Hello, I just want to test, if I can do with my students in computer
lab what they usualy do on the paper
1. find general solution
2. substitute from initail conditions
3. find c
4. use this c in general solution
I agree that this may be strange to do this in the case, we have a
command for solving IVP.
I just wanted to know, if it is possible to substitute some value for y
(x), if y(x) is declared as a function.
Thanks. Robert
On 28 Dub, 16:45, David Joyner <wdjoy...@gmail.com> wrote:
> I don't know if you are asking about how to use ICs in
> desolve or if you are asking about how to do substitutions.
> Anyway, I get this:
>
> sage: y=function('y',x)
> sage: desolve(diff(y,x)+sin(x)*y^6==0,y)
> 1/(5*y(x)^5) == c - cos(x)
> sage: desolve(diff(y,x)+sin(x)*y^6==0,y,[pi,9])
> 1/(5*y(x)^5) == (-295245*cos(x) - 295244)/295245
>
> Does that help?
>
> On Tue, Apr 28, 2009 at 10:36 AM, ma...@mendelu.cz <ma...@mendelu.cz> wrote:
>
> > Dear memebers of SAGE-support
>
> > I wonder if it is possible to substitute initial conditions into an
> > equation produced by desolve. I tried something like
>
> > y=function('y',x)
> > desolve(diff(y,x)+sin(x)*y^6==0,y)
> > sol({x:pi,y:9})
>
> > and got
>
> > 1/(5*y(pi)^5) == c + 1
>
> > but I would like to see
>
> > 1/(5*9^5) == c + 1
>
> > many thanks
>
> > Robert
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