Is it always a coin toss whether a computer algebra system can solve a log equation? Should I not expect to make a career out of using Sage to solve nonlinear equations?
cs On Sunday, July 16, 2017 at 3:41:42 PM UTC-5, Emmanuel Charpentier wrote: > > Wups... My bad : I wasn't really awake, it seems... > > Anyway, as suggested by Dominique, you can do : > > sage: E=log(y) == C + log(x) + log(y-1);E > log(y) == C + log(x) + log(y - 1) > sage: S=E.solve(x)[0].solve(y);S > [y == x*e^C/(x*e^C - 1)] > sage: bool(E.subs(S).expand_log()) > True > > which checks. > > Again, sorry for the noise... > > -- > Emmanuel Charpentier > > > Le dimanche 16 juillet 2017 18:29:46 UTC+2, Chris Seberino a écrit : >> >> Emmanuel >> >> Thank you for your reply but you solved a DIFFERENT equation. Notice >> mine has an x variable in it. >> I can get your's to work but not mine. >> >> cs >> > -- You received this message because you are subscribed to the Google Groups "sage-support" group. To unsubscribe from this group and stop receiving emails from it, send an email to sage-support+unsubscr...@googlegroups.com. To post to this group, send email to sage-support@googlegroups.com. Visit this group at https://groups.google.com/group/sage-support. For more options, visit https://groups.google.com/d/optout.
