload_path()``` – but this
did not suit the task, because ```upload_path``` loaded at
initialisation of the server.
So, given that ```upload_path``` returns a string, I don't understand
why I also have to concatenate the ```filename```:
```
def upload_path(instance, filename):
dtnow = datetime.now(timezone.utc)
dtstr = '{:%Y/%m/%d}'.format(dtnow)
dtstr = 'images/items/' + dtstr + '/' + filename
return dtstr
```
In this case, if I do not concatenate ```filename``` then the
uploaded file gets named with the last element of the date formatting
and without a file extension, ie potentially like this:
```images/items/2020/10/28/20/59/55```
rather than:
```images/items/2020/10/28/20/59/55/image.jpg```
The other thing I don't understand is how ```instance``` and
```filename``` are passed to the function ```upload_path```. I would
expect to do something like:
``` file = ImageField(_('image'), upload_to=upload_path(instance,
filename))```
But if I do that I get:
```NameError: name 'instance' is not defined```
Sorry for so many more questions!
-- Clive
On 28 Oct 2020, at 08:58, Carles Pina i Estany wrote:
Hi,
On Oct/27/2020, Clive Bruton wrote:
I have a function that uses the current date to set up a file path
for
uploaded images:
def upload_path():
[...]
class Image(models.Model):
item = models.ForeignKey(Item, on_delete=models.CASCADE)
#file = ImageField(_('image'), upload_to='images')
file = ImageField(_('image'), upload_to=upload_path())
The problem is that when the Image class calls 'upload_path' the
datetime portion of this is always the runserver initialisation time,
rather than the time when 'upload_path' is called/used.
How to fix this?
For what I remeber (I use FileField usually but this is noto
relevant I
hope) you should do:
def upload_path(instance, filename):
# you have access to the instance (object model Image in your
case)
# and the filename that the user used to upload it
# and this is executed on the upload time
return your_new_file_name
In the model:
file = ImageField(_('image'), upload_to=upload_path)
note that upload_path is a callable: it gets called on the upload
time.
In your code it was called on initialization time.
Some time ago I had a similar code that caused a bug: in a ListView
the
"queryset = " is executed on startup time. For a dynamic one I should
have used get_queryset() method.
--
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https://carles.pina.cat
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Re: Get datetime now, not at server initialisation
On 30 Oct 2020, at 11:00, Carles Pina i Estany wrote: Let me know if it's not clear or if I explained something that you didn't ask! Thanks you very much for spending the time on this, to explain it to me - it was very helpful! -- Clive -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/BBE7C073-E0A4-4927-8A7B-DA13861D40B4%40indx.co.uk.
Re: getting 404 page not found on part 3 of the tutorial
On 11 Nov 2020, at 23:37, George P. Olson wrote:
So when I go to this url: http://127.0.0.1:8000/polls/
Although the urlpatterns below shows "# ex: /polls/", the defined
path has no path elements, so you just need:
http://127.0.0.1:8000/
I think.
urlpatterns = [
# ex: /polls/
path('', views.index, name='index'),...
-- Clive
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Re: getting 404 page not found on part 3 of the tutorial
Sorry, I just checked my version of the tutorial, you load the
manage.py through the directory "mysite", and "polls" is in a sub-
directory. The way you showed the "/polls/urls.py" implied that was
the only file, where in fact the root app/settings are at "/mysite/
settings.py" and urls at "/mysite/urls.py".
Because "/mysite/urls.py" has an include for "polls/urls.py" it
implies the path "/polls".
It's a bit tricky to diagnose, because you are now saying it was
working, but then you changed stuff. My directory setup looks like this:
/mysite/manage.py
...
/mysite/mysite/settings.py
...
/mysite/mysite/urls.py
...
/mysite/polls/settings.py
...
/mysite/polls/urls.py
I checked my polls.py, which looks like this:
*
from django.urls import path
from . import views
app_name = 'polls'
"""
urlpatterns = [
# ex: /polls/
path('', views.index, name='index'),
# ex: /polls/5/
path('/', views.detail, name='detail'),
# ex: /polls/5/results/
path('/results/', views.results, name='results'),
# ex: /polls/5/vote/
path('/vote/', views.vote, name='vote'),
]
"""
urlpatterns = [
path('', views.IndexView.as_view(), name='index'),
path('/', views.DetailView.as_view(), name='detail'),
path('/results/', views.ResultsView.as_view(),
name='results'),
path('/vote/', views.vote, name='vote'),
]
***
I think I read recently that generic views like "IndexView" need a
".as_view()" attached to the end to be recognised.
-- Clive
On 12 Nov 2020, at 04:35, George Olson wrote:
I don't quite follow your note there of just going to:
http://127.0.0.1:8000/
without the app name 'polls' following.
I believe you have to put the app name following that. It was
working before with http://127.0.0.1:8000/polls/, but then I did
something and tried to backtrack and the whole system got messed
up. I tried to reset everything back to the original but it is
still not working.
On Wednesday, November 11, 2020 at 7:47:58 PM UTC-6 Clive Bruton
wrote:
On 11 Nov 2020, at 23:37, George P. Olson wrote:
> So when I go to this url: http://127.0.0.1:8000/polls/
Although the urlpatterns below shows "# ex: /polls/", the defined
path has no path elements, so you just need:
http://127.0.0.1:8000/
I think.
> urlpatterns = [
> # ex: /polls/
> path('', views.index, name='index'),...
-- Clive
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How to avoid select lists on formsets and ManyToMany?
I have a ManyToMany model set, that on the edit uses a formset to add/ edit rows. I have this working, but the unfortunate part of it is that the select that results from the ManyToMany relationship populates with 16,000 records. What I would like to do is, once the records are added, just have the delete checkbox and show the 'description' field (uneditable) next to it), and, rather than add records through a huge select list, add the records by id. To sketch it out, this is how it is: <'Profile.directory-optin' checkbox> <'Profile.directory-desc'> <'Class.description' huge select> <'Class.description' huge select> <'Class.description' huge select> <'Class.description' huge select> And I'd rather it was something like: <'Profile.directory-optin' checkbox> <'Profile.directory-desc'> The database tables look something like: Profile Join table Class === == = id id id directory-optin profile-id description directory-desc class-id Hope someone can help me out! -- Clive -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/E30F44E6-07DA-4703-BAB1-BE295C72EF22%40indx.co.uk.
Re:
Find a project on github and suggest some easy fixes. I'm no django expert, but I've had patches accepted on at least three projects. The last one I contributed to was updating the code from django 1.x to 3.x, so that it would run on more recent versions. This is quite easy to do, since the debug will give you the errors, and then you can just search for the solutions. -- Clive On 2 Apr 2021, at 11:10, Richard Dushime wrote: dear developers i am requesting for help i am new and i wanted to start contributing on a project but i have failed on how to start i have seen one project ideas but i am not seeing a mentor contacts please i need a help thank you -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/ d/msgid/django-users/CAJCm56Kf9mxV7jxErjFBspBaQKBDPoUPGQkWRjSmO3h% 2Btmdw0w%40mail.gmail.com. -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/2C87261E-2A29-471D-A347-213D8E4918F1%40indx.co.uk.
Re: bonjour tout le monde Je suis confronte a cette erreur depuis 2 jours....besoins d'aide svp
Sorry I can't reply in French. It simply means that a template is expected in your project/app folder at: [project/app]/templates/registration/logout.html -- Clive On 26 Nov 2023, at 11:55, fabrice ayissi awono wrote: -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/ d/msgid/django-users/916d7cbc-40b2-4cf8-83bb-7ed054a350ffn% 40googlegroups.com. -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/B07D5682-FEC1-4E44-BF8D-6B31BCA98185%40indx.co.uk.
Re: Custom User models
I am taking it that there is more than one "school"? If so, surely it's is just a many-to-many relationship. On 27 Nov 2023, at 09:33, Okkert Joubert wrote: Good morning all, I made a custom user model for a school, it is currently working with djoser authentication, now what I want to add is for the school to add users, so my School model is a foreignkey in SchoolUser is this possible firstly and secondly can I add the djoser authentication to the SchoolUser model as well -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/ d/msgid/django-users/2754d7b3-a54a-40d6-9cab-50c0a2dbb812n% 40googlegroups.com. -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/650A06A2-C854-4361-9BF3-5CCDF636F2D0%40indx.co.uk.
Re: Registration form in template
If you want to override what the form is showing, then you can build
your own template and only include the elements that you wish to show.
Rather than use:
{{ form }}
use:
{{ form.field_name }}
or break it down further, like:
{{ form.field_name.html_name }}
etc
Consequently, depending on how much you wish to omit, you may need
code the HTML tags and attributes.
On 18 Mar 2024, at 04:13, 'Simon Connah' via Django users wrote:
I have a register user template with a form which works well but I
have a problem where there is lots of other text next to the form
elements such as password length and what characters need to go in
a password. Is their a reasonable way to hide that text or do I
need to do it with JavaScript?
Thank you.
Simon.
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