Django 4.0 released

[Mariusz Felisiak]

Details are available on the Django project weblog:

https://www.djangoproject.com/weblog/2021/dec/07/django-40-released/

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Re: How to update part of a JSONField with a computed value?

[Bazil M H]

Use the inbuilt *json* library in python. Use json.dumps and json.loads
to convert the dictionary to json and vice versa.
On Thursday, 5 August 2021 at 04:17:38 UTC+5:30 shahee...@gmail.com wrote:

> Hi,
>
> I'm using Django 3.2 on Postgres12, and I have a model with a JSONField 
> which contains a simple dict (actually, a Django formset :-)). I would like 
> to update just one value in the dict. I can get this to work when the new 
> value is a hardcoded numeric 333 (quoted, as seems to be needed) like this:
>
> pay_items.update(inputs=JSONBSet('inputs', ['inputs-0-value'], 
> Value("333"), True))
>
> where JSONBSet is a Func, as indicated below. However, I'd like to 
> actually compute the value. I've tried a variety of things, without 
> success. Here is one attempt:
>
> pay_items.update(inputs=JSONBSet('inputs', ['inputs-0-value'],
>  Cast(F('inputs__inputs-0-value'), 
> FloatField()) + Value("3"),
>  True))
>
>
> This fails like this:
>
> ERROR:  function jsonb_set(jsonb, unknown, double precision, boolean) does 
> not exist at character 42 
> HINT:  No function matches the given name and argument types. You might 
> need to add explicit type casts. 
> STATEMENT:  UPDATE "paiyroll_payitem" SET "inputs" = 
> JSONB_SET("paiyroll_payitem"."inputs", '{inputs-0-value}', 
> (CAST(("paiyroll_payitem"."inputs" -> 'inputs-0-value') AS double 
> precision) + '3'), true) WHERE "paiyroll_payitem"."id" IN (...))
>
> I've tried all sorts of variants with Cast, ExpressionWrapper and so on to 
> no avail, so I'd be grateful for any shove in the right direction!
>
> Thanks, Shaheed
>
> Encls: implementation of JSONBSet derived from 
> https://code.djangoproject.com/ticket/32519 and related threads:
>
> class JSONBSet(Func):
> function = 'JSONB_SET'
> arity = 4
> output_field = CharField()
>
> def __init__(self, field, path, value, create: bool = True):
> path = Value('{{{0}}}'.format(','.join(path)))
> create = Value(create)
> super().__init__(field, path, value, create)
>
>

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Re: Mouse movement detection and processing from client UI

[Bazil M H]

Mouse clicks are client side actions. You need javascript to get that data. 
One solution maybe capturing the mouse clicks at the client side via 
javascript and sending the data as JSON to your backend by AJAX. Just a 
suggestion. 

On Thursday, 28 October 2021 at 11:24:39 UTC+5:30 Derek wrote:

> I am not sure about the others, but certainly for map clicks you'll need 
> JavaScript  e.g.
> https://docs.mapbox.com/mapbox-gl-js/example/popup-on-click/
> Of course, the page itself, with JS code links, snippets and supporting 
> data can be generated via Django in the normal way.
>
> HTH
>
>
> On Wednesday, 27 October 2021 at 04:03:16 UTC+2 lego.th...@gmail.com 
> wrote:
>
>> So there are Python packages out there that can handle mouse movement 
>> detection locally. But for a Django app, how do we go about do this? 
>> Clearly we cannot have any processing power on the client machine. Below 
>> are some examples to be more specific:
>> 1 - An e-commerce page where buyer clicks, drags (i.e. holds the mouse) 
>> and drops a picture of an item from shelf to cart.
>> 2 - A web game where player clicks, drags and drops things from one 
>> location on the screen to another.
>> 3 - Web page responds to location of mouse on screen (i.e. coordinates) 
>> such as GPS-related apps with real map.
>>
>> Thanks,
>>
>

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Re: Display api in particular format

[Bazil M H]

Can you make the image an attachment ? Cant see anything on your image.

On Saturday, 27 November 2021 at 23:00:41 UTC+5:30 Sapna Agrahari wrote:

> Can anyone please help me with this? As I want to display the api data in 
> this format.
> [image: image.png]
> 
> Thanks and Regards ,
> *Sapna Agrahari*
>

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Re: class based view Type error

[Bazil M H]

Have you changed the urls.py file accordingly?

On Thursday, 18 November 2021 at 09:02:55 UTC+5:30 Trippy Samurai wrote:

> Hello,
> I have my function based writted like this 
>
>
> @login_required
> def accept_tickets_view(request,pk):
> ticket = get_object_or_404(Ticket,id=pk)
> if ticket.status == 'Opened':
> ticket.status = 'Accepted'
> ticket.accepted_date = datetime.datetime.now()
> ticket.accepted_by = request.user
> ticket.save()
> return redirect(reverse('open_tickets'))
>
>
>
> And i changed the above to cbv but getting the following error how do i 
> solve this
>
> class DeveloperAcceptTicketView(LoginRequiredMixin,TemplateView):
> template_name = 'app/open_tickets.html'
> def get(self,request,pk):
> ticket = Ticket.objects.get(id=self.pk)
> if ticket.status == 'Opened':
> ticket.status = 'Accepted'
> ticket.accepted_by = self.request.user
> ticket.save()
> return render(request,self.template_name)
> [image: Screenshot 2021-11-18 at 9.01.12 AM.png]
>
>
>
>
>

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Re: Can't able to accept the friend request in my django website

[Bazil M H]

Please format your question correctly so that someone can understand that. 
Then only people can answer your question.

On Friday, 3 December 2021 at 05:57:22 UTC+5:30 Kasper Laudrup wrote:

> https://www.propublica.org/nerds/how-to-ask-programming-questions
>

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Re: Django 4.0 released

[Gerardo Palazuelos Guerrero]

Thank you!

—
Gerardo Palazuelos
Enviado desde mi iPhone

> El 7 dic 2021, a la(s) 2:28, Mariusz Felisiak  
> escribió:
> 
> 
> Details are available on the Django project weblog:
> 
> https://www.djangoproject.com/weblog/2021/dec/07/django-40-released/
> 
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Re: Django 4.0 released

[Noel Simela]

Great stuff,

On Tue, Dec 7, 2021 at 11:28 AM Mariusz Felisiak 
wrote:

> Details are available on the Django project weblog:
>
> https://www.djangoproject.com/weblog/2021/dec/07/django-40-released/
>
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> 
> .
>


-- 
*Noel Nqabeni Simela*
Web: https://nqabeni.wordpress.com

*"The Best thing in Life, is Life!"*

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Re: Django 4.0 released

[kayhan]

Okay, thank you. I really like open source technologies

On Tue, Dec 7, 2021 at 8:00 PM Noel Simela  wrote:

> Great stuff,
>
> On Tue, Dec 7, 2021 at 11:28 AM Mariusz Felisiak <
> felisiak.mari...@gmail.com> wrote:
>
>> Details are available on the Django project weblog:
>>
>> https://www.djangoproject.com/weblog/2021/dec/07/django-40-released/
>>
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>> To view this discussion on the web visit
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>> 
>> .
>>
>
>
> --
> *Noel Nqabeni Simela*
> Web: https://nqabeni.wordpress.com
>
> *"The Best thing in Life, is Life!"*
>
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> 
> .
>

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Re: Django security releases issued: 3.2.10, 3.1.14, and 2.2.25

[kayhan]

Okay, thank you. I really like open source technologies

On Tue, Dec 7, 2021 at 11:12 AM Mariusz Felisiak 
wrote:

> Details are available on the Django project weblog:
>
> https://www.djangoproject.com/weblog/2021/dec/07/security-releases/
>
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> 
> .
>

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Why does sqlmigrate need a connection to an existing database?

[Shmuel Treiger]

Wondering why sqlmigrate needs a connection to an existing database.

I understand that for certain commands, it needs the database to generate 
the migration. But for most (basic) commands, no connection is really 
needed.

For example, I created a test project 
and
 
generated migration files. Without ever running the `migrate` command, I 
was able to use `sqlmigrate` perfectly well on all migrations, save the 
last, which drops a `unique_together`.

I'm sure there are other commands which actually need a database connection 
(though I haven't found them yet). Seems to me sqlmigrate could be 
rewritten along the lines of:

   - Try to generate sql from migration file
   - If it hits a command it needs the database, attempt to connect

Or else:

   - If no connection, check if migration file needs connection to database
   
Is there something I'm unaware of?

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