Wups... My bad : I wasn't really awake, it seems... Anyway, as suggested by Dominique, you can do :
sage: E=log(y) == C + log(x) + log(y-1);E log(y) == C + log(x) + log(y - 1) sage: S=E.solve(x)[0].solve(y);S [y == x*e^C/(x*e^C - 1)] sage: bool(E.subs(S).expand_log()) True which checks. Again, sorry for the noise... -- Emmanuel Charpentier Le dimanche 16 juillet 2017 18:29:46 UTC+2, Chris Seberino a écrit : > > Emmanuel > > Thank you for your reply but you solved a DIFFERENT equation. Notice mine > has an x variable in it. > I can get your's to work but not mine. > > cs > -- You received this message because you are subscribed to the Google Groups "sage-support" group. To unsubscribe from this group and stop receiving emails from it, send an email to sage-support+unsubscr...@googlegroups.com. To post to this group, send email to sage-support@googlegroups.com. Visit this group at https://groups.google.com/group/sage-support. For more options, visit https://groups.google.com/d/optout.
