PS: I know that testing "is None" is faster than "len(L)>1" and wouldn't insist that there *has* to be an identity operator. One has to consider two different cases anyway.
However, if there *is* an operator, s==s.operator()(*s.operands()) should hold. Cheers, Simon -- To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to sage-support+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-support URL: http://www.sagemath.org
