In the expression (5^x)^2-7*5^x+4, I want to substitute x^5 by t.
With sagemath 7.2 (or another old versions), I can do
((5^x)^2-7*5^x+4).subs(5^x==t)
and I get t^2 - 5*t + 4
But sagemath 9.4 does not change the first 5^x and he gives
5^(2*x) - 7*t + 4
Why?
(In both cases, var("t") has been previously used)
Yours,
Juan Luis Varona
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