Size of my matrix is (90, 36) with entries are around 2^1000. What is the
fastest
method  to compute Hermite Normal Form?
In my matrix number of rows greater than number of columns. That is
A=  random_matrix(ZZ, 90, 36). Then how can I calculate  transformation
matrix
of LLL?




On 28 December 2010 22:32, luisfe <lftab...@yahoo.es> wrote:

> On Dec 28, 5:27 pm, Santanu Sarkar <sarkar.santanu....@gmail.com>
> wrote:
> > Is there any faster method to compute Hermite Normal Form
> >   of a matrix  A and corresponding transformation matrix? I use
> > A.hermite_form(transformation=true). However it is very slow.
> >
> > Also is there any transformation matrix corresponding to the LLL
> algorithm.
>
> What are the size/shape of your problem? If you just want the
> hermite_form you can use A.hermite_form(algorithm = ...), where the
> algorithms available can be checked in A.echelon_form.
>
> If you need transformation = true. Then the method will always be a
> padic one, that is asymptotically fast, but may be slow for small
> matrices.
>
> Concerning the question of LLL. I may be wrong, but I think that there
> is not right now a  built-in method to obtain the transformation
> matrix. You could solve the linear system of equations
>
> sage: A = random_matrix(ZZ, 25, 50)
> sage: B = A.LLL()
> sage: trans_matrix = A \ B
> sage: A * trans_matrix == B
> True
>
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