Let me rewrite what I wrote in last post again, since it did not format well.
I think it does converge. int( exp(-I 2 Pi f t),{t,0,infinity) = infinity 1/(-I 2 Pi f) * [ exp(-I 2 Pi f t) } 0 Let f be complex in general, say (a+ I b) then the above becomes infinity 1/(-I 2 Pi f) * [ exp(-I 2 Pi (a +I b) t) } 0 or infinity 1/(-I 2 Pi f) * [ exp(-I 2 Pi a t) exp (2 Pi b t) } 0 Since b<0 (this is the assumption that Im(f)<0 ), then the above becomes 1/(-I 2 Pi f) * [ 0 - 1 } or 1/(I 2 Pi f) or -I/(2 Pi f) Nasser --~--~---------~--~----~------------~-------~--~----~ To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/sage-support URLs: http://www.sagemath.org -~----------~----~----~----~------~----~------~--~---