I am struggling with getting kwarg values into a queryset filter:
class UsersItemsView(ListView):
template_name = 'testapp/user_item_list.html'
def get_queryset(self, **kwargs):
print('kwargs-userlist')
print(kwargs)
#return Item.objects.filter(user__username='clive')
#return Item.objects.filter(user__id=2)
return Item.objects.filter(user__id=kwargs['userlist'])
def dispatch(self, *args, **kwargs):
print('kwargs-userlist')
print(kwargs['userlist'])
return super(UsersItemsView, self).dispatch(*args, **kwargs)
On dispatch, I can see the value for "kwargs['userlist']" printed in
the terminal.
But, the queryset returns an error:
Exception Type: KeyError
Exception Value: 'userlist'
I understand this to mean that the key 'userlist' is not in kwargs,
and this is confirmed if I "print(kwargs)" inside the get_queryset
If I use the hard-coded filters, commented-out above
("user__username='clive'", "user__id=2"), I get the result (from the
template) that I expect.
So, how do I get the "kwargs['userlist']" passed to the queryset?
Thanks
-- Clive
--
You received this message because you are subscribed to the Google Groups "Django
users" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to django-users+unsubscr...@googlegroups.com.
To view this discussion on the web visit
https://groups.google.com/d/msgid/django-users/5BD32BE1-331F-4AE5-BB8A-2E769D728972%40indx.co.uk.