p=534601 is known
Defining coefficients is redundant , it is to be omitted.
On 12/9/17, slelievre <samuel.lelie...@gmail.com> wrote:
> ----- Original message (slightly reformatted) ----
> I want to find the value of h0, h1, h2, h3, h4 such that
>
> (x - a1)*(x - a2)*(x - a3)*(h0 + h1*x^1 + h2*x^2 + h3*x^3 + h4*x^4 +
> x^5)
>
> is equal to
>
> (x + b)*g2 + (a*x + d)
>
> for some a, b, d, in GF(p).
>
> Below is my code which is unable to solve it
>
> a, b, d, a1, a2, a3, h0, h1, h2, h3, h4 = var('a b d a1 a2 a3 h0 h1 h2
> h3 h4')
> RHS = (x - a1)*(x - a2)*(x - a3)*(h0 + h1*x^1 + h2*x^2 + h3*x^3 +
> h4*x^4 + x^5)
> g2 = x^7 + 74604*x^6 + 351974*x^5 + 18952*x^4 + 148817*x^3 + 256076*x^2
>
> + 168356*x + 278165
> LHS = (x + b)*g2 + (a*x + d)
> Coeff = RHS.coefficients(x, sparse=False)
> print(solve(RHS == LHS, h0, h1, h2, h3, h4))
>
> -----
>
> - What is the value of p that you want to work with?
> Or is p also an unknown?
>
> - Why do you define "Coeff"? You don't seem to use it.
>
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--
Madhurima Mukopadhyay
Senior Research Fellow
Applied Statistics Unit
ISI, Kolkata
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