I don't know if you are asking about how to use ICs in
desolve or if you are asking about how to do substitutions.
Anyway, I get this:
sage: y=function('y',x)
sage: desolve(diff(y,x)+sin(x)*y^6==0,y)
1/(5*y(x)^5) == c - cos(x)
sage: desolve(diff(y,x)+sin(x)*y^6==0,y,[pi,9])
1/(5*y(x)^5) == (-295245*cos(x) - 295244)/295245
Does that help?
On Tue, Apr 28, 2009 at 10:36 AM, ma...@mendelu.cz <ma...@mendelu.cz> wrote:
>
> Dear memebers of SAGE-support
>
> I wonder if it is possible to substitute initial conditions into an
> equation produced by desolve. I tried something like
>
> y=function('y',x)
> desolve(diff(y,x)+sin(x)*y^6==0,y)
> sol({x:pi,y:9})
>
> and got
>
> 1/(5*y(pi)^5) == c + 1
>
>
> but I would like to see
>
>
> 1/(5*9^5) == c + 1
>
> many thanks
>
> Robert
>
>
> >
>
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